What is the approximate concentration of free Al³+ ion at equilibrium when 1.13×10-² mol aluminum nitrate is added to 1.00 L of solution that is 1.330 M in F. For [AIF6]³, Kf = 6.9x10¹⁹. [A1³+] = M

Chemistry by OpenStax (2015-05-04)
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Chapter15: Equilibria Of Other Reaction Classes
Section: Chapter Questions
Problem 5E: What additional information do we need to answer the following question: How is the equilibrium of...
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What is the approximate concentration of free Al³+ ion at equilibrium when 1.13×10-²
mol aluminum nitrate is added to 1.00 L of solution that is 1.330 M in F. For
[AlF6]³, Kf = 6.9×10¹⁹
[A1³+] =
M
Transcribed Image Text:What is the approximate concentration of free Al³+ ion at equilibrium when 1.13×10-² mol aluminum nitrate is added to 1.00 L of solution that is 1.330 M in F. For [AlF6]³, Kf = 6.9×10¹⁹ [A1³+] = M
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