In the Rutherford model of the hydrogen atom, a proton (mass M, charge Q) is the nucleus and an electron (mass m, charge q) movesaround the proton in a circle of radius r. Let k denote the Coulomb force constant (1/4TTE0) and G the universal gravitational constant.The ratio of the electrostatic force to the gravitational force between electron and proton is:O kMm/GQqO kQq/GMmO GQq/kMmO GMm/kQqO kQq/GMmr²

Mass of proton = M Mass of electron = m Charge on proton = QCharge on electron = q The radius of the…

Answered: In the Rutherford model of the hydrogen…

Glencoe Physics: Principles and Problems, Student Edition

1st Edition

ISBN:9780078807213

Author:Paul W. Zitzewitz

Publisher:Paul W. Zitzewitz

Chapter7: Gravitation

Section: Chapter Questions

Problem 71A

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In the simple Bohr model of the ground state of the hydrogen atom, the electron travels in a circular orbit around a fixed proton. The radius of the orbit is 5.281011m , and the speed of the electron is 2.18106m/s . The mass of an electron is 9.111031kg . What is the force on the electron?
The gravitational force between two masses m and m2 located a distance r apart has a magnitude of FG =Gmm2, where G = 6.674×10 N ⋅ m2/kg2; this has a nearly identical form to the Coulomb force law between two charges (except the force constants are different and masses are always positive). Suppose two identical spherical masses with radius a = 30 μm and mass density ρm = 2.2 × 103 kg/m3 are located a distance L apart. If they are released rest, their gravitational attraction will cause them to eventually collide. If, however, each mass has the same charge, then a Coulomb force will oppose the gravitation force. Suppose each mass has an excess of n extra electrons that causes both to be negatively charged. Find the minimum number n that would prevent the masses from colliding.
In a hydrogen atom an electron is orbiting a proton. There are two forces between the electron and the proton. The Gravitational Force FG and the electrostatic Force FE. What is the factor FE / FG of those two forces. Use the following constants to calculate the problem: me=9.1*10-31 kg mp=1.67*10-27 kg e=1.6*10-19 C k=8.99*109 Nm2/C2 r=1.11*10-10 m ?=6.67⋅10−11??2??2G=6.67⋅10−11Nm2kg2 Please give your answer FE/FG in FE/FG*1040 ie. for 6.734*1042 please write 673.4
and F represents gravitational and electrostatic force respectively between electrons situated at a distance 10 cm. The ratio of F/F is of the order of e (a) 1042 (c) 1024 (b) 10-²1 F g (d) 10-43 KAL
If the gravitational force of two identical particles is equal to the electrostatic force between the proton (p) and the electron (e), what is the mass m of the particles? The magnitude of the charge of the electron and proton is e = 4.8x10-10 esu (CGS), G-6.7x10 CGS, the distance between the [p, e] pair is equal to the distance between the [m, m] pair.
A proton is placed 86.5nm from a helium nucleus. The gravitational force pulls the proton and neutron together, while the electric force pushes them apart. How big is the gravitational force?
If the gravitational force of two identical particles is equal to the elec- trostatic force between proton (p) and electron (e), what is the mass m, of the particles. The magnitude of charge of electron and proton is e=4.8x1010 esu (CGS), G=6.7×10 CGS, the distance between the [p, e] pair is equal to the distance between the [m, m] pair.
Consider a charge of size +3.8 x 10-4 C and mass 8 kg is traveling to the left towards a +1.7 x 10-4 C charge with speed 119 m/s. The +1.7 x 10-4 C charge is so massive that it does not recoil in response to the repulsion of the approaching charge. Calculate how close the two charges get, in m. Use k = 9 x 109 N m2 / kg2. (Please answer to the fourth decimal place - i.e 14.3225)
electrons Two protons (p) and two (e) are arranged on a circle of 5 [cm], with angles 0₁ = 20°, 0₂ = 60°, 03 = 20° and 04 = 60°, as radius r shown in the figure. (qp = +1.6 x 10-1⁹ [C] and qe = -1.6 × 10-19 [C]). The figure is not to scale. 04 y a. Find Enet, the net electric field vector produced at the center of the circle. Enet =([ ])i + ( ]) Ĵ [N/C] b. Where on the circle should a fifth point charge qo be placed (give its angle relative the +x-axis) and what is its value (calculate qo) in order to have Ēnet (the net electric field at the center of the circle) equals zero (Type the detailed solution to this question in the below box, Show all your calculation steps by typing in the box). Р X
A uranium ion and an iron ion are separated by a distance of R = 57.10 nm, as shown in the figure. The uranium atom is uranium ion iron ion electron singly ionized; the iron atom is doubly ionized. K r K- R Calculate the distance r from the uranium atom at which an electron will be in equilibrium. Ignore the gravitational r = nm attraction between the particles. What is the magnitude Fy of the force on the electron from the uranium ion? N Question Source: Freedman College Physics 3e | Publisher: Macmillan
Consider the electrostatic force between two particles of equal mass m = 42.7 × 10-26 kg and carrying different charges q1 = 18e and q2 = 29e, where e denotes the magnitude of the charge on an electron. At what distance, in meters, is the electrostatic force between these two particles equal to the weight of one of them?
Two spheres of equal diameter have a positive 20 µC and a negative 15 µC, respectively. If they are placed 10 cm apart, what would be the force of attraction between them? is at first raised? Given:? Find:? Solution:?

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