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- What is meant by the term diploid? Which cells of the humanbody are diploid, and which cells are not?Pls answer the very last question. “ suppose that lll-2 and lll-5 were to have a child. What is the probability that their first child will be have the disorder?”What are twins?Genetically what are the twotypes of twins that can begenerated?
- What is epistasis? What is the difference between dominant epistasis and recessive epistasis?When a phenotype varies continuously withlevels of protein function, why incomplete dominance results.?. BRCA1 is a bi-allelic gene (let's call the two alleles as C and c) that is inherited on an autosome. The C allele is completely dominant over c, expressing breast cancer as a phenotype. Eye color is determined by two independently assorting bi-allelic genes, B (alleles B and b) and G (alleles G and g), such that the Ballele shows dominant epistasis over the G and g alleles. Brown-eyed individuals have at least one copy of the B allele, green eyed individuals have at least one G allele, while blue eyed individuals have neither B nor G. A blue-eyed person whą is a heterozygote carrier for the BRCA1 gene has 3 children with a brown-eyed person (heterozygote for both B and G genes) who does not have breast cancer. (a) What are the possible genotypes and phenotypes of all their possible children? What are their respective probabilities of being observed (please write all genotype and phenotype probabilities)? (b) What is the probability that all three children will be blue-eyed and not…
- Explain the principle of independent assortment.Hypophosphatemia (vitamin D-resistant rickets) is inherited as a sex-linked dominant trait (H). A) A normal woman and a man with hypophosphatemia marry. What is the chance of having daughters with rickets? Sons? B) A heterozygous woman and a normal man marry. Does the mother have rickets? What is the chance of having daughters with rickets? Sons?Ill.siven the following pedigree below, use Punnett squares for each of the following possibilities: a) X- linked dominant, b) X-linked recessive, c) Autosomal dominant and d) Autosomal recessive in order to determine what is the mode of transmission of this trait. Disease allele = Xª, x², A or a depending on mode of transmission of the disease respectively. Unaffected X chromosome = X *Homozygous unaffected/No 1 *2 carrier=Normal II 1 *4 1 2 3 6. 7 8 a) X-linked dominant 11x12 b) X-linked recessive I 1 x1 2 c) Autosomal dominant 11x12 d) Autosomal recessive I1x12 IV. Based on your analysis what is the mode of transmission for this disease? O+
- The aldose gene is 10 map units from the fructose gene. (A = dominant allele, can produce aldose; a = recessive allele, cannot produce aldose; F = dominant allele, can produce fructose; f = recessive allele, cannot produce fructose). You cross worms with the chromosomes shown below. What is the probability that offspring will be able to produce only aldose (and not fructose)? A f a f ----- X ----- a F a f A) 10% B) 5% C) 90% D) 45% E) 0% F) 25% G) 50% H) 33%. Differentiate between the following:(a) dominant and recessive (b) gene and allele (c) homozygous and heterozygouWhat does genetic heterogeneity mean?