Organic Chemistry - Standalone book
Organic Chemistry - Standalone book
10th Edition
ISBN: 9780073511214
Author: Francis A Carey Dr., Robert M. Giuliano
Publisher: McGraw-Hill Education
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Chapter 15.9, Problem 7P
Interpretation Introduction

Interpretation:

The number of 4d electrons present in Pd2+ and the +2 ion in the fourth and the sixth period having the same number of 3d electrons as Pd2+ are to be determined

Concept Introduction:

The elements in group 3-12 are called d-block elements.

For d-block elements, the number of electrons in valence shell is same as the group number. The number of d-electrons is two less than the group number.

The first sequence of d-block elements starts with the element scandium which has one 3d-electron and continues to zinc which has ten 3d-electrons. The same trend holds true for the second (4d) and third (5d) sequence of d-block elements.

For the elements, in the same group, the number of valence electrons as well as d-electrons remains the same.

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Students have asked these similar questions
How many 4d electrons are there in Pd2+? What +2 ion in the fourth period has the same number of 3d electrons? In the sixth period?
Cr forms two monatomic ions, Cr²+ and Cr³t. From which sublevels do you expect electrons are lost in forming these ions? (Hint: It is possible for electrons other than those in the s and p sublevels to be involved in forming ions.) In forming the Cr*+ ion are: electron(s) lost from the 4s orbital? electron(s) lost from the 3d orbital? To support your answer, complete the following. It is OK to use the noble gas core notation. (Express your answer as a series of orbitals. For example, the electron configuration of Li would be entered in 1 complete form as 1s 2 2s or in condensed form as [He]2s '.) Electron configuration of Cr: Electron configuration of Cr2+:
How many valence electrons are there in group 2 elements? A 1 B 2 C4 D 8

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Organic Chemistry - Standalone book

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