Explanation Given: 1) A current i at time t which is producing magnetic field B is defined by following formula i ( t ) = 10 e − 0.1 t 2) Magnitude of produced magnetic field B is as follows B = μ 0 i 2 π r T Where μ 0 = 4 π × 10 − 7 T − m / A i = current passing through the wire r = distance of magnetic field from wire 3) The area through which the flux needs to be calculated is the isosceles triangle of base 12cm and height 6cm, whose bottom edge is 3cm from the wire. 4) Given figure is follows Formula used: 1) Flux of magnetic field is given by ϕ = ∬ S F . d S 2) Faraday’s law states that voltage drop around the closed surface can be determine by differentiation of flux with respect to time is Voltage drop = d ϕ d t 3) If A = ( x 1 , y 1 ) and B = ( x 2 , y 2 ) then equation of line A B is x − x 1 x 2 − x 1 = y − y 1 y 2 − y 1 Calculation: Flux ϕ ( t ) = ∬ S B . d S [using formula ϕ = ∬ S F . d S ] B = μ 0 i 2 π r [given] Area through which the flux needs to be calculated is isosceles triangle having base 12cm and height is 6cm. Assuming the wire is on x -axis following diagram is simplified version of fig 17 to get the characteristics of flux area Calculating equation of line OB and BA which will be use in further calculation, Equation of line OB is x − 0 6 − 0 = y − 3 9 − 3 [using formula x − x 1 x 2 − x 1 = y − y 1 y 2 − y 1 ] x 6 = y − 3 6 x + 3 = y Equation of line BA is x − 6 12 − 6 = y − 9 3 − 9 [using formula x − x 1 x 2 − x 1 = y − y 1 y 2 − y 1 ] x − 6 6 = y − 9 − 6 x + y = 15 Consider a strip on a triangle OAB, which is parallel to x -axis ϕ ( t ) = ∬ S B ...

4th Edition

ISBN: 9781319050733

Author: Rogawski

Publisher: MAC HIGHER

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Chapter 17.5, Problem 33E

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To Calculate:

The flux of magnetic field through particulars area, produced by current flowing through a straight wire and voltage drop around the triangular loop using Faraday’s law.

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Chapter 17.5, Problem 32E

Chapter 17.5, Problem 34E

Chapter 17 Solutions

CALCULUS (CLOTH)

Ch. 17.1 - Prob. 1PQ Ch. 17.1 - Prob. 2PQ Ch. 17.1 - Prob. 3PQ Ch. 17.1 - Prob. 4PQ Ch. 17.1 - Prob. 1E Ch. 17.1 - Prob. 2E Ch. 17.1 - Prob. 3E Ch. 17.1 - Prob. 4E Ch. 17.1 - Prob. 5E Ch. 17.1 - Prob. 6E

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Prob. 12E Ch. 17.5 - Prob. 13E Ch. 17.5 - Prob. 14E Ch. 17.5 - Prob. 15E Ch. 17.5 - Prob. 16E Ch. 17.5 - Prob. 17E Ch. 17.5 - Prob. 18E Ch. 17.5 - Prob. 19E Ch. 17.5 - Prob. 20E Ch. 17.5 - Prob. 21E Ch. 17.5 - Prob. 22E Ch. 17.5 - Prob. 23E Ch. 17.5 - Prob. 24E Ch. 17.5 - Prob. 25E Ch. 17.5 - Prob. 26E Ch. 17.5 - Prob. 27E Ch. 17.5 - Prob. 28E Ch. 17.5 - Prob. 29E Ch. 17.5 - Prob. 30E Ch. 17.5 - Prob. 31E Ch. 17.5 - Prob. 32E Ch. 17.5 - Prob. 33E Ch. 17.5 - Prob. 34E Ch. 17.5 - Prob. 35E Ch. 17.5 - Prob. 36E Ch. 17.5 - Prob. 37E Ch. 17.5 - Prob. 38E Ch. 17 - Prob. 1CRE Ch. 17 - Prob. 2CRE Ch. 17 - Prob. 3CRE Ch. 17 - Prob. 4CRE Ch. 17 - Prob. 5CRE Ch. 17 - Prob. 6CRE Ch. 17 - Prob. 7CRE Ch. 17 - Prob. 8CRE Ch. 17 - Prob. 9CRE Ch. 17 - Prob. 10CRE Ch. 17 - Prob. 11CRE Ch. 17 - Prob. 12CRE Ch. 17 - Prob. 13CRE Ch. 17 - Prob. 14CRE Ch. 17 - Prob. 15CRE Ch. 17 - Prob. 16CRE Ch. 17 - Prob. 17CRE Ch. 17 - Prob. 18CRE Ch. 17 - Prob. 19CRE Ch. 17 - Prob. 20CRE Ch. 17 - Prob. 21CRE Ch. 17 - Prob. 22CRE Ch. 17 - 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The flux of magnetic field through particulars area, produced by current flowing through a straight wire and voltage drop around the triangular loop using Faraday’s law.

Solution Summary: The author calculates the flux of magnetic field through particulars area, produced by current flowing through a straight wire and voltage drop around the triangular loop using Faraday's law.

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To Calculate: The flux of magnetic field through particulars area, produced by current flowing through a straight wire and voltage drop around the triangular loop using Faraday’s law.

Want to see the full answer?

Chapter 17 Solutions

To Calculate:

The flux of magnetic field through particulars area, produced by current flowing through a straight wire and voltage drop around the triangular loop using Faraday’s law.