Physics: Principles with Applications
Physics: Principles with Applications
6th Edition
ISBN: 9780130606204
Author: Douglas C. Giancoli
Publisher: Prentice Hall
Question
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Chapter 29, Problem 25P
To determine

The amount of current flows in the circuit.

Expert Solution & Answer
Check Mark

Answer to Problem 25P

  13mA .

Explanation of Solution

Given:

Resistor, R=0.100kΩ

Voltage of battery, Vbattery=2V

Formula used:

It is known that: Vbattery=Vdiode+VR

Where,

  Vdiode is the voltage of diode.

  VR is the voltage at resistor.

  Vbattery is the voltage of battery.

Calculation:

The voltage of battery is Vbattery=Vdiode+VR

  2.0V=V(I)+I(0.100kΩ)

  V(I)=2.0V-I(0.100kΩ)

This straight line passes through (20mA,0V)&(12mA,0.8V) , as drawn in figure.

  Physics: Principles with Applications, Chapter 29, Problem 25P

As V(I) is denoted by both curves, the intersection point will give the current.

Hence, the current is 13mA .

Conclusion: The required current is 13mA .

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