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- The characteristic equation of sixth order system is as below find the stability of system. + 2s° + 8s4 + 12s + 20s? + 16s + 16 = 0-9158388cmid%3D3385218&page%3D15 For the circuit shown in the figure, the Norton current (IN) at terminals a-b is: 32 16V 60 2 2V O a. 12 A b. 5.3 A Oc. 5.67 A Od. 4 A. e. -8 A gesohw circuit diagram and step by step solution pls
- 2. Detormine whether or not the following equnlities correct: a. A+B C+ÕC = BC b. B(AO c) +B C+ A(BOC) = AC 3. Convert the following expressions to SOP forms: a. (A +B C) B b. (A + C)(A•B č+A•C• D)Problems: Find the trans fer function for Cisi/Ris) fur the following controd systems by using block diagrum reduction H2 b) Repto Risst Gi G2 G3 Hi G4Ministry of Manpower Directorate General of Technological Education Salalah College of Technology Zlectrical Inginearina Problem - 8 Refer to the circuit below and -25V C2 N. compute the following: i) Total capacitance ii) Voltage across C, iii)Charge across C, iv)Voltage across C5 5 uF C1 5 uF 5 uF C4 5 uF C6 5 uF -16-65V. C5 5 uF (Take V, as 25V) 8-35V VT 25V
- K 1:08 docs.google.com 8 upload solutions here * Q1/ A. For the following Figune Find ITo tal, VRI, VR2 4kr siL Si3 1ov. 3 V R22K2 G1/B- For the following Figure VR3, VR2, IR2 , IR Find: R. lov a2/.Design Circint as the following pescripton: A- the positive Cycle of the vout signal is 3-2 and Negatine cycle is 4-3 (Note: we must used preetical Diodes and vin is tov) 13- the positive cycleg of vaut is s-3 and Negative cycle is (5.4) [Note:consider tovavd we must used Cupaetor with praetical Drode) vin = 1 Add file AYMATLAB R2022b-academ HOME ++ Cu... O New Open Save P |349933331 D... A W... Ⓒ Name col delt HE E_a Hi HJ kB kB_ kB latt latt M M_ |N n_n +7 1 2 3 Editor - C:\Us MP5_5 N = n_sp J = kB = T1 = T2 = n_mc n_pr 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 FILE 22 23 24 8 25 26 27 28 29 PLOTS 40 CL fx >> latt latt % IN N M = E = M_ar E_ar Command Wind >> SW8 Tr Magnetiza Magnetiza 3.2.1. % MO m tic; for Total tim Total tim File 1 11 Home Page 3 of 3 = Insert Design Layout References 0 words 2 For numbers 29 to 30, Given the circuit below. Complete the table of the missing information R1 www 12kQ V1 48V 3 Norton current (mA) Load voltage when R₁ = 2 k English (Philippines) 1 2 3 4 5 6・・・・・・ 7・・・・・ 8 Resonance frequency (Hz) Maximum current (A) Maximum voltage (V) Lower cut-off frequency (Hz) High cut-off frequency (Hz) Bandwidth R2 ww 8kQ Mailings R3 4kQ2 (31) (32) 10 1681 2305 RL 5kQ2 Review Calculated values (29) (30) For numbers 31 to 33, given the circuit below with L = 25.5 mH and C =…MATLAB R2022b-academ HOME ++ Cu... O New Open Save P |341433111 D... A W... Ⓒ Name col delt HE E_a Hi HJ kB kB_ kB latt latt M M_ |N n_n 1 2 3 Editor - C:\Us +7 MP5_5 N = n_sp J = kB = T1 = T2 = 5 6 7 8 9 10 11 12 13 2242972982 14 15 16 17 18 19 20 21 FILE 22 23 24 8 25 26 27 28 29 PLOTS CL fx >> n_mc n_pr latt latt % In M = E = M_ar E_ar % Mo tic; for Command Wind >> SW8 Tr Magnetiza Magnetiza Total tim Total tim ir 11,1,1,3,1,1,,,2,1,1,1,1, File 1 Page 4 of 5 Home Insert 0 words 1 Design V1 10V 10Hz R1 ww 1k92 Layout References capacmance across the nodes and 0? a) Circuit 1 b) Circuit 2 c) Circuit 3 d) Circuits 1 and 3 2 C1 10μF Mailings C2 10μF a) Circuit 1 b) Circuit 2 c) Circuit 3 d) Circuits 1 and 3 English (Philippines) 1 2 3 4 5 6・・・・・・ 7・・・・・ 8 C3 10μF Review Circuit 2 ru 1 V1 ru 10V 10Hz View Document1 - Word (Product Activation Failed) Tell me what you want to do... 1 R1 ww 1kQ T V1 10V 10Hz 0 R1 ww 1kQ 2 2 C3 HH 10μF C1 HH 10μF C1 HH 10μF 3 4 3 - និ C2 10μF C2 10μF Circuit…
- Questions 16 to 20 (Write True or False) A16 A larger inductor produces a smaller rate of change of current. A17 KVL states that E IR + E EMF = 0 for any open circuits. A18 For a sine waveform, the value of form factor is 1.414. A19 In a purely inductive circuit, the current lags the voltage by II/4 rads. In an ideal transformer, the rate of change of flux is the same for both primary A20 and secondary.MATLAB R2022b-academ HOME New Open Save P |999999941, FILE ++ ADD¯ ► Cu... O Editor - C:\Us +7 MP5_5 N = n_sp J = kB = T1 = T2 = n_mc n_pr D... A W... Ⓒ Name col delt HE E_a Hi HJ kB kB_ kB latt latt M M_ |N n_n 1 2 3 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 8 PLOTS 25 26 27 28 29 CL fx >> latt latt % In M = E = M_ar E an % MO tic; for Command Wind >> SW8 Tr Magnetiza Magnetiza Total tim Total tim .....3、、、、...2... L File 1 Page 2 of 2 Home R1 Insert Design R2 R3 6. Which of the following resistors has R = 2 k? a) A b) B c) C d) D 9 8 Effective resistance (kn) 7 6 3 2 1 0 Layout References 0 8.00 4.00 (9) I (mA) V (Volt) (7) (8) A -B -C D 0.5 1 1.5 0 words English (Philippines) 1 2 3 1 (10) Mailings . For numbers 7 to 10, complete the table of missing information. 4.00 2 V (volt) 1 I V1 12V Review 2.5 R1 Document1 - Word (Product Activation Failed) Tell me what you want to do... View CAT NOOISTOT T 1kQ2 3 3.5 4 2 R2 ww 1k92 R3 1k92 * ****.. 4 5 6・・・・・7・・・・・・8・・pa + 1 For…Application: Construct the circuit in figure. R= 2,2KN, L = 1 mH, and C= 10 nF. L Necesssary Formulae: 1 Xc 2.π.f.C X.-2. π.f. L By using the formulea perform the calculations of Xc and XL then fill the table. f (Hz) Xc XL 50000 60000 70000 80000 90000 100000 110000 120000 130000 140000