Use the following constants to calculate the problem: me=9.1*10-31 kg mp=1.67*10-27 kg e=1.6*10-19 C k=8.99*109 Nm2/C2 r=1.11*10-10 m ?=6.67⋅10−11??2??2G=6.67⋅10−11Nm2kg2 Please give your answer FE/FG in FE/FG*1040
Use the following constants to calculate the problem: me=9.1*10-31 kg mp=1.67*10-27 kg e=1.6*10-19 C k=8.99*109 Nm2/C2 r=1.11*10-10 m ?=6.67⋅10−11??2??2G=6.67⋅10−11Nm2kg2 Please give your answer FE/FG in FE/FG*1040
Physics for Scientists and Engineers, Technology Update (No access codes included)
9th Edition
ISBN:9781305116399
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter23: Electric Fields
Section: Chapter Questions
Problem 23.2OQ
Related questions
Question
In a hydrogen atom an electron is orbiting a proton. There are two forces between the electron and the proton. The Gravitational Force FG and the electrostatic Force FE. What is the factor
FE / FG
of those two forces.
Use the following constants to calculate the problem:
me=9.1*10-31 kg
mp=1.67*10-27 kg
e=1.6*10-19 C
k=8.99*109 Nm2/C2
r=1.11*10-10 m
?=6.67⋅10−11??2??2G=6.67⋅10−11Nm2kg2
Please give your answer FE/FG in FE/FG*1040
ie. for 6.734*1042 please write 673.4
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