I JUST WANTED TO NOTE THAT OPTION C IS 100% WRONG AND YOU CAN ONLY CHOOSE ONE OF THE OTHER 4 OPTIONS (WHILE NOTING THAT IT IS B-DNA).
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I JUST WANTED TO NOTE THAT OPTION C IS 100% WRONG AND YOU CAN ONLY CHOOSE ONE OF THE OTHER 4 OPTIONS (WHILE NOTING THAT IT IS B-DNA).
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- Below is an image of a basepair and associated ribose rings as viewed down the helical axis in B DNA (black spheres are oxygen atoms; red lines are hydrogen bonds). G1 B1 G2 G4 Identify the base marked as B1. Identify the base marked as B2. B2 adenine thymine G3 Identify the general location (G1-G4) of the minor groove. G4 Identify the general location (G1-G4) of the major groove. G2 >Below is a nucleotide base pair from B-DNA with three different regions indicated by A, B, and C. C B Which of the following descriptions of regions A, B, and Care INCORRECT? B-minor groove, water spine, sugar edge A minor groove, sugar edge A major groove, Watson-Crick-Franklin edge AThe line below depicts a DNA segment from a eukaryote. In this case, only the top, coding strand, is shown which is ok for our purposes (but remember that the other strand would also be present in DNAà but it is ok for us to ignore). This is very similar to a problem on the old tests. For each letter state the structure or the function of what occurs at that region. Letter A is Letter B is Letter C is Letter D is Letter E is Letter F is Letter G is To which region/letter would RNA Polymerase bind To which region/letter GTF bind Label the position of the start codon ATG and the stop codon TGA The picture below is for the question itself
- Table I CACGT A GA CTGAGG ACTC CACGTAGACTGAG G ACAC Wild-type beta-globin gene fragment Sickle-cell beta-globin gene fragment > Circle the mutation in DNA of the sickle-cell beta-globin gene fragment Compare fragments of DNA the wild-type and mutant beta-globin genes in the Table I above, what are the similarities and differences you observe?Given the DNA template strand 3' GCATTCAAG 5', write the amino acid sequence in the N‑terminal to C‑terminal direction. Note: Enter the amino acids using their three-letter designations. Put a hyphen between each amino acid.The following fragment of DNA is from the template strand. First determine the amino acids of the protein encoded by this sequence by using the table at the end of this document. Then give the altered amino acid sequence of the proteins that will be found in each of the following mutations: 3’ – TAC AAG GCT CTA TTT GCC ACA ATC – 5’ The nucleotides are numbered 1-24 from left to right. Mutant 1: A transition at nucleotide 9 Mutant 2: A transition at nucleotide 11 Mutant 3: A T to A transversion at nucleotide 15 Mutant 4: A one-nucleotide deletion at nucleotide 7 Mutant 5: A transition at nucleotide 13 Mutant 6: An addition of GGA after nucleotide 6
- The chromatogram shows fluorescent peak data from a dye-terminating nucleotide-sequencing reaction. The peaks are shown with shortest fragment on the left to longer fragments on the right. T •C A Select the DNA sequence that matches the data. 5-ТАТAСТТАСGAAGT-3' 5'-GTCCTACGGACGCG–3' 5'-ATATGAATGCTTCA–3' 5'-TGAAGCATTCATAT–3' 5-АСТТCGTAAGTATA-3'A lagging strand is sketched below. The Okazaki fragment DNA is red, and the RNA primers aredashed orange lines. Which Okazaki fragment was made first? When ligase joins fragments Aand B, will it act at arrow 1, arrow 2, or both?The DNA STRAND IS 3’ TAC-AGC-ACT-CAG-TCA 5’, and Non-template strand = 5' - ATGTCGTGAGTCAGT - 3' . If on the non-coding strand of DNA there is suddenly one T base that sneaks into the 4th sequence (from the left), or causes a mutation, then how will the RNA be formed and the chain arrangement of the amino acids produced by this mutation?
- The DNA STRAND IS 3’ TAC-AGC-ACT-CAG-TCA 5’ and Non-template strand = 5' - ATG-TCG-TGA-GTC-AGT - 3' . If on the non-coding strand of DNA there is suddenly one T base that sneaks into the 4th sequence (from the left), or causes a mutation, then how will the RNA be formed and the chain arrangement of the amino acids produced by this mutation? 4th sequence (from the left) should be = TCG right?A DNA strand was sequenced using the Sanger method (https://www.youtube.com/watch?v=KTstRrDTmWI). The reaction tube contained the DNA strand, fluorescently labelled dideoxynucleotide triphosphates (ddATP – yellow, ddGTP – green, ddCTP – blue, ddTTP - red), deoxynucleotide triphosphates, DNA polymerase, or its Klenow fragment. Synthesis of DNA is allowed to proceed, and the results are shown on the right: 15 14 13 12 11 10 (a) What is the sequence of the copy and the template strands? (b) If the template strand were in the 5'-3' direction, what will be the sequence of the DNA copy? Nucleotide LengthHere is a DNA coding strand’s sequence and direction: 5’-ATGCCGATATAG-3’ . What would be the amino acid sequence in the polypeptide encoded by this DNA?
