(a)
The indicated ratios in lowest fractional form.
Answer to Problem 19A
The ratio of dimension A to dimension B is
Explanation of Solution
Given:
The given figure is as follows:
Concept used:
The dimension can be calculated by subtracting the distance of near hole from the one which is farther.
Calculation:
From the given figure, it is clear that the measure of dimension A is given by,
The measure of dimension B is given by,
The ratio of dimension A to dimension B is given by,
Thus, the ratio is
Conclusion:
The ratio of Dimension A to Dimension B is
(b)
The indicated ratios in lowest fractional form.
Answer to Problem 19A
The ratio of dimension A to dimension C is
Explanation of Solution
Given:
The given figure is as follows:
Concept used:
The dimension can be calculated by subtracting the distance of near hole from the one which is farther.
Calculation:
From the given figure, it is clear that the measure of dimension A is given by,
The measure of dimension C is given by,
The ratio of dimension A to dimension C is given by,
Thus, the ratio is
Conclusion:
The ratio of Dimension A to Dimension C is
(c)
The indicated ratios in lowest fractional form.
Answer to Problem 19A
The ratio of dimension C to dimension D is
Explanation of Solution
Given:
The given figure is as follows:
Concept used:
The dimension can be calculated by subtracting the distance of near hole from the one which is farther.
Calculation:
From the given figure, it is clear that the measure of dimension C is given by,
The measure of dimension D is given by,
The ratio of dimension C to dimension D is given by,
Thus, the ratio is
Conclusion:
The ratio of Dimension C to Dimension D is
(d)
The indicated ratios in lowest fractional form.
Answer to Problem 19A
The ratio of dimension C to dimension E is
Explanation of Solution
Given:
The given figure is as follows:
Concept used:
The dimension can be calculated by subtracting the distance of near hole from the one which is farther.
Calculation:
From the given figure, it is clear that the measure of dimension C is given by,
The measure of dimension E is given by,
The ratio of dimension C to dimension E is given by,
Thus, the ratio is
Conclusion:
The ratio of Dimension C to Dimension E is
(e)
The indicated ratios in lowest fractional form.
Answer to Problem 19A
The ratio of dimension D to dimension F is
Explanation of Solution
Given:
The given figure is as follows:
Concept used:
The dimension can be calculated by subtracting the distance of near hole from the one which is farther.
Calculation:
From the given figure, it is clear that the measure of dimension D is given by,
The measure of dimension F is given by,
The ratio of dimension D to dimension F is given by,
Thus, the ratio is
Conclusion:
The ratio of Dimension D to Dimension F is
(f)
The indicated ratios in lowest fractional form.
Answer to Problem 19A
The ratio of dimension F to dimension B is
Explanation of Solution
Given:
The given figure is as follows:
Concept used:
The dimension can be calculated by subtracting the distance of near hole from the one which is farther.
Calculation:
From the given figure, it is clear that the measure of dimension F is given by,
The measure of dimension B is given by,
The ratio of dimension F to dimension B is given by,
Thus, the ratio is
Conclusion:
The ratio of Dimension F to Dimension B is
(g)
The indicated ratios in lowest fractional form.
Answer to Problem 19A
The ratio of dimension F to dimension C is
Explanation of Solution
Given:
The given figure is as follows:
Concept used:
The dimension can be calculated by subtracting the distance of near hole from the one which is farther.
Calculation:
From the given figure, it is clear that the measure of dimension F is given by,
The measure of dimension C is given by,
The ratio of dimension F to dimension C is given by,
Thus, the ratio is
Conclusion:
The ratio of Dimension F to Dimension C is
(h)
The indicated ratios in lowest fractional form.
Answer to Problem 19A
The ratio of dimension E to dimension A is
Explanation of Solution
Given:
The given figure is as follows:
Concept used:
The dimension can be calculated by subtracting the distance of nearer hole from the one which is farther.
Calculation:
From the given figure, it is clear that the measure of dimension E is given by,
The measure of dimension A is given by,
The ratio of dimension E to dimension A is given by,
Thus, the ratio is
Conclusion:
The ratio of Dimension E to Dimension A is
(i)
The indicated ratios in lowest fractional form.
Answer to Problem 19A
The ratio of dimension D to dimension B is
Explanation of Solution
Given:
The given figure is as follows:
Concept used:
The dimension can be calculated by subtracting the distance the near hole from the one which is farther.
Calculation:
From the given figure, it is clear that the measure of dimension D is given by,
The measure of dimension B is given by,
The ratio of dimension D to dimension B is given by,
Thus, the ratio is
Conclusion:
The ratio of Dimension D to Dimension B is
(j)
The indicated ratios in lowest fractional form.
Answer to Problem 19A
The ratio of dimension C to dimension F is
Explanation of Solution
Given:
The given figure is as follows:
Concept used:
The dimension can be calculated by subtracting the distance of nearer hole from the one which is farther.
Calculation:
From the given figure, it is clear that the measure of dimension C is given by,
The measure of dimension F is given by,
The ratio of dimension C to dimension F is given by,
Thus, the ratio is
Conclusion:
The ratio of Dimension C to Dimension F is
Want to see more full solutions like this?
Chapter 20 Solutions
Mathematics For Machine Technology
- Find the decimal value of the distance C in Figure 10-3. Note the total unit value of the line.arrow_forwardFind the decimal value of the distance B in Figure 10-2. Note the total unit value of the line.arrow_forwardFind the decimal value of the distance A in Figure 10-1. Note the total unit value of the line.arrow_forward
- The length, L, of the point on any standard 118° included angle drill, as shown in Figure 12-5, can be calculated using the formula L=0.3 O where represents the diameter of the drill. Determine the lengths of the following drill points with the given diameters. Round to 3 decimal places for inches and 1 decimal place for millimeters. a. 12 b. 14 c. 38 d. 10 mm e. 25 mm f. 45 mmarrow_forwardFind the decimal value of each of the distances A, B, C, D, and E in Figure 97. Note the total unit value of the line. A=_B=_C=_D=_E=_arrow_forwardFind the decimal value of each of the distances A, B, C, D, and E in Figure 96. Note the total unit value of the lines. A=_B=_C=_D=_E=_arrow_forward
- Refer to the shaft shown in Figure 6-4. Determine the missing dimensions in the table using the dimensions given. All dimensions are in inches.arrow_forwardDetermine dimensions A, B, C, D, E, and F of the drill jig in Figure 35. All dimensions are in inches. A = ______. B = ______. C = ______. D = ______. E = ______. F = ______.arrow_forwardMeasure the lengths of dimensions a-f in Figure 30-25 to the nearer whole millimeter.arrow_forward
- Mathematics For Machine TechnologyAdvanced MathISBN:9781337798310Author:Peterson, John.Publisher:Cengage Learning,Glencoe Algebra 1, Student Edition, 9780079039897...AlgebraISBN:9780079039897Author:CarterPublisher:McGraw Hill