Using Kirchoff's current law, the current for node B gives: I, + l3 - l. Using Kirchoff's voltage law, in the loop EFAB gives: -41,+(-30)-51,– 101, +(-60)– 101, = 0. Using Kirchoff's voltage law, in the loop BCDE gives: -301, + 120 - 101, + 60 = 0 (a) Write down the equations as a system of three linear equations. (b) Use any method to determine the currents 1 . 1, I, flowing in the circuit.

Using Kirchoff's current law, the current for node B gives: I, + l3 - l. Using Kirchoff's voltage law, in the loop EFAB gives: -41,+(-30)-51,– 101, +(-60)– 101, = 0. Using Kirchoff's voltage law, in the loop BCDE gives: -301, + 120 - 101, + 60 = 0 (a) Write down the equations as a system of three linear equations. (b) Use any method to determine the currents 1 . 1, I, flowing in the circuit.

Delmar's Standard Textbook Of Electricity

7th Edition

ISBN:9781337900348

Author:Stephen L. Herman

Publisher:Stephen L. Herman

Chapter7: Parallel Circuits

Section: Chapter Questions

Problem 3PP: Using the rules for parallel circuits and Ohmslaw, solve for the missing values....

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