Physical Chemistry
2nd Edition
ISBN: 9781133958437
Author: Ball, David W. (david Warren), BAER, Tomas
Publisher: Wadsworth Cengage Learning,
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Textbook Question
Chapter 1, Problem 1.49E
Why is nitrogen a good choice for the study of ideal gas behavior around room temperature?
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Why is it that real gases do not behave as ideal gases at very low temperatures?
How does Dalton's law of partial pressures help us with our model of ideal gases? That is, what postulates of the kinetic molecular theory does it support?
c) This relationship is known as Graham's Law of Effusion. Since both gases are at te same temperature, they must
have the same average kinetic energy (½ mv²), where m is mass and v is velocity (like speed). Since both gases have
the same average kinetic
energy, you can state that ½ muvL2 = v ². Multiplying both sides by 2 gives you m v 2 y ². Rearranging the equation to get
H H
LL
H H
2 m
= m
both masses on the same side of the equation will give you mu/mH = V 2/VL2. In 3a and 3b, you probably noticed that the
heavy gas particles took twice as long to diffuse as the light gas particles. This means that the light gas particles are
moving twice as fast, VH/VL = ½. Therefore, V 2/VL2 = ¼. How many times heavier is the heavy gas compared to the
light gas?
d) If the light gas was Ne, what would be a reasonable identity for the heavy gas?
Chapter 1 Solutions
Physical Chemistry
Ch. 1 - A bomb calorimeter is a study metal vessel in...Ch. 1 - Difference between the system and the...Ch. 1 - Prob. 1.3ECh. 1 - Prob. 1.4ECh. 1 - Prob. 1.5ECh. 1 - Prob. 1.6ECh. 1 - Prob. 1.7ECh. 1 - A pot of cold water is heated on a stove, and when...Ch. 1 - hat difference is necessary for heat to flow...Ch. 1 - What is the value of FT for a sample of gas whose...
Ch. 1 - What is the value of FP for a sample of gas whose...Ch. 1 - Prob. 1.12ECh. 1 - Hydrogen gas is used in weather balloon because it...Ch. 1 - Prob. 1.14ECh. 1 - A 2.0 L soda bottle is pressurized with 4.5 atm of...Ch. 1 - The Mount Pinatubo volcano eruption in 1991...Ch. 1 - Prob. 1.17ECh. 1 - Scottish physicist W. J. M. Rankine proposed an...Ch. 1 - Use the two appropriate values of R to determine a...Ch. 1 - Prob. 1.20ECh. 1 - Pressures of gases in mixtures are referred to as...Ch. 1 - Earths atmosphere is approximately 80 N2 and 20...Ch. 1 - The atmospheric surface pressure on Venus is 90...Ch. 1 - Prob. 1.24ECh. 1 - Prob. 1.25ECh. 1 - In the anaerobic oxidation of glucose by yeast,...Ch. 1 - What are the slopes of the following lines at the...Ch. 1 - For the following function, evaluate the...Ch. 1 - Determine the expressions for the following,...Ch. 1 - Determine the expressions for the following,...Ch. 1 - Prob. 1.31ECh. 1 - Prob. 1.32ECh. 1 - Prob. 1.33ECh. 1 - Prob. 1.34ECh. 1 - What properties of a nonideal gas do the Vander...Ch. 1 - Prob. 1.36ECh. 1 - Prob. 1.37ECh. 1 - Calculate the Boyle temperatures for carbon...Ch. 1 - Prob. 1.39ECh. 1 - Prob. 1.40ECh. 1 - Table 1.4 show that the second virial coefficient...Ch. 1 - Prob. 1.42ECh. 1 - What is the van der Waals constant a for Ne in...Ch. 1 - Prob. 1.44ECh. 1 - Under what conditions would the van der Waals...Ch. 1 - By definition, the compressibility of an ideal gas...Ch. 1 - The second virial coefficient B and the third...Ch. 1 - Use the approximation 1 x-1 1 x x2 to...Ch. 1 - Why is nitrogen a good choice for the study of...Ch. 1 - Evaluate for a gas following the Redlich-Kwong...Ch. 1 - Numerically evaluate for one mole of methane...Ch. 1 - Under what conditions of volume does a van der...Ch. 1 - At high temperatures, one of the van der Waals...Ch. 1 - Under what conditions of temperature does a...Ch. 1 - The Berthelot equation of state for one mole of...Ch. 1 - Prob. 1.56ECh. 1 - Referring to exercises 1.6 and 1.7, does it matter...Ch. 1 - Prob. 1.58ECh. 1 - Use Figure 1.11 to construct the cyclic rule...Ch. 1 - Prob. 1.60ECh. 1 - Prob. 1.61ECh. 1 - Calculate for one mole of an ideal gas at STP and...Ch. 1 - Prob. 1.63ECh. 1 - Show that = T/p for an ideal gas.Ch. 1 - Determine an expression for V/T p, n in terms of ...Ch. 1 - Prob. 1.66ECh. 1 - Prob. 1.67ECh. 1 - Perform a units analysis on the exponent of the...Ch. 1 - Using the barometric formula, calculate the...Ch. 1 - The barometric formula can also be used for...Ch. 1 - Prob. 1.71ECh. 1 - Prob. 1.72ECh. 1 - Prob. 1.73ECh. 1 - Prob. 1.74ECh. 1 - Prob. 1.75ECh. 1 - Prob. 1.76ECh. 1 - Prob. 1.77ECh. 1 - Prob. 1.78ECh. 1 - Prob. 1.79ECh. 1 - Use the ideal gas law to symbolically prove the...Ch. 1 - Prob. 1.81E
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- Combustion of hydrocarbons such as decane ( C 10 H 22 ) produces carbon dioxide, a "greenhouse gas." Greenhouse gases in the Earth's atmosphere can trap the Sun's heat, raising the average temperature of the Earth. For this reason there has been a great deal of international discussion about whether to regulate the production of carbon dioxide. Suppose 0.270 kg of decane are burned in air at a pressure of exactly 1 atm and a temperature of 10 °C . Calculate the volume of carbon dioxide gas that is produced. Be sure your answer has 3 significant digits.arrow_forwardAll of the postulates of Kinetic Molecular Theory hold for ideal gases. True Falsearrow_forwardCalculate the amount of energy in the form of heat that is produced when a volume of 4.37 L of SO2(g) is converted to 4.37 L of SO3(g) according to this process at constant pressure and temperature of 1.00 bar and 25.0 ° C. Assume ideal gas behavior.arrow_forward
- This relationship is known as Graham’s Law of Effusion. Since both gases are at the same temperature, they must have the same average kinetic energy (½ mv2), where m is mass and v is velocity (like speed). Since both gases have the same average kinetic energy, you can state that ½ mLvL2 = ½ mHvH2. Multiplying both sides by 2 gives you mLvL2 = mHvH2. Rearranging the equation to get both masses on the same side of the equation will give you mL/mH = VH2/VL2. In 3a and 3b, you probably noticed that the heavy gas particles took twice as long to diffuse as the light gas particles. This means that the light gas particles are moving twice as fast, VH/VL = ½. Therefore, VH2/VL2 = ¼. If the light gas was Ne, what would be a reasonable identity for the heavy gas? Explain.arrow_forwardA sample of neon gas occupies a volume of 9.40 L at 53.0°C and 0.440 atm. If it is desired to decrease the volume of the gas sample to 7.44 L, while increasing its pressure to 0.540 atm, the temperature of the gas sample at the new volume and pressure must be | PC.arrow_forwardTA 50 cm3 sample of a gas in a syringe at 150C is heated to 500C and the syringe's piston is allowed to move outward against a constant atmospheric pressure. Calculate the new volume of the hot gas.arrow_forward
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