Knowing that the Curly leaf (Cy) is a dominant gene on chromosome 6, as it is useful in tracking other genes using trisomics for chromosome 6. Assume a Cy Cy cy plant used as a pollen parent where disomic pollen does not function crossed to a Cy cy cy female where disomic eggs do function. A) What ratio would be predicted in the progeny of this cross? B) What if the reciprocal cross was made?
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Knowing that the Curly leaf (Cy) is a dominant gene on chromosome 6, as it is useful in tracking other genes using trisomics for chromosome 6. Assume a Cy Cy cy plant used as a pollen parent where disomic pollen does not function crossed to a Cy cy cy female where disomic eggs do function.
A) What ratio would be predicted in the progeny of this cross?
B) What if the reciprocal cross was made?
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- Familial Down syndrome is similar to primary Down syndrome in that it is caused by trisomy 21. However, in familial Down syndrome, all or part of the third copy of chromosome 21 has translocated onto another autosome, typically chromosome 14. In cases of familial Down syndrome, one of the parents of the affected child is often a carrier of a translocated chromosome. The translocation carrier parent does not have Down syndrome because he or she has a total of two copies of chromosome 21. Suppose that a woman is a translocation carrier of chromosome 21 on chromosome 14. She conceives six zygotes with a normal man who carries no aneuploidies. Match the description of the chromosomes inherited by each zygote with the viability of the zygote. Viable normal, or translocation carrier Viable, with Down syndrome Inviable Answer Bank two normal copies of 21, one normal copy of 14 two normal copies of 21, two normal copies of 14 one 21 to 14 translocation, one normal copy of 21, two normal copies…Deletion mapping: In your diploid model organism, one copy of the chromosome has all normal, dominant alleles of these genes. It is P Q R STU V (not necessarily in that order). But the other copy of the chromosome has all recessive alleles, p q r stu v. You find various deletions in which chunks of the "dominant chromosome" are missing, and so there are recessive phenotypes as shown: Phenotype -- recessive for genes... T, Q, and U R, V, and S T and U S and V Q, P, and R R and S First deletion Second deletion Third deletion Fourth deletion Fifth deletion Sixth deletion Seventh deletion T and Q Figure out the order of the genes. Show some kind of work.Topic: Penetrance. Petal number is controlled by a single gene in merigonias. The gene has a completely dominant wild type allele F that makes a plant have five petals and a mutant recessive six petal allele(f). However the six petal trait is only 50% penetrant. You do the cross Ff x Ff. What fraction of the progeny do you have the 6 petals? what is the meaning for 50% penetrant.
- Make a key for this problem. Use these symbols to show the cross for the P generation, the Chapter 14: Mendel and the Gene Idea 10. Figure 14.5 in your text explains how to construct a Punnett square for a cros bet true-breeding plants with purple or white flowers. You are going to reproduce this Goeen use symbols instead of pictures. offspring in the Fi generation, and both the cross and the offspring in the F2 generati, the dicate the alleles for each individual as well as the gametes it produces and complete Punnett square. Key: P Generation F, Generation F2 Generation Genetics problems have their own vocabulary, and you will have difficulties in solving them unless you master the following terms. Define the terms and give an example of each using the following symbols: 11. P = purple flowers p = white flowers homozygous heterozygous genotype phenotype parental cross monohybrid cross dihybrid cross -4- Copyright © 2021 Pearson Education, Inc.Neep help ASAP. A red flowered plant was crossed with a blue flowered plant and produced all purple flowered plants. When the purple flowered plants were crossed with each other they produced 5 red plants, 5 blue plants, 20 deep purple plants, 20 light lilac plants, and 30 purple plants How many genes are involved in the color production? Assume that red color is caused by an A allele and blue color by a B allele and determine the likely genotype of the plants in the F2 generation.otypes. Inference: Revision: Parent 2 rryy Gametes ry Parent 1 RY RrYy RRYY The F, generation are all RrYy. ROund seeds 1. What is the phenotype of parent 1?. 2. What is the genotype of parent 1? 3. What is the phenotype of parent 2? 4. What is the genotype of parent 2? 5. What is the phenotype of the F, offspring? 6. What is the genotype of the F, offspring?. 7. What kind of cross does this figure describe? 1 Chapter 12 Introduction to Genetics Copyright Pearson Education, Inc., or its affiliates. All rights re Gametes
- . Jimsom. weed plants can produce purple or white flowers and spiny or smooth seed pods. A purple spiny plant is crossed with a white spiny plant. This cross produces: 89 purple spiny; 92 white spiny; 31 purple smooth and 27 white smooth plants. What are the genotypes of the parental plants and the progeny plants? Use the letters P/p for flower color and S/s for pod texture Parent #1 –genotype:_________________________________; Parent #2 –genotype: ______________________________ b. Offspring plants – genotypes and phenotypes c. Calculate the recombination frequency using these results_________________________________ i need help finding the right answer and i need an explation on how you got it so i understand and please do it with a punnet square and show the calutions step by stepTUSOIES. TITCSC CIITOTIOSOTIES are iavCicu WILT UICTEIevarIC alleles. For example: to Figure 1. Showing a homologous pair of chromosomes that carry two linked genes. Here we can see that one chromosome carries A and B alleles, while the other homologous chromosome carries a and b alleles. This is much more informative than just giving the genotype of AaBb. Another way to symbolize the arrangement of alleles on a chromosome is to give the symbols for alleles on one chromosome above a horizontal line, and the symbols for the alleles on the homologous chromosome below the horizontal line. For example: B b. Figure 2. Showing the arrangement of alleles for a pair of linked genes. Here we can see that, exactly like the example in Figure 1, one chromosome carries A and B alleles, while the other chromosome carries a and b alleles. 1. Suppose that Gene G and Gene D are linked. If the genotype of an organism is GGDD, use both types of symbols you learned in Figure 1 and Figure 2 above to show…mapping gene The genes for ruby eyes (rb), tan body (t) and cut wings (ct) are all found on the X-chromosome of Drosophila melanogaster. All of these are recessive traits. They map in the order rb, ct, t with 12.5 map units between rb and ct and 7.5 map units between ct and t. Suppose you cross a cut wing male with a homozygous female that is both tan and has ruby eyes. What will the F1 females look like? Draw map of the section of the X chromosomes that has these 3 genes for the F1 females Assume you testcross your F1 females. What progeny classes would you expect? ii. Give approximate numbers for each class based on a total of 2000 progeny. Assuming the i=1 and there are no double crossovers. Assuming the i=0 and there are the expected number of double crossovers.
- Problem Solving: In Drosophila, the gene that controls red eye color (dominant) versus white eye color is on the X chromosomes. What are the expected phenotypic results if a heterozygous female is crossed with a white-eyed male? In cats, S = short hair; s = long hair; XC = black coat; Xc = yellow coat; XCXc = tortoiseshell (calico) coat. If a long-haired yellow male is crossed with a tortoiseshell female homozygous for short hair, what are the expected phenotypic results?Linkage Mapping Using Dihybrid Testcrosses in Fruit Flies In fruit flies, the normal honey-gray body-color (bl*) is dominant to black (bl), having normal red eyes (pu+) is dominant to purple (pu), and having normal wings (vg+) is dominant to vestigial (vg). The three genes are located close together on the same chromosome. Your task is to use data from three dihybrid testcrosses to (1) calculate recombination frequencies, (2) convert recombination frequencies into map distances, and (3) build a map of the chromosome interval covered by the three genes, indicating their order and distances between them. BLACK PURPLE DIHYBRID CROSS In the parental generation, you mate a pure-breeding wild-type female (bl+/blt;put/pu+) with a pure-breeding black, purple male (bl/bl;pu/pu) to produce an F1 generation that is all wild-type (bl+/bl;pu*/pu). Note that the F1 flies are all dihybrid. Next, you mate several F1 dihybrid females (bl+/bl;pu*/pu) with tester males, which are black, purple…Genetics Problems. Show your crosses. It must contain: (a) parental genes, (b) genotypic ratio, (c) phenotypic ratio, (d) hybrid cross and (e) other answer needed in the question. An albino is a person with no pigmentation in his skin, eyes or hair. Normal pigmentation is (A) is dominant over albino (a). A normal pigmented man marries a homozygous normal woman. What would the expected appearances of the children be