Mathematics All Around (6th Edition)
Mathematics All Around (6th Edition)
6th Edition
ISBN: 9780134434681
Author: Tom Pirnot
Publisher: PEARSON
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Chapter 10.3, Problem 32E

In Exercises 25-32, we use the Hamilton method to do the apportionment.

The new states paradox.Redo Exercise 31, but now use the populations given below. Also assume that the original commission has 70 members.

State Population (thousands)
A 230
B 740
C 380
D 600

31.The new states paradox.Redo Exercise 29, but now use the populations given below. Also assume that the original commission has 56 members. Assume that A, B, and C are the original states and D is the new state.

State Population (thousands)
A 8,700
B 4,300
C 3,200
D 6,500

29.The new states paradox.Two states A and B have formed a 100-member commission to explore ways in which they can work jointly to improve the business climate in their states. The members will be apportioned to the commission according to the populations of the two states. After seeing the success of the commission, a third state asks to join and appoint members to the commission. States A and B agree and will allow state C to add as many members to the commission as they would deserve now using the current standard divisor. The populations of the three states are given below. Does this example illustrates the new states paradox? Explain.

State Population (thousands)
A 2,000
B 7,770
C 600
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Students have asked these similar questions
Solve the problem. Which apportionment method may produce the Alabama paradox? Jefferson Webster Adams O Hamilton
Consider the apportionment problem for College Town.   North: 5,100 South: 9,300 East: 6,800 West: 8,800     Suppose each council member is to represent approximately 3,000 citizens. Use Jefferson's assuming there must be 10 representatives.   N __________S__________ E__________ W __________ __________ __________ _________
Consider the small country of Tasmania with the three states and their population in the chart below. State A В C Total Population 161 250 489 900 Apportion 30 legislative seats using Hamilton's method. Increase the number of legislative seats to 31 and apportion the seats using Hamilton's method. Does the Alabama paradox occur? Which answer below best represents the problem? a. 30 seats; A has 6 seats, B has 8 seats, C has 16 seats. 31 seats; A has 5 seats, B has 8 seats, C has 17 seats. Yes, the Alabama paradox occurs because C gained a seat and A lost a seat. X b. 30 seats; A has 5 seats, B has 8 seats, C has 16 seats. 31 seats; A has 6 seats, B has 9 seats, C has 17 seats. Yes, the Alabama paradox occurs because B and C gained a seat and A lost a seat. c. 30 seats; A has 6 seats, B has 8 seats, C has 16 seats. 31 seats; A has 5 seats, B has 9 seats, C has 17 seats. Yes, the Alabama paradox occurs because B and C gained a seat and A lost a seat. d. 30 seats; A has 6 seats, B has 8…

Chapter 10 Solutions

Mathematics All Around (6th Edition)

Ch. 10.1 - Sharpening your Skills Recall that on a 10-member...Ch. 10.1 - Sharpening your Skills Redo Exercise 11 for Aroco...Ch. 10.1 - Sharpening your Skills Apportioning...Ch. 10.1 - Sharpening your Skills Apportioning...Ch. 10.1 - Applying What Youve Learned The Alabama paradox....Ch. 10.1 - Applying What Youve Learned The Alabama paradox....Ch. 10.1 - Applying What Youve Learned The Alabama paradox...Ch. 10.1 - Prob. 18ECh. 10.1 - Prob. 19ECh. 10.1 - Prob. 20ECh. 10.1 - Prob. 21ECh. 10.1 - Prob. 25ECh. 10.1 - Prob. 26ECh. 10.1 - Prob. 27ECh. 10.1 - Prob. 28ECh. 10.2 - Prob. 1ECh. 10.2 - Prob. 2ECh. 10.2 - Prob. 3ECh. 10.2 - Prob. 4ECh. 10.2 - Prob. 5ECh. 10.2 - Prob. 6ECh. 10.2 - Prob. 7ECh. 10.2 - Prob. 8ECh. 10.2 - Prob. 9ECh. 10.2 - Prob. 10ECh. 10.2 - Prob. 11ECh. 10.2 - Prob. 12ECh. 10.2 - Prob. 13ECh. 10.2 - Prob. 14ECh. 10.2 - Prob. 15ECh. 10.2 - Prob. 16ECh. 10.2 - Prob. 17ECh. 10.2 - Prob. 18ECh. 10.2 - Prob. 19ECh. 10.2 - Prob. 20ECh. 10.2 - Prob. 21ECh. 10.2 - Prob. 22ECh. 10.2 - Prob. 23ECh. 10.2 - Prob. 24ECh. 10.2 - Prob. 25ECh. 10.2 - Prob. 26ECh. 10.2 - Prob. 27ECh. 10.2 - Prob. 28ECh. 10.2 - Prob. 29ECh. 10.2 - Prob. 30ECh. 10.2 - Prob. 31ECh. 10.2 - Prob. 32ECh. 10.2 - Prob. 33ECh. 10.2 - Prob. 34ECh. 10.3 - In Exercises 1-4, we give you a total population,...Ch. 10.3 - Prob. 2ECh. 10.3 - In Exercises 1-4, we give you a total population,...Ch. 10.3 - Prob. 4ECh. 10.3 - Prob. 5ECh. 10.3 - Use the Jefferson method to assign the seats on...Ch. 10.3 - Prob. 7ECh. 10.3 - Prob. 8ECh. 10.3 - Choosing representatives on a negotiations...Ch. 10.3 - Prob. 10ECh. 10.3 - Prob. 11ECh. 10.3 - Use the Webster method to apportion the members of...Ch. 10.3 - Prob. 13ECh. 10.3 - Prob. 14ECh. 10.3 - Prob. 15ECh. 10.3 - Prob. 16ECh. 10.3 - Prob. 17ECh. 10.3 - Prob. 18ECh. 10.3 - Prob. 19ECh. 10.3 - Prob. 20ECh. 10.3 - Prob. 21ECh. 10.3 - Prob. 22ECh. 10.3 - Prob. 23ECh. 10.3 - Use the Webster method to assign the number of...Ch. 10.3 - Prob. 25ECh. 10.3 - Prob. 26ECh. 10.3 - Prob. 27ECh. 10.3 - In Exercises 25-32, we use the Hamilton method to...Ch. 10.3 - Prob. 29ECh. 10.3 - Prob. 30ECh. 10.3 - In Exercises 25-32, we use the Hamilton method to...Ch. 10.3 - In Exercises 25-32, we use the Hamilton method to...Ch. 10.3 - Exercises 33-36Illustrate that the Jefferson and...Ch. 10.3 - Prob. 34ECh. 10.3 - Prob. 35ECh. 10.3 - Prob. 36ECh. 10.3 - Prob. 37ECh. 10.3 - Prob. 38ECh. 10.3 - Prob. 39ECh. 10.3 - Prob. 40ECh. 10.3 - Prob. 43ECh. 10.3 - Prob. 44ECh. 10.3 - Prob. 45ECh. 10.3 - Prob. 46ECh. 10.3 - Prob. 47ECh. 10.4 - Identify each situation as dealing with either...Ch. 10.4 - Identify each situation as dealing with either...Ch. 10.4 - Use the method of sealed bids to complete the...Ch. 10.4 - Prob. 4ECh. 10.4 - Use the method of sealed bids to complete the...Ch. 10.4 - Prob. 6ECh. 10.4 - Prob. 7ECh. 10.4 - Prob. 8ECh. 10.4 - Prob. 9ECh. 10.4 - Use the method of sealed bids to complete the...Ch. 10.4 - Prob. 11ECh. 10.4 - Prob. 12ECh. 10.4 - Prob. 13ECh. 10.4 - Prob. 14ECh. 10.4 - Prob. 15ECh. 10.4 - In Exercises 15 and 16, use the method of sealed...Ch. 10.4 - Prob. 17ECh. 10.4 - Prob. 18ECh. 10.4 - Prob. 19ECh. 10.4 - Prob. 20ECh. 10.4 - Prob. 21ECh. 10.4 - Prob. 22ECh. 10.4 - Prob. 23ECh. 10.4 - Prob. 24ECh. 10.4 - Prob. 25ECh. 10.4 - Prob. 26ECh. 10.4 - Prob. 27ECh. 10.4 - Prob. 28ECh. 10.CR - Prob. 1CRCh. 10.CR - Prob. 2CRCh. 10.CR - Prob. 3CRCh. 10.CR - Prob. 4CRCh. 10.CR - Prob. 5CRCh. 10.CR - Prob. 6CRCh. 10.CR - Prob. 7CRCh. 10.CR - Prob. 8CRCh. 10.CR - Prob. 9CRCh. 10.CR - Prob. 10CRCh. 10.CR - Prob. 11CRCh. 10.CR - Prob. 12CRCh. 10.CR - Prob. 13CRCh. 10.CR - Prob. 14CRCh. 10.CR - Prob. 15CRCh. 10.CR - Prob. 16CRCh. 10.CT - What is the Alabama paradox?Ch. 10.CT - Suppose state C has a population of 1,640,000 and...Ch. 10.CT - The Metropolitan Community College Arts Council...Ch. 10.CT - Prob. 4CTCh. 10.CT - Suppose that Arizona has a population of 5.23...Ch. 10.CT - Prob. 6CTCh. 10.CT - Prob. 7CTCh. 10.CT - Prob. 8CTCh. 10.CT - Prob. 9CTCh. 10.CT - Prob. 10CTCh. 10.CT - Prob. 11CTCh. 10.CT - Prob. 12CTCh. 10.CT - Prob. 13CTCh. 10.CT - Prob. 14CTCh. 10.CT - Three brothersLarry, Moe, and Curlyare dissolving...
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