A molecular scale picture should be drawn to distinguish between alumina and silica and it should be stated if the picture is accurate of schematic. Concept introduction: Matter exists in three major states as solid, liquid, and gases. These states have various differences depending on their physical properties and the most important factor is their binding at molecular or atomic level. The difference in these states depends on the force of attraction between the molecules existing in the particular phase and their kinetic energies. The solids have more prominent crystal structures in comparison to liquid because of their regular arrangements. The molecular scale images are created with the help of nanotechnologies to show the microscopic arrangement of molecules in a given state.
A molecular scale picture should be drawn to distinguish between alumina and silica and it should be stated if the picture is accurate of schematic. Concept introduction: Matter exists in three major states as solid, liquid, and gases. These states have various differences depending on their physical properties and the most important factor is their binding at molecular or atomic level. The difference in these states depends on the force of attraction between the molecules existing in the particular phase and their kinetic energies. The solids have more prominent crystal structures in comparison to liquid because of their regular arrangements. The molecular scale images are created with the help of nanotechnologies to show the microscopic arrangement of molecules in a given state.
Solution Summary: The author explains that a molecular scale picture should be drawn to distinguish between the three major states of matter, namely solid, liquid, and gases.
A molecular scale picture should be drawn to distinguish between alumina and silica and it should be stated if the picture is accurate of schematic.
Concept introduction:
Matter exists in three major states as solid, liquid, and gases. These states have various differences depending on their physical properties and the most important factor is their binding at molecular or atomic level. The difference in these states depends on the force of attraction between the molecules existing in the particular phase and their kinetic energies.
The solids have more prominent crystal structures in comparison to liquid because of their regular arrangements. The molecular scale images are created with the help of nanotechnologies to show the microscopic arrangement of molecules in a given state.
Write balanced complete ionic equation for CaS(aq) +CdCl2 (aq)
→ CdS(s) + CaCl (aq).
Express your answer as a chemical equation. Identify all of the phases in your answer.
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At first, it seemed like the poisoned Russian agent might have ingested thallium in the form of thallium(I) sulfate, a rodenticide (rat poison), not allowed in the US and Western countries but still used in other countries. Thallium leads to hair loss. It also replaces potassium in important enzymes in the brain, muscles and skin. It takes 8.0 x 102 mg of thallium ion to kill an average adult. It took a bit of investigating to figure out that the agent was actually poisoned by polonium, a radioactive element, harmful only if it goes into the body. The radioactivity emitted by polonium, alpha particles, can be stopped by skin; but, if ingested, it gets into the blood stream, travels to organs and does lots of damage. The maximum safe body amount of polonium is 7 pg (picograms!) The agent was apparently poisoned with about 10 micrograms. To provide the minimum amount of thallium to kill the average adult, how many mL of 0.45 M solution of thallium(I) sulfate needs to be ingested?…
student found a bottle of unknown origin in the basement of an
"CAUTION—contains С₁H₁O.” No other
A
old house. The bottle was labelled
information was given, but inside the bottle were some white crystals.
The student took the bottle to a chemistry laboratory, where she analyzed the
crystals with the help of the laboratory staff. C₁2H₁6O reacted with Br₂ in CCl4
adding one mole of Br, and forming C₁₂H₁OB2₂.
When a sample of C₁₂H₂O was reacted with O3 followed by Zn/H₂O, two
different samples, J and K, were obtained. Compound J had a molecular formula
of C.HgO₂, and its NMR is shown below.
Compound K had a molecular formula of C₂H₂O, and it could be oxidized to
compound L, with a molecular formula of C₂H₂O₂. The IR spectrum of L showed
a very wide, strong band centred around 3000 cm*¹. The NMR spectrum of L
showed only two different absorptions: a doublet (6H) at 0.9 ppm and a septet
(1H) at 3.6 ppm. There was also a singlet (1H) off the scale at 11.8 ppm.
students, deduce possible…
Chapter 1 Solutions
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