(a)
The
Answer to Problem 14.13P
The value of electric field
Explanation of Solution
Given:
The following information is given:
The radiation field
Calculation:
Using the condition
Conclusion:
The value of electric field
(b)
The
Answer to Problem 14.13P
The value of electric field
Explanation of Solution
Given:
The vertical current element location is
Concept Used:
Due to the change in the position of the vertical current element, there will be practically no change in the distance of P. However, this will enforce a change in the phase term which needs to be included in the overall electric field expression.
Calculation:
Consider two lines are drawn. One line is drawn from the origin to the point
The overall electric field will be obtained by using the modified result obtained in part (a) with the phase factor due to the path difference. The electric field will be,
Conclusion:
The value of electric field
(c)
The
Answer to Problem 14.13P
The value of electric field
Explanation of Solution
Given:
The radiation field
Identical vertical elements are located at
Concept Used:
Due to the presence of the element at
Overall electric field can be found by adding the contribution of
Calculation:
Since the phase angle of
Therefore, overall electric field will be,
Conclusion:
The value of electric field
Want to see more full solutions like this?
Chapter 14 Solutions
Engineering Electromagnetics
- Two antennas located at points A and B are broadcasting radio waves of frequency 96 MHz. The signals start in phase with each other. The two antennas are separated by a distance d=11.2 m. An observer is located at point P on the x axis, a distance x=97 m from antenna A. The points A, P and B form a right triangle. A) What is the phase difference between the waves arriving at P from antennas A and B? Enter your answer in radians (rad). 1.2957 rad (correct) B) Now observer P walks along the x axis toward antenna A. What is P's distance from A when they first observe fully constructive interference between the two waves? 20.0704 m (incorrect) C) If observer P continues walking until they reach antenna A, at how many places along the x axis (including the place you found in the previous problem) will they find maxima in the radio signal due to constructive interference? 4 (incorrect) Can you please help with parts B and C.arrow_forwardThe condition of circular polarization . * .... ..... O Ex=Ey O phase angle 90 Ex=Ey and phase angle =+90 or -90 Ex=Ey and phase angle =-180arrow_forwardElectromagnetics Given field V= 4y^2z+(3x^2/y). If E = gradV. Determine Ex at P(-6,-5,-1)arrow_forward
- Electromagnetics Given the field D =3zp cos(φ) aφ. Determine DivD at P(p=2.6, φ=1.9, z=-3)arrow_forward2. The E-field pattern (radiation intensity) of an antenna 0 < ø <360º, varies as follows: 0° < 0 < 45° 45° < 0 < 90° 90° < 0 < 180° 1 E = 2 (b) What is the radiation resistance of the antenna at 200 m from it if the electric field is equal to 10 V/m (rms) for 0=0• at that distance and the terminal current is 5 A (rms)?arrow_forwardQuèstion 3 The angle formed between A = 5ap+10a,+3az and surface z = 5 is 74.97 48.189 10 15.1 A Moving to another question will save this response.arrow_forward
- A dielectric material formed region one of x>0 with ɛr1=2.4 and region two is free space find Eland 01, 02 if D1 — 6ах 8аy + 12azarrow_forwardPlane y = 0 carries a uniform current of 30a, mA/m. At (1, 10, -2), the magnetic field intensity is (a) -15a, mA/m (d) 18.85a, nA/m (b) 15a, mA/m (e) None of the above (c) 477.5a, µA/marrow_forwardThe magnetic field along the propagation direction inside a rectangular waveguide with the cross section shown in the figure is H Z = 3 сos сos (80πx) сos сos (60пу) cos cos (2πx10¹⁰t - 2nz). Find the phase velocity Vp of the wave inside the waveguide.arrow_forward
- The azimuth angle is the angle between the intersection of the horizontal plane determine by the observer and the sun with the horizontal and horizontal line facing directly south from the observer O True O Falsearrow_forwardThe magnetic field along the propagation direction inside a rectangular waveguide with the cross section shown in the figure is H₂ = 3 cos (2.094x10²x) cos (2.618×10²y) cos(6.283×10¹0 t - Bz) 1 1.2 cm 3 cm X The phase velocity V₁ of the wave inside the waveguide satisfies (A) Vp > C (B) Vp = C (C) 0 < Vparrow_forwardIn free space " check image " Find the average power crossing a circular area of radius 2 meters in a plane ? = 0.arrow_forwardarrow_back_iosSEE MORE QUESTIONSarrow_forward_ios
- Introductory Circuit Analysis (13th Edition)Electrical EngineeringISBN:9780133923605Author:Robert L. BoylestadPublisher:PEARSONDelmar's Standard Textbook Of ElectricityElectrical EngineeringISBN:9781337900348Author:Stephen L. HermanPublisher:Cengage LearningProgrammable Logic ControllersElectrical EngineeringISBN:9780073373843Author:Frank D. PetruzellaPublisher:McGraw-Hill Education
- Fundamentals of Electric CircuitsElectrical EngineeringISBN:9780078028229Author:Charles K Alexander, Matthew SadikuPublisher:McGraw-Hill EducationElectric Circuits. (11th Edition)Electrical EngineeringISBN:9780134746968Author:James W. Nilsson, Susan RiedelPublisher:PEARSONEngineering ElectromagneticsElectrical EngineeringISBN:9780078028151Author:Hayt, William H. (william Hart), Jr, BUCK, John A.Publisher:Mcgraw-hill Education,