The Robinson annulation is a combination of two carbonyl coupling reactions, the Michael reaction and the intramolecular aldol condensation. The most common partners in the reaction are anucleophilic donor (such as a cyclic ketone, a ß-keto ester, an enamine, or a 6-diketone) and an a 6-unsaturated ketone acceptor The product is a substituted 2-cyclohexenone derivative.Draw the structures of the nucleophilic B-diketone and the a B-unsaturated ketone acceptor that wvere combined in a Robinson annulation to give the following product:PhC P000- IF

The α-β-unsaturated ketones are the organic compounds which contain ketone group in conjugation with…

The Robinson annulation is a combination of two carbonyl coupling reactions, the Michael reaction and the intramolecular aldol condensation. The most common partners in the reaction are a nucleophilic donor (such as a cyclic ketone, a B-keto ester, an enamine, or a B-diketone) and an a6-unsaturated ketone acceptor. The product is a substituted 2-cyclohexenone derivative. Draw the structures of the nucleophilic B-diketone and the aB-unsaturated ketone acceptor that were combined in a Robinson annulation to give the following product: Ph opy ato

The Robinson annulation is a combination of two carbonyl coupling reactions, the Michael reaction and the intramolecular aldol condensation. The most common partners in the reaction are a nucleophilic donor (such as a cyclic ketone, a B-keto ester, an enamine, or a B-diketone) and an a6-unsaturated ketone acceptor. The product is a substituted 2-cyclohexenone derivative. Draw the structures of the nucleophilic B-diketone and the aB-unsaturated ketone acceptor that were combined in a Robinson annulation to give the following product: Ph opy ato

Organic Chemistry: A Guided Inquiry

2nd Edition

ISBN:9780618974122

Author:Andrei Straumanis

Publisher:Andrei Straumanis

Chapter26: Aldol And Claisen Reactions

Section: Chapter Questions

Problem 5E

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The Robinson annulation is a combination of two carbonyl coupling reactions, the Michael reaction and the intramolecular aldol condensation. The most common partners in the reaction are a nucleophilic donor (such as a cyclic ketone, a β-keto ester, an enamine, or a β-diketone) and an α,β-unsaturated ketone acceptor. The product is a substituted 2-cyclohexenone derivative. Draw the structures of the nucleophilic β-keto ester and the α,β-unsaturated ketone acceptor that were combined in a Robinson annulation to give the following product: Draw the β-keto ester as an ethyl ester,
The Robinson annulation is a combination of two carbonyl coupling reactions, the Michael reaction and the intramolecular aldol condensation. The most common partners in the reaction are a nucleophilic donor (such as a cyclic ketone, a β-keto ester, an enamine, or a β-diketone) and an α,β-unsaturated ketone acceptor. The product is a substituted 2-cyclohexenone derivative. Draw the structures of the nucleophilic β-diketone and the α,β-unsaturated ketone acceptor that were combined in a Robinson annulation to give the following product:
The Robinson annulation is a combination of two carbonyl coupling reactions, the Michael reaction and the intramolecular aldol condensation. The most common partners in the reaction are a nucleophilic donor (such as a cyclic ketone, a ß-keto ester, an enamine, or a ß-diketone) and an a,ß-unsaturated ketone acceptor. The product is a substituted 2-cyclohexenone derivative. il The above reaction between a ß-keto ester and an a,ß-unsaturated ketone yields a product containing a 2- cyclohexenone ring. One of the steps of this reaction follows. Draw curved arrows to show the movement of electrons in this step of the mechanism. Arrow-pushing Instructions AC↔XT я OEt -I H OEt CO₂Et Eto: يز OEt EtOH
base 2 H3C H H3C OH heat H H3C + H₂O H The aldol reaction is a carbonyl condensation reaction between two carbonyl partners and involves a combination of nucleophilic addition and a-substitution steps. One partner is converted into an enolate ion nucleophile and adds to the electrophilic carbonyl group of the second partner. In the classic aldol reaction, the carbonyl partners are aldehydes or ketones, although aldehydes are more reactive. The product is a ẞ-hydroxy carbonyl compound. Under reaction conditions slightly more vigorous than those employed for the aldol reaction, the ẞ-hydroxyl group is eliminated in an E1CB dehydration to give an a,ẞ-unsaturated carbonyl compound. Draw curved arrows to show the movement of electrons in this step of the mechanism. Arrow-pushing Instructions X :OH H₂O: а کی H₂C H H₂C H H
I H H3C NOC XT :0: MET H₂C base H3C The aldol reaction is a carbonyl condensation reaction between two carbonyl partners and involves a combination of nucleophilic addition and a-substitution steps. One partner is converted into an enolate ion nucleophile and adds to the electrophilic carbonyl group of the second partner. In the classic aldol reaction, the carbonyl partners are aldehydes or ketones, although aldehydes are more reactive. The product is a ß-hydroxy carbonyl compound. H OH q H3C H₂C H Under reaction conditions slightly more vigorous than those employed for the aldol reaction, the ß-hydroxyl group is eliminated in an E1cB dehydration to give an a,ß-unsaturated carbonyl compound. Draw curved arrows to show the movement of electrons in this step of the mechanism. Arrow-pushing Instructions heat H H + H₂O
The Robinson annulation is a combination of two carbonyl coupling reactions, the Michael reaction and the intramolecular aldol condensation. The most common partners in the reaction are a nucleophilic donor (such as a cyclic ketone, a B-keto ester, an enamine, or a B-diketone) and an a,8-unsaturated ketone acceptor. The product is a substituted 2-cyclohexenone derivative. The above reaction between a enamine and an a,B-unsaturated ketone yields a product containing a 2-cyclohexenone ring. One of the steps of this reaction follows. Draw curved arrows to show the movement of electrons in this step of the mechanism. Arrow-pushing Instructions H-A A OH HO Nest Emal Instructor Save and Ex
2 Moin H3C H H₂C C⇒x= base :0: OH Hori H3C H. The aldol reaction is a carbonyl condensation reaction between two carbonyl partners and involves a combination of nucleophilic addition and a-substitution steps. One partner is converted into an enolate ion nucleophile and adds to the electrophilic carbonyl group of the second partner. In the classic aldol reaction, the carbonyl partners are aldehydes or ketones, although aldehydes are more reactive. The product is a B-hydroxy carbonyl compound. Under reaction conditions slightly more vigorous than those employed for the aldol reaction, the ß-hydroxyl group is eliminated in an E1cB dehydration to give an a,ß-unsaturated carbonyl compound. Draw curved arrows to show the movement of electrons in this step of the mechanism. Arrow-pushing Instructions H₂C Ἡ :0: heat H Home H3C + H₂O
The Stork reaction is a condensation reaction between an enamine donor and an α,β-unsaturated carbonyl acceptor. The overall reaction consists of a three-step sequence of formation of an enamine from a ketone, Michael addition to an α,β-unsaturated carbonyl compound, and hydrolysis of the enamine in dilute acid to regenerate the ketone. Consider the Stork reaction between cyclohexanone and propenal Draw the structure of the product of the enamine formed between cyclohexanone and dimethylamine. - Michael addition to an α,β-unsaturated carbonyl compound, and - hydrolysis of the enamine in dilute acid to regenerate the ketone.
An enolate attacks an aldehyde and the resulting product is subsequently protonated. What type of reaction is this? an acid-catalyzed aldol condensation a Fischer esterification. a Grignard reaction. a base-mediated aldol condensation
The Stork reaction is a condensation reaction between an enamine donor and an α,β-unsaturated carbonyl acceptor. The overall reaction consists of a three-step sequence of formation of an enamine from a ketone, Michael addition to an α,β-unsaturated carbonyl compound, and hydrolysis of the enamine in dilute acid to regenerate the ketone. Consider the Stork reaction between acetophenone and 3-buten-2-one. Draw the structure of the product of the enamine formed between acetophenone and pyrrolidine. Draw the structure of the Michael addition product. Draw the structure of the final product.
H₂C=CHCCH3 then H3O+ The Michael reaction is a conjugate addition process wherein a nucleophilic enolate anion (the donor) reacts with an a,ß-unsaturated carbonyl compound (the acceptor). The best Michael reactions are those that take place when a particularly stable enolate anion is formed via treatment of the donor with a strong base. Alternatively, milder conditions can be used if an enamine is chosen as the donor, this variant is termed the Stork reaction. In the second step, the donor adds to the ẞ-carbon of the acceptor in a conjugate addition, generating a new enolate. The enolate abstracts a proton from solvent or from a new donor molecule to give the conjugate addition product. Draw curved arrows to show the movement of electrons in this step of the mechanism. Arrow-pushing Instructions N 9a
What is the product resulted due to the reaction of 2-hydroxy-3-methoxybenzaldehyde with ethyl bromoacetate in a basic solution indicating all the reagents and intermediates occurred during the reaction? What is the product obtained when product A reacted with ethyl acetate in the same basic solution?