Interpretation:
The pair of combination that produces a greater mass of the solid product is to be determined.
Concept introduction:
In a precipitation reaction, two ionic compounds in a solution react to form an insoluble compound, which is called the precipitate.
The formation of the precipitate can be predicted by using solubility rules.
The mass of the precipitate can be determined from the stoichiometry of the reaction.
Answer to Problem 91QP
Solution:
(a) Combination 1
(b) Combination 2
(c) Combination 2
Explanation of Solution
a)
Combination 1:
Combination 2:
In Combination 1:
The precipitation reaction between lead nitrate and potassium chloride is as follows:
From the above balanced equation, one mole of
First, calculate the number of moles of
Now, calculate the number of moles of KCl.
Hence, KCl is a limiting reagent that determines the amount of
Convert moles to grams by multiplying the moles with the molar mass of
Hence, the mass of the
In Combination 2,
Calculate the number of moles of
Now, calculate the number of moles of KCl.
KCl is a limiting reagent that determines the amount of
Now convert the number of moles to grams by multiplying the number of moles with the molar mass of PbCl2
Hence, the mass of the PbCl2 formed is
Therefore, combination 1 will produce a greater mass of the product.
b)
Combination 1:
Combination 2:
Combination 1:
The precipitation reaction between sodium phosphate and calcium nitrate is as follows:
From the above balanced equation, two moles of
First, calculate the number of moles of Na3PO4 using the given volume and concentration:
Now, calculate the number of moles of
Here, Na3PO4 is a limiting reagent that determines the amount of product formed.
Convert the number of moles to grams by multiplying the number of moles with the molar mass of
Hence, the mass of the
Combination 2:
Calculate the number of moles of
Now, calculate the number of moles of
Here,
Convert the number of moles to grams by multiplying the number of moles with the molar mass of
Hence, the mass of the
Therefore, combination 2 produces a greater mass of the product.
c)
Combination 1:
Combination 2:
Combination 1:
The precipitation reaction between silver nitrate and barium chloride is as follows:
From the above balanced equation, one mole of BaCl2 reacts with two moles of
First, calculate the number of moles of
Now, calculate the number of moles of
Hence,
Convert the number of moles to grams by multiplying the number of moles with the molar mass of AgCl:
Hence, the mass of the AgCl formed is
Combination 2:
Calculate the number of moles of BaCl2 using the given volume and concentration:
Now, calculate the number of moles of AgNO3.
Hence,
Convert the number of moles to grams by multiplying the number of moles with the molar mass of AgCl:
Hence, the mass of the AgCl formed is
Therefore, combination 2 produces a greater mass of the product.
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Chapter 4 Solutions
Chemistry
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