Concept explainers
(a)
To sketch: The graph of a polynomial function using leading coefficient test.
(a)
Explanation of Solution
Given information:
Graph:
By leading coefficient test:
As the x4is a leading variable and its coefficient is 1 which is a positive coefficient
And x is having even number as its degree.
So when the large numbers were taken than x4 will be dominating
For
For
The graph will be
(b)
To Find: polynomial function using the real values of zeroes.
(b)
Answer to Problem 84E
The curve will pass through -2, 0 and 2.
Explanation of Solution
Given information:
Graph:
The roots of the equation
The curve will pass through -2, 0 and 2.
(c)
To graph:Sketching the graph of a polynomial function
(c)
Explanation of Solution
Given information:
Graph:
Plotting points:
F(x) | x |
-3 | -1 |
0 | 0 |
-3 | 1 |
So the curve also passes through (-1,-3)(0,0)(1,-3)
(d)
To graph:Sketching the graph of a polynomial function.
(d)
Explanation of Solution
Given information:
Graph:
Continuous curve through the points
Points are:(-2,0)(-1.414,-4)(-1,-3)(0,0)(1,-3)(1.414,-4)(2,0)
Chapter 2 Solutions
PRECALCULUS W/LIMITS:GRAPH.APPROACH(HS)
- Calculus: Early TranscendentalsCalculusISBN:9781285741550Author:James StewartPublisher:Cengage LearningThomas' Calculus (14th Edition)CalculusISBN:9780134438986Author:Joel R. Hass, Christopher E. Heil, Maurice D. WeirPublisher:PEARSONCalculus: Early Transcendentals (3rd Edition)CalculusISBN:9780134763644Author:William L. Briggs, Lyle Cochran, Bernard Gillett, Eric SchulzPublisher:PEARSON
- Calculus: Early TranscendentalsCalculusISBN:9781319050740Author:Jon Rogawski, Colin Adams, Robert FranzosaPublisher:W. H. FreemanCalculus: Early Transcendental FunctionsCalculusISBN:9781337552516Author:Ron Larson, Bruce H. EdwardsPublisher:Cengage Learning