*Using the Taylor equation for tool life and Tetting n = 0.5 and C= 400, calculate the percentage increase in tool life when the cutting speed is reduced by 50%. 100% b. 200% a. 300% d. C. 400%
Q: 22. Calculate the rpm for machining a cast iron work piece 10 inches in diameter and the cutting…
A:
Q: Examples (homework) 1. In orthogonal cutting if the depth of cut is a 1.25 mm and chip thickness…
A: As per our guidelines, we are supposed to answer only first one question in case of multiple…
Q: Turning tests have resulted in 1 min tool life at a cutting speed = 4.0 m/s and a 20 min tool life…
A:
Q: Make a comprehensive write up on tool-wear and tool life with due reference to cutting speed and…
A: Short cutting times, long tool life, and great cutting precision are ideal cutting circumstances.…
Q: Given that the length of a work-piece made from copper alloy to be face-milled is 250 mm and the…
A: Given : L = 250 mm D = 150 mm z = 10 To find : Cutting speed and feed
Q: Using the Taylors tool life equation with exponent n = 0.5, if the cutting speed is reduced by 50%…
A: Given Data n=0.5 V2=0.5V1
Q: The following data pertain to a vertical milling operation: 200 600 (L)* 30(W) * 25 (t) Diameter of…
A:
Q: In orthogonal machining operation the chip thickness and the uncut chip thickness are equal to 0.45…
A: Given:Chip thickness=uncut chip thickness=0.45 mmt1=t2=0.45 mmr=1α=0o
Q: Find the machining time required to turn a mild steel rod from 65mm to 58 mm over a length of 100 mm…
A: Given data: - The initial diameter of the rod is D = 65 mm. The final diameter of the rod is d = 58…
Q: regrind and machining cost is Rs.10/min. Tool change time is 2 min. Optimum cutting speed (in m/min)…
A:
Q: Q4: Answer the following questions: 1. Increasing cutting speed is undesirable at any time to raise…
A:
Q: During orthogonal cutting of MS with a 10 ° rake angle tool, the chip thickness ratio was obtained…
A: Given data: The rake angle is θ = 10o. The chip thickness ratio is r = 0.4.
Q: Taylor's tool life equation is given by VT" = C, where V is in m/min and T is in min. In a turning…
A: Given:- Equation:-VTn=CFor tool Xn=0.3C=60For tool Yn=0.6C=90To find:-Cutting speed
Q: . Let n = 0.5 and C = 90 in the Taylor equation for tool wear. What is the percent increase in…
A: GIVEN DATA- IN TAYLOR TOOL LIFE EQUATION n=0.5, C=90
Q: 22.36 Referring to Table 22.1, state which tool materials would be suitable for interrupted cutting…
A: Tool materials would be suitable for interrupted cutting operations :-
Q: In a turning operation on carbon steel with hardness- 175 HB. the cutting speed - 225 m/min, feed-…
A: GivenV=225m/minf=0.25mm/revd=7.5mmη=90% Cutting energy for Brinell hardess 175Hb=1.6J/mm3U=1.6J/mm3
Q: value. The exponent nin Taylor's tool life equation In a machining operation, doubling the cutting…
A:
Q: (i) For a 400 minute tool life, which tool is recommended and why? (ii) The tool changing time for…
A:
Q: In a cutting test with 0.3 mm flank wear as tool failure criterion, a tool life of 10 min was…
A: Taylor's tool life equation is given by F.W. Taylor. Taylor's tool life equation gives the relation…
Q: 3. A slot of 20 mm width is to be produced using horizontal milling machine. The ks 5,000 N/mm?,…
A:
Q: In a turning operation, the tool life varies with cutting speed, as shown in following table:…
A: Turning operation is the manufacturing technique that is done on a lathe machine. In this operation,…
Q: 22.25 Can cutting fluids have any adverse effects in machining? If so, what are they?
A: Generally, cutting fluids are used for carrying away the heat generated. Cutting fluids can also…
Q: Why are tool temperatures low at low cutting speeds and high at high cutting speeds?
A: Solution:
Q: In a machine test, a cutting speed of 100 m/min indicated the tool life as 16 min and a cutting…
A: Given data: The first cutting speed is V1 = 100 m/min. The tool life based on first cutting speed…
Q: 2. Illustrate the influences of tool wear on the workpiece and the overall machining operation.
A: Due to the tool wear following consequences can be seen - The cutting temperature will increase.…
Q: 22.30 Negative rake angles generally are preferred for ceramic, diamond, and cubic-boron-nitride…
A:
Q: In addition to cutting speed, what other cutting variables are included in the expanded version of…
A: The expression for the modified Taylor's tool life equation can be expressed as below, TL=CTVxS0ytz…
Q: During orthogonal cutting of MS with a 15degree rake angle tool, the chip thickness ratio was…
A: As per given question Rake angle =15° Chip thickness =0.2 We have to determine shear angel
Q: A tool with zero rake angle used in orthogonal cutting when its clearance angle a is changed from 10…
A: Given:initial rake angle, α1=10ofinal rake angle, α2=7o
Q: (j) In a turning operation on stainless steel with hardness = 200 HB, the cutting speed = 250 m/min,…
A: Given data : stainless steel with hardness = 200 HB cutting speed (v) = 250 m/min feed (f) = 0.3…
Q: In turning operation, spindle speed is set to provide a cutting speed of 2.2 m/- The feed and depth…
A: We know for orthogonal turning...
Q: Discuss three (3) advantages of using cutting fluids in machining operation
A: GIVEN TOPIC- Machining Operation Discussion -Advantages of using cutting fluids in machining…
Q: In a surface broaching process, a broach having 8 mm pitch and cut per teeth 0.01 mm is used for…
A:
Q: In an orthogonal machining with a tool of 9 degree orthogonal rake angle, the uncut chip thickness…
A: Given, Orthogonal rake angle = α = 9o Uncut chip thickness = t = 0.2 mm Minimum chip thickness = tc1…
Q: 1. In a production turning operation, the cylindrical workpiece is 425 mm long and 190 mm in…
A:
Q: to remove more material betwee
A: The distance (ft) the tool travels before it reaches the end of its life (a specified wear land) is…
Q: A turning operation is carried out on aluminum. Based on the specific energy values in Table 17.2,…
A:
Q: Write down the steps required to proof the mathematical relation for SHEAR PLANE ANGLE in Orthogonal…
A:
Q: 1. “Milling is an intermitted cutting operation”. Explain it.
A: Intermittent cutting means the cutting is not continuous. That means at some time the tool is in…
Q: 2:(b) “Milling is an intermitted cutting operation”. Explain it.
A: Intermittent cutting means the cutting is not continuous. In other words at some time cutting tool…
Q: In turning of stales steel alloy, 1100 mm length and 400 mm diameter, the Feed was 0.35 mm/rev, and…
A:
Trending now
This is a popular solution!
Step by step
Solved in 3 steps
- Question: Determine the optimum cutting speed for an operation on a Lathe machine using the following information: Tool change time: Tool regrinds time: 3 min Machine running cost Re.0.50 per min Depreciation of tool regrinds Rs. 5.0 The constants in the tool life equation are 60 and 0.2 3 minIn machining operation, if velocity doubled then the tool life reduced to 1/16 th of initial value find the Taylor's tool life index (n) for a machining operation.In machining operation, if velocity doubled then the tool life reduced to 1/16 th of initial value. What is the Taylor's tool life index (n) for a machining operation?
- In orthogonal machining operation the chip thickness and the uncut chip thickness are equal to 0.45 mm. If the tool rake and is 0 deg. What is the shear plane angle?A mild steel specimen of Initial diameter of 30.5 mm is turned to final diameter of 27 mm for an initial length of 153 mm on a lathe machine. Using the given data find the following. (i) Feed of 0.4 mm/rev & Depth of cut is 0.5 mm (ii)During machining the tool's approach length is 5 mm, over run length is 2mm (iii) Time required to complete one single turning operation is 3.5 minutes (a)Find number of passes to finish the entire turning operation (b) Total time required to complete the turning operation in minutesA mild steel specimen of Initial diameter of 30.5 mm is turned to final diameter of 27 mm for an initial length of 153 mm on a lathe machine. Using the given data find the following. (i) Feed of 0.4 mm/rev & Depth of cut is 0.5 mm (ii)During machining the tool's approach length is 5 mm, over run length is 2mm (iii) Time required to complete one single turning operation is 3.5 minutes (c) Spindle speed in in rpm (= (d) Cutting speed in m/minutes(=
- Determine the optimum cutting speed for an operation on a lathe machine using the following information: Tool change time 3 min Tool regrind time 3 min Machine running cost Re. 0.50 per min Depreciation of tool regrind Re. 0.50 The constants in the tool life equation are 60 and 0.2.A mild steel specimen of Initial diameter of 32.5 mm is turned to final diameter of 25 mm for an initial length of 154 mm on a lathe machine. Using the given data find the following. (i) Feed of 0.3 mm/rev & Depth of cut is 0.5 mm (ii)During machining the tool's approach length is 6 mm, over run length is 3mm (iii) Time required to complete one single turning operation is 2.3 minutes (a)Find number of passes to finish the entire turning operation (b) Total time required to complete the turning operation in minutes (c) Spindle speed in in rpm (d) Cutting speed in m/minutesIn machining operation, if velocity doubled then the 1ool life reduced to 1/16 th of initial value. Taylor's tool life index (n) for a machining operation is
- A mild steel specimen of Initial diameter of 51.5 mm is turned to final diameter of 48 mm for an initial length of 151 mm on a lathe machine. Using the given data find the following. (i) Feed of 0.1 mm/rev & Depth of cut is 0.5 mm (ii) During machining the tool's approach length is 7 mm, over run length is 2mm (iii) Total time required to complete the turning operation is 48.8 minutes (a) Find number of passes to finish the entire turning operation (b) The actual length of the turning operation in mm ( (c)The time required to complete one single turning operation in minutes (d) Spindle speed in rpm3) Turning: A turning operation is to be adopted under the following machining conditions: Cutting speed: V = 75 m/min Feed rate: f= 0.25 mm/rev Depth of cut: a = 1.75 mm External workpiece diameter: Do = 50 mm Determine: a. The final workpiece diameter b. The rotational speed of the workpiece c. The tool feed rate expressed in m/min d. The material removal rate mm³/min e. The specific energy of the material assuming that the measured cutting force is F= 750 N. Knowing the specific energy, which of materials from the table below could the workpiece be composed? Approximate Specific-Energy Requirements in Cutting Operations SPECIFIC ENERGY* MATERIAL Aluminum alloys Cast irons Copper alloys High-temperature alloys W-s/mm³ 0.4-1.1 1.6-5.5 1.4-3.3 3.3-8.5 0.4-0.6 4.9-6.8 3.8-9.6 3.0-5.2 2.7-9.3 3.0-4.1 hp-min/in³ 0.15-0.4 0.6-2.0 0.5-1.2 1.2-3.1 0.15-0.2 1.8-2.5 1.1-3.5 1.1-1.9 1.0-3.4 1.1-1.5 Magnesium alloys Nickel alloys Refractory alloys Stainless steels Steels Titanium alloys * At…Exercises 4 1. A 30 mm diameter mild steel bar is being turned at a spindle speed of 8 rev/s, on a multi-tool centre lathe having eight tools in operation. The feed is 0-3 mm/rev, the specific cutting pressure/tool is 2 000N/mm and the total power consumed for the operation is 14 kW. If the depth of cut is to be kept the same for each tool, calculate the depth of cut/tool in mm.