(a)
To find: the probability that the researcher sells above 2000 cups of coffee in one week.
(a)
Answer to Problem 45E
1.63
Explanation of Solution
Given:
Cups of coffee
mean = 320 cups
standard deviation = 20 cups
Doughnut
mean = 150 doughnut
standard deviation = 12 doughnuts
Formula used:
Calculation:
To find the total coffee cups per week, the averages of 320 cups per day must be multiplied by 6 days in one week, when the shop is open.
To evaluate the standard deviation in cups within a week, the difference of doughnuts each week needs to be calculated by applying the square root of the standard deviatin for the six days that the shop has been opened.
For the standard deviation
For the z score
The table reveals that the 1.63 z-score is 0.9483 or 94.84% of the probability that fewer than 2,000 cups will go to the store. Thus, 0.0516 or 5.16 per cent (1 minus 94.84 per cent) is required to sell the shop over 2,000 cups of coffee a week
(b)
To Explain: that researcher can reasonably predict to has one day’s profit of above $300.
(b)
Explanation of Solution
Given:
Cups of coffee
mean = 320 cups
standard deviation = 20 cups
Doughnut
mean = 150 doughnut
standard deviation = 12 doughnuts
Calculation:
It is considered that 50 cents for each cup of coffee and 40 cents for every doughnut make a profit from the market. it has to decide if the shop is going to receive more than $300 a day. Second, as the number of coffee cup (c) and doughnuts (D) sales, it may convey the profit of the company.
Now, estimate the mean
Therefore, the standard deviation of profits must be measured using the profits equation and the variance squaring value per unit and the standard deviation between the two goods must be determined.
For the standard deviation
The estimated daily benefit is thus $220 and the standard deviation is $11.09.it would then infer that a day's profit of over $300 cannot be expected for the company, since there will be over seven standard deviations away from the average of $220.
(c)
To find: the probability that on any mention day researcher would sell one doughnut to greater than half of the coffee customers.
(c)
Explanation of Solution
Given:
Cups of coffee
mean = 320 cups
standard deviation = 20 cups
Doughnut
mean = 150 doughnut
standard deviation = 12 doughnuts
Calculation:
It was important to assess the probability that more than half of its coffee customers would buy a doughnut on every day store. The doughnut customers (D) and half of coffee clients (C) have to be subtracted in order to demonstrate the gap.
Difference = D- 0.5(C).
The difference must then be evaluated by means of the difference equation and the variation shall be estimated according to the standard deviation of the doughnut as well as of the coffee consumer. The difference between the two variables must then be determined by the total of the variances.
Chapter 16 Solutions
Stats: Modeling the World Nasta Edition Grades 9-12
Additional Math Textbook Solutions
Basic Business Statistics, Student Value Edition (13th Edition)
Fundamentals of Statistics (5th Edition)
Essentials of Statistics, Books a la Carte Edition (5th Edition)
Introductory Statistics (10th Edition)
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