You find that a 25-F capacitor connected to 480 VAC is defective. The storeroom has no capacitors with a 480-VAC rating. However, you find two capacitors rated at 50 F and 370 VAC. Can these two capacitors be connected in such a manner that they can replace the defective capacitor? If yes, explain how they are connected and why the capacitors will not be damaged by the lower voltage rating. If no, explain why they cannot be used without damaging the capacitor.

List the five capacitor replacement rules.

A pure capacitive circuit is connected to a 480-volt, 60-Hz power source. An ammeter indicates a current flow of 24 amperes. The circuit current must be reduced to 16 amperes by connecting a second capacitor in series with the first. What is the value of the existing capacitor? What value capacitor should be connected in series with the original capacitor to limit the circuit current to 16 amperes?

Incandescent lighting of 500 W is connected in parallel with an inductive load. A clamp-on ammeter reveals a total circuit current of 7 A. What is the inductance of the load connected in parallel with the incandescent lights? Assume a voltage of 120 V and a frequency of 60 Hz.

Two capacitors having values of 80 F and 60 F are connected in series. What is the total capacitance?

The attached image shows a circuit with an AC voltage source, a resistor, inductor, and capacitor connected in series. The circuit has the following characteristics: Resistor resistance: 10 ohm Capacitor capacitance: 0.05 F Inductor inductance: 13 H Current Amplitude: 4 A Voltage amplitude across the source: 60 V Frequency at the source: 0.3 Hz Voltage amplitude across the resistor: 35 V Voltage amplitude across the capacitor: 37 V  Voltage amplitude across the inductor: 80 V  (a) Calculate the RMS voltages from the amplitudes above. From the RMS voltages across the capacitor, inductor and resistor, calculate the RMS voltage of the AC source. Hint: Vrms = V0/sqrt(2) Vrms = sqrt( (Vrms,R)2 + (Vrms, L - Vrms, C)2 ) (b) Calculate the RMS value of the current (c) Using the resistance, capacitance, inductance, and the frequency of the AC voltage, calculate the impedance Z. From this, and the previously measured value of Vrms, find the RMS value of the current in the circuit.

Calibri (Body) -11 by AaBbCcDx AaBbCcD AaBbC AaBbCc AaB AaBbCc. mat Painter BIU 1Normal 1No Spaci. Heading 1 Heading 2 Title Subtitle Chang Styles d Font Paragraph Styles IMPEDANCE QUIZ # 2 1. What capacitance when connected in series with a 500Q resistor will limit the current drawn from a 48-mV 465-kHz source to 20µA? * a. 144pF b. 145pF c. 146pF d. 147pF MY ANSWER: c.146pF 2. What is the total impedance at 20kHz of a series circuit consisting of a 1.5mH inductance, a 100Q resistance, and a 0.08uF capacitance? * a. 1340 41.7 b. 1930 L-37.2" C. 920 290 d. 530 2-12.6°

An RL series circuit is connected to a 240 volt 60 hz line the capacitor has current of 1.25 amperes flowling though it. the Xc of the inductor is 22 ohms. the resistor has a resistance of 16ohms. how much voltage is dropped across the resistor?

A elearning.adpoly.ac.ae * Question Completion Status: QUESTION 16 E-06, PC-02. Three inductors 15 mH, 15 mH and 15 mH are connected in parallel. What is the total inductance? O Without knowing the coupling factor the total inductance cannot be found. O 45mH. O5 mH. QUESTION 17 E-06, PC-04. The time constant in an inductive circuit is the time required for the current to reach? O 70.7% of maximum value. O 63,7% of maximum value. O 63,2% of maximum value. QUESTION 18 E-06, PC-01. When more than two inductors of different inductance are connected in parallel in a circuit, the total inductance is? O Less than the inductance of the lowest rated inductor. O Equal to the sum of the individual inductance. O Equal to the inductance of the highest rated inductor. QUESTION 19 E-06, PC-02, Three inductors 15 mH, 15 mH and 15 mH are connected in series, What is the total inductance? Click Saue and Submit to save and submit. Click Save All Answers to save all answers.