Advanced Mathematical Concepts: Precalculus with Applications, Student Edition
Advanced Mathematical Concepts: Precalculus with Applications, Student Edition
1st Edition
ISBN: 9780078682278
Author: McGraw-Hill, Berchie Holliday
Publisher: Glencoe/McGraw-Hill
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Chapter 2.7, Problem 5CFU

a.

To determine

To find:an inequality that represents the weight (in pounds) of packages carried by the truck.

a.

Expert Solution
Check Mark

Answer to Problem 5CFU

  25x+50y≤4200

Explanation of Solution

Given information:

Weight withstand by truck = 4200 pounds

Maximum weight of small package for delivery = 25 pounds

Maximum weight of large package for delivery = 50 pounds

The number of small packages and large packages are denoted by x and y respectively.

Calculation:

The inequality representing the weight (in pounds) of packages carried by the truck is 25x+50y≤4200 .

b.

To determine

To find: an inequality that represents the volume (in ft3 ) of packages carried by the truck.

b.

Expert Solution
Check Mark

Answer to Problem 5CFU

  3x+5y≤480

Explanation of Solution

Given information:

Volume of truck = 480ft3

Maximum volume of small package for delivery = 3ft3

Maximum volume of large package for delivery = 5ft3

The number of small packages and large packages are denoted by x and y respectively.

Calculation:

The inequality representing the volume of packages carried by the truck is 3x+5y≤480 .

c.

To determine

To graph: the system of inequalities.

c.

Expert Solution
Check Mark

Explanation of Solution

Given information:

The inequalities evaluated in part a. and b. are as follows:

  25x+50y≤4200

  3x+5y≤480

Calculation:

Each inequality has les than or equal to sign, so the graph of each inequality will have a solid line.

First create a table of values for 25x+50y=4200 and 3x+5y=480 as shown below.

    25x+50y=4200x01201685001000−1000
    y84240−166−416584
    3x+5y=480x060120160800−200
    y9660240−384216

Plot the points and join them with a straight line. Now test a point to shade the region that represents the solutions for both the inequalities as shown below.

    Test point25x+50y≤4200True / False
    (50,59)25(50)+50(59)≤42004200≤4200True
    (20,80)25(20)+50(80)≤42004500≤4200False
    Test point3x+5y≤480True / False
    (50,59)3(50)+5(59)≤480445≤480True
    (200,0)3(200)+5(0)≤480600≤480False

Nowshade the common region where the true point lies but remember the weight and volume cannot be negative. The graph of the given inequalities is shown below.

  Advanced Mathematical Concepts: Precalculus with Applications, Student Edition, Chapter 2.7, Problem 5CFU , additional homework tip 1

d.

To determine

To find: function that represents the amount (in $) of delivery service made on each truckload.

d.

Expert Solution
Check Mark

Answer to Problem 5CFU

  P(x,y)=5x+8y

Explanation of Solution

Given information:

Service charge for small package = $5

Service charge for large package = $8

The number of small packages and large packages are denoted by x and y respectively.

Calculation:

The function that representing the amount (in $) of delivery service made on each truckload is P(x,y)=5x+8y .

e.

To determine

To find: number of each type of package to be placed in order to maximize the revenue.

e.

Expert Solution
Check Mark

Answer to Problem 5CFU

Small packages = 160

Large packages = 0

Explanation of Solution

Given information:

The function evaluated in part d. for the maximum revenue is P(x,y)=5x+8y .

The graph drawn in part c. is shown below.

  Advanced Mathematical Concepts: Precalculus with Applications, Student Edition, Chapter 2.7, Problem 5CFU , additional homework tip 2

Calculation:

The vertices of shown in the graph are (0,84),(120,24) and (160,0) . Substitute the values in the function and test the vertices for the maximum value as shown below.

  P(0,84)=5(0)+8(84)=672P(120,24)=5(120)+8(24)=600+192=792P(160,0)=5(160)+8(0)=800

Since the value for x=160 and y=0 gives the maximum value of the function. Thus, the number of 160 small packages and 0 large package should be placed in order to maximize the revenue.

f.

To determine

To find: maximum revenue per truck.

f.

Expert Solution
Check Mark

Answer to Problem 5CFU

$800

Explanation of Solution

Given information:

The function evaluated in part d. for the maximum revenue is P(x,y)=5x+8y .

The graph drawn in part c. is shown below.

  Advanced Mathematical Concepts: Precalculus with Applications, Student Edition, Chapter 2.7, Problem 5CFU , additional homework tip 3

Calculation:

The vertices of shown in the graph are (0,84),(120,24) and (160,0) . Substitute the values in the function and test the vertices for the maximum value as shown below.

  P(0,84)=5(0)+8(84)=672P(120,24)=5(120)+8(24)=600+192=792P(160,0)=5(160)+8(0)=800

Since the value for x=160 and y=0 gives the maximum value of the function. Thus, the maximum revenue is $800.

g.

To determine

To explain: whether maximizing the revenue necessarily the best thing for the company to do.

g.

Expert Solution
Check Mark

Answer to Problem 5CFU

Probably not

Explanation of Solution

Given information:

The function evaluated in part d. for the maximum revenue is P(x,y)=5x+8y .

The graph drawn in part c. is shown below.

  Advanced Mathematical Concepts: Precalculus with Applications, Student Edition, Chapter 2.7, Problem 5CFU , additional homework tip 4

Calculation:

The vertices of shown in the graph are (0,84),(120,24) and (160,0) . Substitute the values in the function and test the vertices for the maximum value as shown below.

  P(0,84)=5(0)+8(84)=672P(120,24)=5(120)+8(24)=600+192=792P(160,0)=5(160)+8(0)=800

Since the value for x=160 and y=0 gives the maximum value of the function. Thus, the maximum revenue is $800 for delivering only small packages. But more realistically the company would choose to deliver each type of package in order to grow business and compete with other companies of same field.

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Chapter 2.7, Problem 4CFU
Next
Chapter 2.7, Problem 6CFU

Chapter 2 Solutions

Advanced Mathematical Concepts: Precalculus with Applications, Student Edition

Ch. 2.1 - Prob. 1CFUCh. 2.1 - Prob. 2CFUCh. 2.1 - Prob. 3CFUCh. 2.1 - Prob. 4CFUCh. 2.1 - Prob. 5CFUCh. 2.1 - Prob. 6CFUCh. 2.1 - Prob. 7CFUCh. 2.1 - Prob. 8CFUCh. 2.1 - Prob. 9CFUCh. 2.1 - Prob. 10CFU
Ch. 2.1 - Prob. 11ECh. 2.1 - Prob. 12ECh. 2.1 - Prob. 13ECh. 2.1 - Prob. 14ECh. 2.1 - Prob. 15ECh. 2.1 - Prob. 16ECh. 2.1 - Prob. 17ECh. 2.1 - Prob. 18ECh. 2.1 - Prob. 19ECh. 2.1 - Prob. 20ECh. 2.1 - Prob. 21ECh. 2.1 - Prob. 22ECh. 2.1 - Prob. 23ECh. 2.1 - Prob. 24ECh. 2.1 - Prob. 25ECh. 2.1 - Prob. 26ECh. 2.1 - Prob. 27ECh. 2.1 - Prob. 28ECh. 2.1 - Prob. 29ECh. 2.1 - Prob. 30ECh. 2.1 - Prob. 31ECh. 2.1 - Prob. 32ECh. 2.1 - Prob. 33ECh. 2.1 - Prob. 34ECh. 2.1 - Prob. 35ECh. 2.1 - Prob. 36ECh. 2.1 - Prob. 37ECh. 2.1 - Prob. 38ECh. 2.1 - Prob. 39ECh. 2.1 - Prob. 40ECh. 2.1 - Prob. 41ECh. 2.1 - Prob. 42ECh. 2.1 - Prob. 43ECh. 2.1 - Prob. 44ECh. 2.1 - Prob. 45ECh. 2.2 - Prob. 1CFUCh. 2.2 - Prob. 2CFUCh. 2.2 - Prob. 3CFUCh. 2.2 - Prob. 4CFUCh. 2.2 - Prob. 5CFUCh. 2.2 - Prob. 6CFUCh. 2.2 - Prob. 7CFUCh. 2.2 - Prob. 8ECh. 2.2 - Prob. 9ECh. 2.2 - Prob. 10ECh. 2.2 - Prob. 11ECh. 2.2 - Prob. 12ECh. 2.2 - Prob. 13ECh. 2.2 - Prob. 14ECh. 2.2 - Prob. 15ECh. 2.2 - Prob. 16ECh. 2.2 - Prob. 17ECh. 2.2 - Prob. 18ECh. 2.2 - Prob. 19ECh. 2.2 - Prob. 20ECh. 2.2 - Prob. 21ECh. 2.2 - Prob. 22ECh. 2.2 - Prob. 23ECh. 2.2 - Prob. 24ECh. 2.2 - Prob. 25ECh. 2.2 - Prob. 26ECh. 2.2 - Prob. 27ECh. 2.2 - Prob. 28ECh. 2.2 - Prob. 29ECh. 2.3 - Prob. 1CFUCh. 2.3 - Prob. 2CFUCh. 2.3 - Prob. 3CFUCh. 2.3 - Prob. 4CFUCh. 2.3 - Prob. 5CFUCh. 2.3 - Prob. 6CFUCh. 2.3 - Prob. 7CFUCh. 2.3 - Prob. 8CFUCh. 2.3 - Prob. 9CFUCh. 2.3 - Prob. 10CFUCh. 2.3 - Prob. 11CFUCh. 2.3 - Prob. 12CFUCh. 2.3 - Prob. 13CFUCh. 2.3 - Prob. 14CFUCh. 2.3 - Prob. 15ECh. 2.3 - Prob. 16ECh. 2.3 - Prob. 17ECh. 2.3 - Prob. 18ECh. 2.3 - Prob. 19ECh. 2.3 - Prob. 20ECh. 2.3 - Prob. 21ECh. 2.3 - Prob. 22ECh. 2.3 - Prob. 23ECh. 2.3 - Prob. 24ECh. 2.3 - Prob. 25ECh. 2.3 - Prob. 26ECh. 2.3 - Prob. 27ECh. 2.3 - Prob. 28ECh. 2.3 - Prob. 29ECh. 2.3 - Prob. 30ECh. 2.3 - Prob. 31ECh. 2.3 - Prob. 32ECh. 2.3 - Prob. 33ECh. 2.3 - Prob. 34ECh. 2.3 - Prob. 35ECh. 2.3 - Prob. 36ECh. 2.3 - Prob. 37ECh. 2.3 - Prob. 38ECh. 2.3 - Prob. 39ECh. 2.3 - Prob. 40ECh. 2.3 - Prob. 41ECh. 2.3 - Prob. 42ECh. 2.3 - Prob. 43ECh. 2.3 - Prob. 44ECh. 2.3 - Prob. 45ECh. 2.3 - Prob. 46ECh. 2.3 - Prob. 47ECh. 2.3 - Prob. 48ECh. 2.3 - Prob. 49ECh. 2.3 - Prob. 50ECh. 2.3 - Prob. 51ECh. 2.3 - Prob. 52ECh. 2.3 - Prob. 53ECh. 2.3 - Prob. 54ECh. 2.3 - Prob. 55ECh. 2.3 - Prob. 56ECh. 2.3 - Prob. 57ECh. 2.3 - Prob. 58ECh. 2.3 - Prob. 59ECh. 2.3 - Prob. 60ECh. 2.3 - Prob. 61ECh. 2.3 - Prob. 62ECh. 2.3 - Prob. 63ECh. 2.3 - Prob. 64ECh. 2.4A - Prob. 1GCECh. 2.4A - Prob. 2GCECh. 2.4A - Prob. 3GCECh. 2.4A - Prob. 4GCECh. 2.4A - Prob. 1MCQCh. 2.4A - Prob. 2MCQCh. 2.4A - Prob. 3MCQCh. 2.4A - Prob. 4MCQCh. 2.4A - Prob. 5MCQCh. 2.4A - Prob. 6MCQCh. 2.4A - Prob. 7MCQCh. 2.4A - Prob. 8MCQCh. 2.4A - Prob. 9MCQCh. 2.4A - Prob. 10MCQCh. 2.4 - Prob. 1CFUCh. 2.4 - Prob. 2CFUCh. 2.4 - Prob. 3CFUCh. 2.4 - Prob. 4CFUCh. 2.4 - Prob. 5CFUCh. 2.4 - Prob. 6CFUCh. 2.4 - Prob. 7CFUCh. 2.4 - Prob. 8CFUCh. 2.4 - Prob. 9CFUCh. 2.4 - Prob. 10CFUCh. 2.4 - Prob. 11ECh. 2.4 - Prob. 12ECh. 2.4 - Prob. 13ECh. 2.4 - Prob. 14ECh. 2.4 - Prob. 15ECh. 2.4 - Prob. 16ECh. 2.4 - Prob. 17ECh. 2.4 - Prob. 18ECh. 2.4 - Prob. 19ECh. 2.4 - Prob. 20ECh. 2.4 - Prob. 21ECh. 2.4 - Prob. 22ECh. 2.4 - Prob. 23ECh. 2.4 - Prob. 24ECh. 2.4 - Prob. 25ECh. 2.4 - Prob. 26ECh. 2.4 - Prob. 27ECh. 2.4 - Prob. 28ECh. 2.4 - Prob. 29ECh. 2.4 - Prob. 30ECh. 2.4 - Prob. 31ECh. 2.4 - Prob. 32ECh. 2.4 - Prob. 33ECh. 2.4 - Prob. 34ECh. 2.4 - Prob. 35ECh. 2.4 - Prob. 36ECh. 2.4 - Prob. 37ECh. 2.4 - Prob. 38ECh. 2.4 - Prob. 39ECh. 2.4 - Prob. 40ECh. 2.4 - Prob. 41ECh. 2.4 - Prob. 42ECh. 2.5 - Prob. 1CFUCh. 2.5 - Prob. 2CFUCh. 2.5 - Prob. 3CFUCh. 2.5 - Prob. 4CFUCh. 2.5 - Prob. 5CFUCh. 2.5 - Prob. 6CFUCh. 2.5 - Prob. 7CFUCh. 2.5 - Prob. 8CFUCh. 2.5 - Prob. 9CFUCh. 2.5 - Prob. 10CFUCh. 2.5 - Prob. 11CFUCh. 2.5 - Prob. 12CFUCh. 2.5 - Prob. 13CFUCh. 2.5 - Prob. 14ECh. 2.5 - Prob. 15ECh. 2.5 - Prob. 16ECh. 2.5 - Prob. 17ECh. 2.5 - Prob. 18ECh. 2.5 - Prob. 19ECh. 2.5 - Prob. 20ECh. 2.5 - Prob. 21ECh. 2.5 - Prob. 22ECh. 2.5 - Prob. 23ECh. 2.5 - Prob. 24ECh. 2.5 - Prob. 25ECh. 2.5 - Prob. 26ECh. 2.5 - Prob. 27ECh. 2.5 - Prob. 28ECh. 2.5 - Prob. 29ECh. 2.5 - Prob. 30ECh. 2.5 - Prob. 31ECh. 2.5 - Prob. 32ECh. 2.5 - Prob. 33ECh. 2.5 - Prob. 34ECh. 2.5 - Prob. 35ECh. 2.5 - Prob. 36ECh. 2.5 - Prob. 37ECh. 2.5 - Prob. 38ECh. 2.5 - Prob. 39ECh. 2.5 - Prob. 40ECh. 2.5 - Prob. 41ECh. 2.5 - Prob. 42ECh. 2.5 - Prob. 43ECh. 2.5 - Prob. 44ECh. 2.5 - Prob. 45ECh. 2.5 - Prob. 46ECh. 2.5 - Prob. 47ECh. 2.5 - Prob. 48ECh. 2.5 - Prob. 49ECh. 2.5 - Prob. 50ECh. 2.5 - Prob. 51ECh. 2.5 - Prob. 52ECh. 2.5 - Prob. 53ECh. 2.5 - Prob. 54ECh. 2.5 - Prob. 55ECh. 2.5 - Prob. 56ECh. 2.5 - Prob. 57ECh. 2.5 - Prob. 58ECh. 2.5 - Prob. 59ECh. 2.5 - Prob. 60ECh. 2.5 - Prob. 61ECh. 2.5 - Prob. 62ECh. 2.5B - Prob. 1GCECh. 2.5B - Prob. 2GCECh. 2.5B - Prob. 3GCECh. 2.5B - Prob. 4GCECh. 2.5B - Prob. 5GCECh. 2.6 - Prob. 1CFUCh. 2.6 - Prob. 2CFUCh. 2.6 - Prob. 3CFUCh. 2.6 - Prob. 4CFUCh. 2.6 - Prob. 5CFUCh. 2.6 - Prob. 6CFUCh. 2.6 - Prob. 7CFUCh. 2.6 - Prob. 8CFUCh. 2.6 - Prob. 9ECh. 2.6 - Prob. 10ECh. 2.6 - Prob. 11ECh. 2.6 - Prob. 12ECh. 2.6 - Prob. 13ECh. 2.6 - Prob. 14ECh. 2.6 - Prob. 15ECh. 2.6 - Prob. 16ECh. 2.6 - Prob. 17ECh. 2.6 - Prob. 18ECh. 2.6 - Prob. 19ECh. 2.6 - Prob. 20ECh. 2.6 - Prob. 21ECh. 2.6 - Prob. 22ECh. 2.6 - Prob. 23ECh. 2.6 - Prob. 24ECh. 2.6 - Prob. 25ECh. 2.6 - Prob. 26ECh. 2.6 - Prob. 27ECh. 2.6 - Prob. 28ECh. 2.6 - Prob. 29ECh. 2.6 - Prob. 30ECh. 2.6 - Prob. 31ECh. 2.6 - Prob. 32ECh. 2.6 - Prob. 33ECh. 2.7 - Prob. 1CFUCh. 2.7 - Prob. 2CFUCh. 2.7 - Prob. 3CFUCh. 2.7 - Prob. 4CFUCh. 2.7 - Prob. 5CFUCh. 2.7 - Prob. 6CFUCh. 2.7 - Prob. 7CFUCh. 2.7 - Prob. 8CFUCh. 2.7 - Prob. 9ECh. 2.7 - Prob. 10ECh. 2.7 - Prob. 11ECh. 2.7 - Prob. 12ECh. 2.7 - Prob. 13ECh. 2.7 - Prob. 14ECh. 2.7 - Prob. 15ECh. 2.7 - Prob. 16ECh. 2.7 - Prob. 17ECh. 2.7 - Prob. 18ECh. 2.7 - Prob. 19ECh. 2.7 - Prob. 20ECh. 2.7 - Prob. 21ECh. 2.7 - Prob. 22ECh. 2.7 - Prob. 23ECh. 2.7 - Prob. 24ECh. 2.7 - Prob. 25ECh. 2.7 - Prob. 26ECh. 2.7 - Prob. 27ECh. 2.7 - Prob. 28ECh. 2 - Prob. 1SGACh. 2 - Prob. 2SGACh. 2 - Prob. 3SGACh. 2 - Prob. 4SGACh. 2 - Prob. 5SGACh. 2 - Prob. 6SGACh. 2 - Prob. 7SGACh. 2 - Prob. 8SGACh. 2 - Prob. 9SGACh. 2 - Prob. 10SGA

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