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- If the following pedigree is for a family who has sickle cell anemia, which individuals are definitely carriers for ?SCA Il-2 and III-1 only O |-1 and l-3 only O |-1, 1-2, II-2 and III-1 only |-1 and l-2 only O II-1only O 1-1, 1-2, I-3, Il-2 and IlI-1 محو التحديد --The following pedigree follows the inheritance of clubbed fingers in humans. (A) Predict how this disorder is inherited (what pattern of inheritance?). (B) State the genotypes for the individuals listed below.. If more than possibility is possible for an individual, list both. Individuals: 1-2, 1-4, Il-7, III-1, and IV-7 3. 4 6. 7. 3. 6. IVThe following pedigree represents the inheritance of an autosomal recessive disease in a certain family. 2 5 2 4 5 8 3 4. 6. 1 1- How many males are affected by the disease? 3- How many children did the couple Il-4 and Il-5 have? 4- How many sisters did III-8 have? 5- What is the genotype of III-8? 40
- 1. Is this trait autosomal recessive or autosomal dominant? 2. What is the genotype of II-3? 3. Circles that are shaded in means the individual has the condition. True or False? 6 4. The horizontal line connecting Il-4, I-5, and Il-6 means they are 5. What is the genotype of III-2? 4 6. Parents 3 and 4 in the first generation are looking to have a fourth child. What is the probability that the new baby would have the condition?Individual I-2 is genotype GG + Gg + gg Individual Il-2 is genotype GG + Gg + gg Individual II-6 is genotype GG+ Gg + gg Individual IlI-1 is genotype GG + Gg + 99 GG+ Gg + gg Individual IlI-2 is genotype GG+ Gg + gg Individual IV-3 is genotypeTTGG ttgg F1 TG tg F2 TtGg Which types of genotypes are represented in F1 and F2 in the above figure, respectively? heterozygous and heterozygous heterozygous and homozygous homozygous and heterozygous homozygous and homozygous
- Blood types in humans are caused by a combination of two of three possible alleles - IA, IB, and i. The i allele is recessive and individuals homozygous for this allele have blood types O. Blood type A may be due to either homozygous condition or the IA i Blood type AB is caused by having a copy of both the IA and IB alleles. Rh factor is another “marker” on human red blood cells and is either positive (dominant—RR or Rr) or negative (recessive—rr). Franks has blood type A-negative. Frank’s father is B-positive and his mother is AB-positive. Frank marries Susan, a woman that is B-positive. Susan’s mother is A-negative and her father is AB-positive. Give the genotype of all of the individuals mentioned above. b. Give the genotypes and phenotypes of the possible offspring from this marriageUse the pedigree to answer the questions that follow. Make sure you put your answer in the correct blank. A) AB В 1 5 II A A AB B A AB A 3 5 6 7 8 II A A B 2 3 5 6 a) State the possible blood type(s) of individual I-4 b) State the possible blood type(s) of individual I-6 c) State the possible genotype(s) of individual Il-5 d) State the possible genotype(s) of individual II-6 e) Determine the percentage chance that couple Il-4 and Il-5 have another child that has type O blood 2.Consider the pedigree below of a dominant autosomal trait. Which individual must be non-penetrant? Select all that apply. I-1 T-2 I-1I-2 13 I-4 II-5 III-3 IV-1 IV-2 IV-3 III-2 1-2 Il-5 IIl-1 [V-2 IV-1. IV-3 Il-4
- In humans, the Rh factor genetic information is inherited from our parents, but it is inherited independently of the ABO blood type alleles. In humans, Rh+ individuals have the Rh antigen on their red blood cells, while Rh- individuals do not. There are two different alleles for the Rh factor known as Rh+ and rh. Assume that a dominant gene Rh produces the Rh+ phenotype, and that the recessive rh allele produces the Rh- phenotype. In a population that is in Hardy-Weinberg equilibrium, if 160 out of 200 individuals are Rh+, calculate the frequencies of both alleles.There are six types of agglutinogen named C,D, E and c,d,e.the first three are dominant and last three are recessive.discussJunctional epidermolysis bullosa (JEB) is a severe skin disorder that results in blisters over the entire body. The disorder is caused by autosomal recessive mutations at any one of three loci that help to encode laminin 5, a major component in the dermal–epidermal basement membrane. Leena Pulkkinen and colleagues described a male newborn who was born with JEB and died at 2 months of age (L. Pulkkinen et al. 1997. American Journal of Human Genetics 61:611–619); the child had healthy, unrelated parents. Chromosome analysis revealed that the infant had 46 normal-appearing chromosomes. Analysis of DNA showed that his mother was heterozygous for a JEB-causing allele at the LAMB3 locus, which is on chromosome 1. The father had two normal alleles at this locus. DNA fingerprinting demonstrated that the male assumed to be the father had, in fact, conceived the child. Q. Assuming that no new mutations occurred in this family, explain the presence of an autosomal recessive disease in the child…