PRECALCULUS:GRAPHICAL,...-NASTA ED.
PRECALCULUS:GRAPHICAL,...-NASTA ED.
10th Edition
ISBN: 9780134672090
Author: Demana
Publisher: PEARSON
Expert Solution & Answer
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Chapter 4.6, Problem 72E
Solution

(a)

To calculate : The company's sales in 2012.

The company's sales in 2012 is 105 million dollars.

Given information :

The business manager of a small manufacturing company finds that she can model the company's annual growth as roughly exponential but with cyclical fluctuations. She uses the function St=1051.04t+4sinπt3 to estimate sales (in million of dollars), t years after 2012.

Calculation :

Consider the given function St=1051.04t+4sinπt3 .

To estimate the company's sales in 2012, substitute t=0 .

  S0=1051.040+4sinπ03=105+4sin0=105

Therefore, the sales in 2012 is 105 million dollars.

(b)

To calculate : The approximate annual growth rate.

The approximate annual growth rate is 7.66 million dollars.

Given information :

The business manager of a small manufacturing company finds that she can model the company's annual growth as roughly exponential but with cyclical fluctuations. She uses the function St=1051.04t+4sinπt3 to estimate sales (in million of dollars), t years after 2012.

Calculation :

Consider the given function St=1051.04t+4sinπt3 .

To estimate the growth rate, find the company's sales in 2013 and for this substitute t=1 .

  S0=1051.041+4sinπ13=109.2+4sinπ3=109.2+432=112.66

Thus the growth rate is,

  =112.661051=7.66

Therefore, the annual growth rate is 7.66 million dollars.

(c)

To calculate : The sales for 2020.

The sales for 2020 is 147.16 million dollars.

Given information :

The business manager of a small manufacturing company finds that she can model the company's annual growth as roughly exponential but with cyclical fluctuations. She uses the function St=1051.04t+4sinπt3 to estimate sales (in million of dollars), t years after 2012.

Calculation :

Consider the given function St=1051.04t+4sinπt3 .

To find the company's sales in 2020 and for this substitute t=8 .

  S0=1051.048+4sinπ83=143.70+4sin8π3=143.70+3.46=147.16

Therefore, the sales in 2020 is 147.16 million dollars.

(d)

To calculate : The number of years in each economic cycle.

The number of years in each economic cycle is 6 .

Given information :

The business manager of a small manufacturing company finds that she can model the company's annual growth as roughly exponential but with cyclical fluctuations. She uses the function St=1051.04t+4sinπt3 to estimate sales (in million of dollars), t years after 2012.

Calculation :

Consider the given function St=1051.04t+4sinπt3 .

The period of the model function is same as sinπt3 .

The period of the function asinbx+c+d is 2πb .

So, the period of sinπt3 is 2ππ3=6 .

Therefore, the number of years in each economic cycle is 6 .

Chapter 4 Solutions

PRECALCULUS:GRAPHICAL,...-NASTA ED.

Ch. 4.1 - Prob. 1ECh. 4.1 - Prob. 2ECh. 4.1 - Prob. 3ECh. 4.1 - Prob. 4ECh. 4.1 - Prob. 5ECh. 4.1 - Prob. 6ECh. 4.1 - Prob. 7ECh. 4.1 - Prob. 8ECh. 4.1 - Prob. 9ECh. 4.1 - Prob. 10ECh. 4.1 - Prob. 11ECh. 4.1 - Prob. 12ECh. 4.1 - Prob. 13ECh. 4.1 - Prob. 14ECh. 4.1 - Prob. 15ECh. 4.1 - Prob. 16ECh. 4.1 - Prob. 17ECh. 4.1 - Prob. 18ECh. 4.1 - Prob. 19ECh. 4.1 - Prob. 20ECh. 4.1 - Prob. 21ECh. 4.1 - Prob. 22ECh. 4.1 - Prob. 23ECh. 4.1 - Prob. 24ECh. 4.1 - Prob. 25ECh. 4.1 - Prob. 26ECh. 4.1 - Prob. 27ECh. 4.1 - Prob. 28ECh. 4.1 - Prob. 29ECh. 4.1 - Prob. 30ECh. 4.1 - Prob. 31ECh. 4.1 - Prob. 32ECh. 4.1 - Prob. 33ECh. 4.1 - Prob. 34ECh. 4.1 - Prob. 35ECh. 4.1 - Prob. 36ECh. 4.1 - Prob. 37ECh. 4.1 - Prob. 38ECh. 4.1 - Prob. 39ECh. 4.1 - Prob. 40ECh. 4.1 - Prob. 41ECh. 4.1 - Prob. 42ECh. 4.1 - Prob. 43ECh. 4.1 - Prob. 44ECh. 4.1 - Prob. 45ECh. 4.1 - Prob. 46ECh. 4.1 - Prob. 47ECh. 4.1 - Prob. 48ECh. 4.1 - Prob. 49ECh. 4.1 - Prob. 50ECh. 4.1 - Prob. 51ECh. 4.1 - Prob. 52ECh. 4.1 - Prob. 53ECh. 4.1 - 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Prob. 37ECh. 4.7 - Prob. 38ECh. 4.7 - Prob. 39ECh. 4.7 - Prob. 40ECh. 4.7 - Prob. 41ECh. 4.7 - Prob. 42ECh. 4.7 - Prob. 43ECh. 4.7 - Prob. 44ECh. 4.7 - Prob. 45ECh. 4.7 - Prob. 46ECh. 4.7 - Prob. 47ECh. 4.7 - Prob. 48ECh. 4.7 - Prob. 49ECh. 4.7 - Prob. 50ECh. 4.7 - Prob. 51ECh. 4.7 - Prob. 52ECh. 4.7 - Prob. 53ECh. 4.7 - Prob. 54ECh. 4.7 - Prob. 55ECh. 4.7 - Prob. 56ECh. 4.7 - Prob. 57ECh. 4.7 - Prob. 58ECh. 4.7 - Prob. 59ECh. 4.7 - Prob. 60ECh. 4.7 - Prob. 61ECh. 4.7 - Prob. 62ECh. 4.7 - Prob. 63ECh. 4.7 - Prob. 64ECh. 4.7 - Prob. 65ECh. 4.7 - Prob. 66ECh. 4.7 - Prob. 67ECh. 4.7 - Prob. 68ECh. 4.7 - Prob. 69ECh. 4.7 - Prob. 70ECh. 4.7 - Prob. 71ECh. 4.7 - Prob. 72ECh. 4.8 - Prob. 1QRCh. 4.8 - Prob. 2QRCh. 4.8 - Prob. 3QRCh. 4.8 - Prob. 4QRCh. 4.8 - Prob. 5QRCh. 4.8 - Prob. 6QRCh. 4.8 - Prob. 7QRCh. 4.8 - Prob. 8QRCh. 4.8 - Prob. 9QRCh. 4.8 - Prob. 10QRCh. 4.8 - Prob. 1ECh. 4.8 - Prob. 2ECh. 4.8 - Prob. 3ECh. 4.8 - Prob. 4ECh. 4.8 - Prob. 5ECh. 4.8 - Prob. 6ECh. 4.8 - Prob. 7ECh. 4.8 - Prob. 8ECh. 4.8 - Prob. 9ECh. 4.8 - Prob. 10ECh. 4.8 - Prob. 11ECh. 4.8 - Prob. 12ECh. 4.8 - Prob. 13ECh. 4.8 - Prob. 14ECh. 4.8 - Prob. 15ECh. 4.8 - Prob. 16ECh. 4.8 - Prob. 17ECh. 4.8 - Prob. 18ECh. 4.8 - Prob. 19ECh. 4.8 - Prob. 20ECh. 4.8 - Prob. 21ECh. 4.8 - Prob. 22ECh. 4.8 - Prob. 23ECh. 4.8 - Prob. 24ECh. 4.8 - Prob. 25ECh. 4.8 - Prob. 26ECh. 4.8 - Prob. 27ECh. 4.8 - Prob. 28ECh. 4.8 - Prob. 29ECh. 4.8 - Prob. 30ECh. 4.8 - Prob. 31ECh. 4.8 - Prob. 32ECh. 4.8 - Prob. 33ECh. 4.8 - Prob. 34ECh. 4.8 - Prob. 35ECh. 4.8 - Prob. 36ECh. 4.8 - Prob. 37ECh. 4.8 - Prob. 38ECh. 4.8 - Prob. 39ECh. 4.8 - Prob. 40ECh. 4.8 - Prob. 41ECh. 4.8 - Prob. 42ECh. 4.8 - Prob. 43ECh. 4.8 - Prob. 44ECh. 4.8 - Prob. 45ECh. 4.8 - Prob. 46ECh. 4.8 - Prob. 47ECh. 4.8 - Prob. 48ECh. 4.8 - Prob. 49ECh. 4.8 - Prob. 50ECh. 4.8 - Prob. 51ECh. 4 - Prob. 1RECh. 4 - Prob. 2RECh. 4 - Prob. 3RECh. 4 - Prob. 4RECh. 4 - Prob. 5RECh. 4 - Prob. 6RECh. 4 - Prob. 7RECh. 4 - Prob. 8RECh. 4 - Prob. 9RECh. 4 - Prob. 10RECh. 4 - Prob. 11RECh. 4 - Prob. 12RECh. 4 - Prob. 13RECh. 4 - Prob. 14RECh. 4 - Prob. 15RECh. 4 - Prob. 16RECh. 4 - Prob. 17RECh. 4 - Prob. 18RECh. 4 - Prob. 19RECh. 4 - Prob. 20RECh. 4 - Prob. 21RECh. 4 - Prob. 22RECh. 4 - Prob. 23RECh. 4 - Prob. 24RECh. 4 - Prob. 25RECh. 4 - Prob. 26RECh. 4 - Prob. 27RECh. 4 - Prob. 28RECh. 4 - Prob. 29RECh. 4 - Prob. 30RECh. 4 - Prob. 31RECh. 4 - Prob. 32RECh. 4 - Prob. 33RECh. 4 - Prob. 34RECh. 4 - Prob. 35RECh. 4 - Prob. 36RECh. 4 - Prob. 37RECh. 4 - Prob. 38RECh. 4 - Prob. 39RECh. 4 - Prob. 40RECh. 4 - Prob. 41RECh. 4 - Prob. 42RECh. 4 - Prob. 43RECh. 4 - Prob. 44RECh. 4 - Prob. 45RECh. 4 - Prob. 46RECh. 4 - Prob. 47RECh. 4 - Prob. 48RECh. 4 - Prob. 49RECh. 4 - Prob. 50RECh. 4 - Prob. 51RECh. 4 - Prob. 52RECh. 4 - Prob. 53RECh. 4 - Prob. 54RECh. 4 - Prob. 55RECh. 4 - Prob. 56RECh. 4 - Prob. 57RECh. 4 - Prob. 58RECh. 4 - Prob. 59RECh. 4 - Prob. 60RECh. 4 - Prob. 61RECh. 4 - Prob. 62RECh. 4 - Prob. 63RECh. 4 - Prob. 64RECh. 4 - Prob. 65RECh. 4 - Prob. 66RECh. 4 - Prob. 67RECh. 4 - Prob. 68RECh. 4 - Prob. 69RECh. 4 - Prob. 70RECh. 4 - Prob. 71RECh. 4 - Prob. 72RECh. 4 - Prob. 73RECh. 4 - Prob. 74RECh. 4 - Prob. 75RECh. 4 - Prob. 76RECh. 4 - Prob. 77RECh. 4 - Prob. 78RECh. 4 - Prob. 79RECh. 4 - Prob. 80RECh. 4 - Prob. 81RECh. 4 - Prob. 82RECh. 4 - Prob. 83RECh. 4 - Prob. 84RECh. 4 - Prob. 85RECh. 4 - Prob. 86RECh. 4 - Prob. 87RECh. 4 - Prob. 88RECh. 4 - Prob. 89RECh. 4 - Prob. 90RECh. 4 - Prob. 91RECh. 4 - Prob. 92RECh. 4 - Prob. 93RECh. 4 - Prob. 94RECh. 4 - Prob. 95RECh. 4 - Prob. 96RECh. 4 - Prob. 97RECh. 4 - Prob. 98RECh. 4 - Prob. 99RECh. 4 - Prob. 100RECh. 4 - Prob. 101RECh. 4 - Prob. 102RECh. 4 - Prob. 103RECh. 4 - Prob. 104RECh. 4 - Prob. 105RECh. 4 - Prob. 106RE
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