Physics for Scientists and Engineers with Modern Physics
10th Edition
ISBN: 9781337553292
Author: Raymond A. Serway, John W. Jewett
Publisher: Cengage Learning
expand_more
expand_more
format_list_bulleted
Question
Chapter 42, Problem 2P
To determine
The ionization energy of potassium.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
The density of potassium, which has the FCC
structure and one atom per lattice point, is
0.855 g/cm3. The atomic weight of potassium
is 39.09 g/mole and Avogadro's number, NA=
6.02*1023 atom/mol. The lattice parameter for
this structure is equal to:
O a. a,= 6.7223*10 8 cm
O b. ao= 5.6355*108 cm
O c. a,= 6.3355*108 cm
O d. ao= 5.3355*10 8 cm
The gap between valence and conduction bands in silicon is 1.12 eV. A nickel nucleus in an excited state emits a gamma-ray photon with wavelength 9.31 * 10-4 nm. How many electrons can be excited from the top of the valence band to the bottom of the conduction band by the absorption of this gamma ray?
A sample of copper has a mass of 10.68 g when measured in air. It has a mass of 9.47 g when measured in water.
Answer these three questions:
How many atoms are in the sample?
What is the simple volume of the space including and surrounding each atom? Assume the atoms are evenly distributed throughout the sample. That is no FCC, BCC, or HCP crystal structure.
What is the diameter of each atom?
Chapter 42 Solutions
Physics for Scientists and Engineers with Modern Physics
Ch. 42.1 - For each of the following atoms or molecules,...Ch. 42.2 - Prob. 42.2QQCh. 42.2 - Prob. 42.3QQCh. 42 - Prob. 1PCh. 42 - Prob. 2PCh. 42 - Prob. 3PCh. 42 - Prob. 4PCh. 42 - Prob. 5PCh. 42 - The photon frequency that would be absorbed by the...Ch. 42 - Prob. 8P
Ch. 42 - Prob. 9PCh. 42 - Prob. 10PCh. 42 - (a) In an HCl molecule, take the Cl atom to be the...Ch. 42 - Prob. 12PCh. 42 - Prob. 13PCh. 42 - Prob. 14PCh. 42 - Prob. 15PCh. 42 - Prob. 16PCh. 42 - Prob. 17PCh. 42 - Prob. 19PCh. 42 - Prob. 21PCh. 42 - Prob. 22PCh. 42 - Prob. 23PCh. 42 - Prob. 24PCh. 42 - Prob. 25PCh. 42 - Prob. 26PCh. 42 - Prob. 27PCh. 42 - Prob. 28PCh. 42 - Prob. 29PCh. 42 - Prob. 30PCh. 42 - Prob. 32PCh. 42 - Prob. 33PCh. 42 - Prob. 35PCh. 42 - Prob. 36APCh. 42 - Prob. 37APCh. 42 - Prob. 39APCh. 42 - Prob. 40APCh. 42 - As an alternative to Equation 42.1, another useful...
Knowledge Booster
Similar questions
- The measured density of a NaF crystal is 2.558 g/cm3 . What is the equilibrium separate distance of Na+ and Flions?arrow_forward(a) In an HCl molecule, take the Cl atom to be the isotope 35Cl. The equilibrium separation of the H and Cl atoms is 0.127 46 nm. The atomic mass of the H atom is 1.007 825 u and that of the 35Cl atom is 34.968 853 u. Calculate the longest wavelength in the rotational spectrum of this molecule. (b) What If? Repeat the calculation in part (a), but take the Cl atom to be the isotope 37Cl, which has atomic mass 36.965 903 u. The equilibrium separation distance is the same as in part (a). (c) Naturally occurring chlorine contains approximately three parts of 35Cl to one part of 37Cl. Because of the two different Cl masses, each line in the microwave rotational spectrum of HCl is split into a doublet as shown in Figure P42.11. Calculate the separation in wavelength between the doublet lines for the longest wavelength.arrow_forwardCalculate the radius of a nickel atom in cm, given that Ni has an FCC crystal structure, a density of 7.982 g/cm³, and an atomic weight of 58.69 g/mol.arrow_forward
- A silicon p-n junction consists of a p-type region containing 3x1016 cm-3 acceptors and an n- type region containing also 1017 cm-3 donors. a. Calculate the density of electrons and holes in both p-type and n-type regions under thermal equilibrium at room temperature. b. Calculate the built-in potential of the p-n junction? c. Calculate the width of the depletion layer under a reverse bias of 1.0 V. d. Based on c, calculate the junction capacitance. Note that the junction cross-session area is 1.2 mm2.arrow_forwardP-type semi conducting material is Select one: a. holes are majority charge carriers and it is due to addition of trivalent impurities. O b. electrons are majority charge carriers and it is due to addition of trivalent impurities. O c. holes are minority charge carriers and it is due to addition of pentavalent impurities. Od. electrons are majority charge carriers and it is due to addition of pentavalent impurities.arrow_forwardPlot the electron distribution function N(E) versus energy in a metal at (a) T = 0 K and (b) T = 300 K.arrow_forward
- For a K*- CH ion pair, attractive and repulsive energies EA and ER, respectively, depend on the distance between the ions r, according to 5.8 x 10-6 1.436 EA and ER For these expressions, energies are expressed in electron volts per K*- CH pair, and r is the distance in nanometers. a) If the net energy EN is just the sum of the two expressions above: EN = E, + ER, Find the values of ro and E, ? b) If curves of E, ER, and EN are plotted in given figure, compare the calculated values of ro and E, with that from the graph. 2 am 0.00 010 0.20 0.30 040 0.70 00 1.00 Interatomic Separation, nm Bonding Energy, eVarrow_forwardYou are preparing to compete in the Physics Olympics. Your instructor is coaching you by providing you with challenging problems of the type you might see on an Olympics exam. He comes up with the following problem and gives you 15 minutes to solve it: Imagine a perfectly rigid HCl molecule that does not stretch as it rotates. The equilibrium separation of its ions is 0.127 5 nm. There are two isotopes for chlorine on the sample, Cl-35 and Cl-37. This results in double peaks in the molecular spectrum as shown. (a) Find an expression for the difference in the frequency between the peaks to the right of the gap as a function of the masses of the two chlorine isotopes and the quantum number J. (b) Estimate the difference in frequency numerically for J = 0, without consulting tables. Quick! Get to work!arrow_forwardSilicon atoms with a concentration of 7x 1010 cm are added to gallium arsenide GaAs at T = 400 K. Assume that the silicon atoms act as fully ionized dopant atoms and that 15% of the concentration added replaces gallium atoms to free electrons and 85% replaces arsenic to create holes. Use the following parameters for GaAs at T = 300 K: N. = 4.7 x 1017cm-3 and N, = 7 x 1018 cm-3. The bandgap is E, = 1.42 eV and it is constant over the temperature range. The intrinsic concentration?arrow_forward
- Graph below shows the electron occupancy probability P(E) as a function of energy for Bismuth (mBi = 3.47 × 10-25 kg) at the temperature T = 0 K. What is the number of conduction electrons per unit volume for Bismuth? 1 1 2 3 4 5 6 7 8 E (ev) P(E)arrow_forwardA:08 الرسائل المحفو. . . 1 03: Rhenium has a Hexagonal Close-Packed crystal structure with an atomic radius of 0.137 nm and a ratio c/a of 1.615, compute: a) The volume of the unit cell. b) The theoretical density c) Atomic packing factor Note: Avogadro's' number = 6.023×10²³ Atomic weight = 186.21 g/mol إضافة وصف.. . IIIarrow_forwardThe forbidden energy bandgap of AIP is 2.43 eV. Determine the wavelength (in nm) of an incident photon that can interact with a valence electron and elevate the electron into the conduction band. Oλ = 511 nm Oλ = 419 nm O λ = 882 nm λ = 575 nmarrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Physics for Scientists and Engineers with Modern ...PhysicsISBN:9781337553292Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
University Physics Volume 3PhysicsISBN:9781938168185Author:William Moebs, Jeff SannyPublisher:OpenStax
Modern PhysicsPhysicsISBN:9781111794378Author:Raymond A. Serway, Clement J. Moses, Curt A. MoyerPublisher:Cengage Learning
Physics for Scientists and Engineers with Modern ...
Physics
ISBN:9781337553292
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
University Physics Volume 3
Physics
ISBN:9781938168185
Author:William Moebs, Jeff Sanny
Publisher:OpenStax
Modern Physics
Physics
ISBN:9781111794378
Author:Raymond A. Serway, Clement J. Moses, Curt A. Moyer
Publisher:Cengage Learning