Please only answer question 4 Parts C and D
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Please only answer question 4 Parts C and D
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- A reversible refrigerator operates using a Carnot refrigeration cycle. It operates usingr-134a between 140 and 400 kPa. The refrigerant exits the compressor (and enters the condenser) assaturated vapor. It also leaves the condenser as saturated liquid.a. Sketch the P-v and T-s diagram of this cycle. Define the coordinate properties of each state oneach graph.b. Evaluate the specific heat and specific work properties of each (in kJ/kg). Indicate the sense.c. Evaluate the coefficient of performance using the specific heats and works from the previousitem. Did it match with the COPR obtained if you used the operating temperatures? Solve for states first. Then, show the solution to each of the above required in order.A two stage refrigeration cycle is shown in fig. B. The working fluid is refrigerant 134a. The interchanger is a heat exchanger where the heat absorbed by the refrigerant in the higher-temperature cycle 2 serves to condense the refrigerant in the lower-temperature cycle 1. The refrigerant in cycle 1/2 leaves the interchanger as saturated liquid/vapor. The corresponding temperatures of saturation are 5.12 ℉ / 0 ℉. The saturation temperature in the evaporator is -40 ℉. The pressure in the condenser is 60 psia. The compressor in cycle 1 operates isentropically. The compressor in cycle 2 has an isentropic efficiency of 80%. (a) Sketch the cycle in a T-s diagram and determine the enthalpy at each point of the cycle. (b) Calculate the ratio of the mass flow rates of the refrigerant in the two cycles. (c) Calculate the coefficient of performance of this refrigeration cycle.with schematic diagram A vacuum refrigeration system consists of a large insulated flash chamber kept at low pressure by a steam ejector which pumps vapor to a condenser. condensate is removed by a condensate to an air vent. warm return water enters the flash chamber at 13 c, chilled water comes out of the flash chamber at 5 c. vapor leaving the flash chamber has a quality of 0.97 and the temperature in the condenser is 32 c. for 350 kw of refrigeration. a) how much chilled water at 5 deg C does this system provide b) how much make up water is needed c) how much vapor must the system ejector remove from the flash chamber answers: a) 10.41 kg/s b) 0.1521 kg/s c) 21.7 kg/s
- Refrigerant 22 is the working fluid in a Carnot refrigeration cycle operating at steady state. The refrigerant enters the condenser as saturated vapor at 36°C and exits as saturated liquid. The evaporator operates at -30°C. What is the coefficient of performance of the cycle? A 10 B 3.68 8.53 5The figure shown represents a refrigeration system works with R-134a as a refrigerant to produce 20 T.R. The evaporator, flash sub-cooler and condenser temperatures are respectively -23 °C, 0 °C and 42 °C. The liquid refrigerant leaves the condenser saturated and it is sub-cooled 7 °C in the liquid flash sub-cooler. Vapor leaves the evaporator coil with 5 °C superheated. Adiabatic compression efficiency is 90 % for each stage. Find the power required to derive the compressor and C.O.P of the system. Cond Evap 8 C₁ C₂4. The values of a vapor compression refrigeration cycle were given below. Calculate the values of refrigerant flow rate, refrigeration capacity, and the COP of the system. T1= Evaporator water outlet = 10 °C T2= Evaporator water inlet = 16 °C T3= Condenser water inlet = 16 °C T4= Condenser water outlet = 22°C Cooling water flow rate = 1.5 L/min Heating water flow rate = 1.5 L/min Enthalpy of R134a in evaporator outlet = 305 kj/kg, Enthalpy of R134a in evaporator inlet =115 kj/kg Enthalpy of R134a in condenser inlet =327 kj/kg
- As shown below, a refrigeration cycle condenses a flow of ammonia from a saturated vapor at 4 barto a saturated liquid. The entering volumetric flow rate of the ammonia is 0.1 m3/s. The ammonia functions asthe cold reservoir for the refrigeration cycle, and the hot reservoir is at 25 ∘C. A faded specification sheet for therefrigeration cycle reads that the required power input is 35 kW.(a) Is this cycle possible? Why or why not?(b) If the cycle is impossible, how much work input is required to make the cycle1st Step: Evaluate the performance of the Refrigerator 1.Refrigerator 1 operates as a reverse Carnot cycle using R-717 as the refrigerant at aflow of 1.8 kg/s. The condensing and evaporating temperatures are 25 °C and -5 °C, respectively.To evaluate the performance of Chiller 1, you must determine the following performance parameters:project:a) Rate of heat elimination in the condenser (Q );b) The power of the compressor;c) The COP of the cycle.For the energy balance, make the following considerations:- Permanent regime;- Variation of kinetic energy and potentials are negligible;- Compressor and turbine operate adiabatically;- Evaporation and condensation steps do not involve work. Please, make it typeable, written in virtual text, do not do it by hand and do not take a photo, it interferes with the understanding of the lyrics.Q2/ A vapor-compression refrigeration system operates on the cycle. The refrigerant is tetrafluoroethane. For Evaporation T = 0°C; condensation T = 26°C; n(compressor) = 0.79; refrigeration rate = 600 kJ-s—1., determine the circulation rate of the refrigerant, the heat-transfer rate in the condenser, the power requirement, the coefficient of performance of the cycle
- Q2: Two stage vapour compression refrigeration system with water intercooler uses R-22 as shown in figure 2 below. The evaporating temperature is -40 °C and condensing temperature 40 °C. The refrigeration capacity is 10 TR and the compression is adiabatic reversible process. The refrigerant leaves the water intercooler at 10 °C. Draw the cycle on p-h diagram and determine:- 1- The refrigerant mass flow rate. 2- Work done of each compressor. 3- Condenser heat load. >4- Coefficient of performance. 60 1Step: Evaluate the performance of Refrigerator 2.Refrigerator 2 is a refrigerator that operates as an ideal vapor refrigeration cycle, and uses theSame refrigerant and evaporation and condensing temperatures as Refrigerator 1.In Cooler 2, the working fluid must be admitted by the compressor only in the form of vaporsaturated, and must leave the compressor in the form of superheated steam with enthalpy equal to 1640 kJ/kg.Differently from Refrigerator 1, the cycle operates with an expansion valve (isenthalpic process).For this 2nd step, you must determine the following design parameters:a) The rate of cooling and the rate of heat rejection in the condenser.b) The power of the compressor;c) The COP of the cycle.For the energy balance, make the following considerations:- Permanent regime;- Variation of kinetic and potential energy are negligible;- Compressor and expansion valve operate adiabatically;- Evaporation and condensation steps do not involve work. Please, make it typeable,…The values of a vapor compression refrigeration cycle were given below. Calculate the values ofrefrigerant flow rate, refrigeration capacity, and the COP of the system.T1= Evaporator water outlet = 10 °CT2= Evaporator water inlet = 16 °CT3= Condenser water inlet = 16 °CT4= Condenser water outlet = 22°CCooling water flow rate = 1.5 L/minHeating water flow rate = 1.5 L/minEnthalpy of R134a in evaporator outlet = 305 kj/kg,Enthalpy of R134a in evaporator inlet =115 kj/kgEnthalpy of R134a in condenser inlet =327 kj/kg