Q4) In fatigue test, the specimen constructed as in figure, which its broken at 50118 revolution. Calculating the maximum bending stress in Mpa applied to the specimen at a diameter 5 mm. L=125.2 mm H diameter 5 mm = 29.4 N
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- Solve the preceding problem if the cross- sectional dimensions are b = 1.5 in. and h = 5.0 in., the gage angle is ß = 750, the measured strains are = 209 × 10-6 and B = -110 × 10, and the material is a magnesium alloy with modulus E = 6.0 X 106 psi and Poisson’s ratio v = 0.35.Solve the preceding problem if the thickness of the steel plate is. t = 12 mm. the gage readings are x = 530 × 10-6 (elongation) and y = -210 -× l0-6 (shortening), the modulus is E = 200 GPa, and Poisson’s ratio is v = 0.30.diagram and determine approximately the modulus of elasticity, the yield stress, the ultimate stress, and the fracture 2.00 in. The data is listed in the table. Plot the stress-strain 8-1. A tension test was performed on a steel specimen n original diameter of 0.503 in. and gage length of PROBLEMS *84. origi the f having an for t and stress. Use a scale of 1 in. Dodraw the elastic region, using the same stress scale but a 20 ksi and 1 in. = 0.05 in./in. strain scale of 1 in.= 0.001 in./in. Load (kip) Elongation (in.) 0. 0. 0.0005 0.0015 1.50 4.60 8.00 11.00 0.0025 0.0035 0.0050 11.80 11.80 0.0080 0.0200 12.00 16.60 0.0400 0.1000 0.2800 20.00 21.50 19.50 18.50 0.4000 0.4600 Prob. 8-1
- Tensile test specimens are extracted from the "X" and "y" directions of a rolled sheet of metal. "x" is the rolling direction, "y" is transverse to the rolling direction, and "z" is in the thickness direction. Both specimens were pulled to a longitudinal strain = 0.15 strain. For the sample in the x-direction, the width strain was measured to be ew= -0.0923 at that instant. For the sample in the y-direction, the width strain was measured to be gw=-0.1000 at that instant. The yield strength of the x-direction specimen was 50 kpsi and the yield strength of the y-direction specimen was 52 kpsi. Determine the strain ratio for the x direction tensile test specimen. Determine the strain ratio for the y-direction tensile test specimen. Determine the expected yield strength in the z-direction. Give your answer in units of kpsi (just the number). If the sheet is plastically deformed in equal biaxial tension (a, = 0, to the point where & = 0.15, calculate the strain, 6, that would be expected.A tensile test specimen has a gage length = 3.0 in and diameter 0.75 in. Yielding occurs at a load of 38,000 lb. The corresponding gage length 3.01 03 in (neglect the 0.2 percent yield point). The maximum load of 54,000 lb is reached at a gage length 3.453 in. Determine the tensile strength (round to the nearest whole Ksi) 3860mm 2. H we measure a &=13µm decrease in the bolt diameter d. Bolt material properties are given as G=77 GPa and v=0.3. The bolt in the following figure when tightened, Determine the internal force at the bolt due to bolt tightening. i. 1 09 = p
- uniform diameter d= 1.75 in. Segment (1) is an aluminum Ę₁ = 10000 ksi L₁ = 90 in. Segment (2) is a copper Ę₂ = 17000 ksi L₂ = 126 in. When Pis applied, a strain gage attached to copper segment (2) measures a normal strain of &2 = 1700 uin./in. in the longitudinal direction. What is the elongation of segment (1)? Answer in inch rounded-off to 3 decimal places L₁ A (1) Aluminum B L2 (2) CopperA tensile test specimen has a gage length = 3.0 in and diameter 0.75 in. Yielding occurs at a load of 38,000 lb. The corresponding gage length = 3.0103 in (neglect the 0.2 percent yield point). The maximum load of 54,000 lb is reached at a gage length = 3.453 in. Determine the modulus of elasticity (neglect the 0.2% offset, and round to the nearest whole Msi). 37EHide bl OP=287 N OP=573 N Let's consider a rod having a solid circular cross-section with diameter of 4 mm and it is made of a material having a Young's modulus E = 200 Gpa and a Poisson's ratio of 0.3. If a tensile force F is subjected to that rod cross-section, the diameter becomes 3.998 mm. determine the applied force F. Select one: OF=10472 N OF=15708 N OF=6283 N O F= 4189N F = 13090 N OF= 5236 N Finish attempt.. US ACTIVITY O Test-Spring 2020-2021 Jump to...
- Let's consider a rod having a solid circular cross-section with diameter of 6 mm and it is made of a material having a Young's modulus E = 200 Gpa and a Poisson's ratio of 0.3. If a tensile force F is subjected to that rod cross-section, the diameter becomes 5.995 mm. determine the applied force F. Select one: O F=15708N O F= 10472 N O F=5236 N O F= 13090 N O F=6283 N O F=4189 NThe figure below shows a hollow circular beam with an outside diameter of 100 mm and a wall thickness of 40 mm loaded in bending with force F = 200 kN. F Ra Rb 1m 1 m Young's modulus of the beam is 80 GPa. Calculate the second moment of area, I, in m* in the form a x 10 0 where the number a is correct to two decimal places. I: x10 m4 Calculate the maximum bending moment, M, in kilonewtonmetres (kNm): M: kNm Calculate the maximum bending stress, o, in megapascals (MPa) correct to two decimal places. MPaThe stress strain curve determined from a sample of material is shown in the figure. The original diameter was 14.3 mm and it changed to 14.28858 when a 43.5 kN load was applied. Calculate Poisson's ratio for the sample. o (MPa) 550 400 0.00275 Poisson's ratio v = 0.0