In Drosophila, the gene that controls red eye color (dominant) versus white eye color is on the X chromosomes. What are the expected phenotypic results if a heterozygous female is crossed with a white-eyed male?
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- In Drosophila, the gene that controls red eye color (dominant) versus white eye color is on the X chromosomes. What are the expected
phenotypic results if a heterozygous female is crossed with a white-eyed male? - In cats, S = short hair; s = long hair; XC = black coat; Xc = yellow coat; XCXc = tortoiseshell (calico) coat. If a long-haired yellow male is crossed with a tortoiseshell female homozygous for short hair, what are the expected phenotypic results?
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- QUESTION:- In Drosophila, assume that the gene for scute bristles (s) is located at map position 0.0 and that the gene for ruby eyes (r) is at position 25.0. Both genes are located on the X chromosome and are recessive to their wild-type alleles. A cross is made between scute-bristled females and ruby-eyed males. Phenotypically wild-type F1 females were then mated to homozygous double mutant males, and 1000 offspring were produced. Give the phenotypes and frequencies expected..GENETICS: X LINKED GENES In fruit flies, eye color is a sex linked trait. Red is dominant to white. What are the sexes and eye colors of flies with the following genotypes: XRXr XRY XRXR X'Y What are the genotypes of these flies: white eyed, male red eyed female (heterozygous). red eyed, male white eyed, female Show the cross of a white eyed female X'X' with a red-eyed male XRY. Show a cross between a pure red eyed female and a white eyed male. What are the genotypes of the parents: & & Show the cross of a red eyed female (heterozygous) and a red eyed male. What are the genotypes of the parents? How many are: white eyed, male_ red eyed, male How many are: white eyed, male white eyed, female red eyed, male red eyed, female white eyed, female red eyed, femaleTopic: Gene Locus Height in gryphons is determined by a single locus. You cross a two 9' tall gryphons and get 1/4 10'; 1/2 9' and 1/4 8' tall gryphons. If you across two 7' tall gryphons you get 1/4 8', 1/2 7'; 1/4 6' tall gryphons. pls kindly help to explanation: why In gryphons, alleles of the height lous are semidominant and form an allelic series. A.
- In Drosophila, the gene w specifies eye color. Wildtype allele w+ gives red eyes and is dominant. The recessive allele w specifies white eye color. The gene m specifies wing size and the wildtype allele m+ gives normal wing whereas the recessive allele m specifies miniature wing. Both genes are on the X chromosome. If you cross a female fly (red eye, normal wing) with a male fly (white eye, miniature wing), you get a total of 100 progeny, 41 red eye + miniature wing, 45 white eye + normal wing, 6 white eye, miniature wing, and 8 red eye, normal wing. In each category, both males and female are present, at roughly equal proportions. a). Which ones are parental types and which ones are recombinants? b). Are the two mutant alleles w and m in cis or in trans in the female parent? Why? c). What is the genetic distance between the two genes? Please show your calculations. d). A third gene vg on the X chromosome is 3 cM apart from the w gene. Please draw out two possible orders of the three…Topic: Penetrance. Petal number is controlled by a single gene in merigonias. The gene has a completely dominant wild type allele F that makes a plant have five petals and a mutant recessive six petal allele(f). However the six petal trait is only 50% penetrant. You do the cross Ff x Ff. What fraction of the progeny do you have the 6 petals? what is the meaning for 50% penetrant.Genetics 181 Rule of Incomplete Dominance When two different pure-breeding strains are crossed, and their offspring show a blending of phenotypes, then neither allele is dominant. This is easily recognized when the phenotype is somewhere between two extremes. Counting the parents, there are three phenotypes (black, white, grey) being expressed in these flowers instead of only two, and that third phenotype is intermediate between the other two. This heterozygous condition is called incomplete dominance. 1. On the chart you did earlier, which of the three hair types (wavy, curly, or straight) represents incomplete dominance-the blended heterozygous condition? 2. You cross a herd of red cattle with white cattle and all of the calves appear to be roan (reddish white). Is this an example of incomplete dominance? How do you know? 3. You cross a blue flowering pea plant with a white flowering pea plant and all of the offspring are blue flowered. Is this an example of incomplete dominance? How…
- Cross C: Homozygote wild type flies (+/+) were crossed with white eye flies. The table shows the results for the F1 and F2 generations. White eye females Wild type females White eye males Wild type males 50 F1 phenotypes (observed) F2 phenotypes (observed) F2 - expected phenotypes 50 60 60 60 60 What does the F1 tell you about the trait? Is the gene on an autosome or sex chromosome? What was the genotypes of each parent, male and female? What are the genotypes of the F1 flies? The F1 were crossed with each other and the phenotypes found in F2 are shown in the table above. Are these results consistent with the F1 and your theory of inheritance of this gene? Do a X2 test to see if the observed numbers are consistent with your theory.In Drosophila the genes forked bristles (f and f+) and vermilion eyes (v and v+) are ~24 m.u. apart on the X chromosome. From a cross of f v / f+ v+ females with f v / y males, what % of the progeny do you expect to have the f+ v+ phenotypes? (Don’t let the X chromosome throw you off – this question is essentially asking what % of the female’s gametes will be f+ v+).Consider the following three autosomal recessive mutations in Drosophila:vestigial wings (v); wild type is long (v+)black body color (b); wildtype is gray (b+)plum eyes (p); wildtype is red (p+)A vestigal, gray, red female (homozygous for all three genes) is crossed with a long wing, black, plum male (homozygous for all three genes). The F1 female progeny are mated with triple homozygous recessive males. Here is the phenotypic data for the F2 progeny:vestigal; gray; red 580long wings; black; plum 592vestigal; black; red 45long; gray; plum 40vestigal; black; plum 89long; gray; red 94vestigal; gray; plum 3long; black; red 5A total of 1448 progeny were counted.Which one of the following values is the approximate distance between the plum eye color and black body color loci?
- Using Drosophila notation: A.) Diagram the genotype of a female fly that is recessive for apterus (ap, chromosome 2), heterozygous wild-type for black (b, chromosome 2), recessive for forked (f, x-chromosome), and homozygous wild type for rosy (ry, chromosome 3). B.) Diagram the genotype of a male fly that is heterozygous for clot (ct) eyes (an autosomal gene) and has yellow (y) body color (x-linked gene).Part 2 Spotty and Cutie have puppies and 50% of the puppies are unaffected for both traits (not blind and not BHFD). What is Spotty's genotype? bbDD bbdd BBDd BbDd BbDD BBddAnother gene in Drosophila determines wing length. The dominant wild-type allele of this gene produces long wings; a recessive allele produces vestigial (short) wings. A female that is true- breeding for red eyes and long wings is mated with a male that has purple eyes and vestigial wings. F1 females are then crossed with purple-eyed, vestigial-winged males. From this second cross, a total of 600 offspring are obtained with the following combinations of traits: 252 with red eyes and long wings 276 with purple eyes and vestigial wings 42 with red eyes and vestigial wings 30 with purple eyes and long wings Are the genes linked, unlinked, or sex-linked? If they are linked, how many map units separate them on the chromosome?