Physics for Scientists and Engineers
6th Edition
ISBN: 9781429281843
Author: Tipler
Publisher: MAC HIGHER
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 5, Problem 124P
(a)
To determine
To Show:
For given object in static equilibrium,
(b)
To determine
To Show:
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
The cable BC carries a tension of 750 N.
Determine the projection of the tension on
the line BO and find the angle between
them.
1.2 m
1.6 m
с
0.7 m
B
OT BO=555.16 N,0=42.25
OT BO=500.16 N,0=25.25
OT BO=-598i+411j+189.5k N,0=42.25
30°
0.8m
PROBLEM 02
Find the angle between two vector forces whose magnitudes are F and 3F and the magnitude of whose resultant
19 3F.
PROBLEM 03
A force T passing through points A and B as shown, has a counterclockwise moment of 400 KN-m about point O.
If the coordinates of points A and B are (0,6) and (8,0) in meters, compute the value of force T.
PROBLEM 04
The resultant of the concurrent forces shown 15 1OOKN with O, of 60° directed DR. Determine the unknown
force.
Figure,
PROBLEM 05.
Refer to problem SP203.
Q = 10 KN
%3D
Change P=25 KN up to the left at 30 degrees
w/ x-axis, Q=30 KN, W=35 KN, T=18 KN
directed to the right.
F = ?
3|
4
P = 30 KN
T = 20 KN
Q.1) For the figure shown if the tension in cable AC
is 21 kN, and 35 m long. Determine (a) the x, y, and
z components of the force (CA) exerted by the cable
on the support C, (b) the angles 0x, 0y, and 0z
defining the direction of that force.
28 m
20°
50
Chapter 5 Solutions
Physics for Scientists and Engineers
Ch. 5 - Prob. 1PCh. 5 - Prob. 2PCh. 5 - Prob. 3PCh. 5 - Prob. 4PCh. 5 - Prob. 5PCh. 5 - Prob. 6PCh. 5 - Prob. 7PCh. 5 - Prob. 8PCh. 5 - Prob. 9PCh. 5 - Prob. 10P
Ch. 5 - Prob. 11PCh. 5 - Prob. 12PCh. 5 - Prob. 13PCh. 5 - Prob. 14PCh. 5 - Prob. 15PCh. 5 - Prob. 16PCh. 5 - Prob. 17PCh. 5 - Prob. 18PCh. 5 - Prob. 19PCh. 5 - Prob. 20PCh. 5 - Prob. 21PCh. 5 - Prob. 22PCh. 5 - Prob. 23PCh. 5 - Prob. 24PCh. 5 - Prob. 25PCh. 5 - Prob. 26PCh. 5 - Prob. 27PCh. 5 - Prob. 28PCh. 5 - Prob. 29PCh. 5 - Prob. 30PCh. 5 - Prob. 31PCh. 5 - Prob. 32PCh. 5 - Prob. 33PCh. 5 - Prob. 34PCh. 5 - Prob. 35PCh. 5 - Prob. 36PCh. 5 - Prob. 37PCh. 5 - Prob. 38PCh. 5 - Prob. 39PCh. 5 - Prob. 40PCh. 5 - Prob. 41PCh. 5 - Prob. 42PCh. 5 - Prob. 43PCh. 5 - Prob. 44PCh. 5 - Prob. 45PCh. 5 - Prob. 46PCh. 5 - Prob. 47PCh. 5 - Prob. 48PCh. 5 - Prob. 49PCh. 5 - Prob. 50PCh. 5 - Prob. 51PCh. 5 - Prob. 52PCh. 5 - Prob. 53PCh. 5 - Prob. 54PCh. 5 - Prob. 55PCh. 5 - Prob. 56PCh. 5 - Prob. 57PCh. 5 - Prob. 58PCh. 5 - Prob. 59PCh. 5 - Prob. 60PCh. 5 - Prob. 61PCh. 5 - Prob. 62PCh. 5 - Prob. 63PCh. 5 - Prob. 65PCh. 5 - Prob. 67PCh. 5 - Prob. 68PCh. 5 - Prob. 69PCh. 5 - Prob. 70PCh. 5 - Prob. 71PCh. 5 - Prob. 72PCh. 5 - Prob. 73PCh. 5 - Prob. 74PCh. 5 - Prob. 75PCh. 5 - Prob. 76PCh. 5 - Prob. 77PCh. 5 - Prob. 78PCh. 5 - Prob. 79PCh. 5 - Prob. 80PCh. 5 - Prob. 82PCh. 5 - Prob. 83PCh. 5 - Prob. 84PCh. 5 - Prob. 85PCh. 5 - Prob. 86PCh. 5 - Prob. 87PCh. 5 - Prob. 88PCh. 5 - Prob. 89PCh. 5 - Prob. 90PCh. 5 - Prob. 91PCh. 5 - Prob. 92PCh. 5 - Prob. 93PCh. 5 - Prob. 94PCh. 5 - Prob. 95PCh. 5 - Prob. 96PCh. 5 - Prob. 97PCh. 5 - Prob. 101PCh. 5 - Prob. 102PCh. 5 - Prob. 103PCh. 5 - Prob. 104PCh. 5 - Prob. 105PCh. 5 - Prob. 106PCh. 5 - Prob. 107PCh. 5 - Prob. 108PCh. 5 - Prob. 109PCh. 5 - Prob. 110PCh. 5 - Prob. 111PCh. 5 - Prob. 112PCh. 5 - Prob. 113PCh. 5 - Prob. 114PCh. 5 - Prob. 115PCh. 5 - Prob. 116PCh. 5 - Prob. 117PCh. 5 - Prob. 118PCh. 5 - Prob. 119PCh. 5 - Prob. 120PCh. 5 - Prob. 121PCh. 5 - Prob. 122PCh. 5 - Prob. 123PCh. 5 - Prob. 124PCh. 5 - Prob. 125PCh. 5 - Prob. 126PCh. 5 - Prob. 127PCh. 5 - Prob. 128PCh. 5 - Prob. 129PCh. 5 - Prob. 130PCh. 5 - Prob. 131PCh. 5 - Prob. 132PCh. 5 - Prob. 133PCh. 5 - Prob. 134PCh. 5 - Prob. 135PCh. 5 - Prob. 136PCh. 5 - Prob. 137PCh. 5 - Prob. 138PCh. 5 - Prob. 139P
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- A 20.0-kg horizontal plank 4.00 m long rests on two supports, one at the left end and a second 1.00 m from the right end. What is the magnitude of the force exerted on the plank by the support near the right end? (a) 32.0 N (b) 45.2 N (c) 112 N (d) 131 N (e) 98.2 Narrow_forwardF = (-30i + 60j + 60k )kN %3D Forces are concurrent at point O. Determine the magnitude of the resultant of the three vectors. a 71.5 kN b 187 kN F, = (60i – 20j+ 15k )kN c 116 kN d 83.7 kN Determine the angle between F, andF,. F, = (20j – 25k)kN X а 111° b 132° c 69.0° d 21.0° Select the expression that denotes a unit vector in the direction and sense of F,. a 0.625j -0.781k b 0.625i -0.781j c -0.625 j –0.781k d 0.625i +0.781jarrow_forward16. ao The drawing shows a rectangular piece of wood. The forces applied to corners B and D have the same magnitude of 12 N and are directed parallel to the long and short sides of the rectangle. The long side of the rectangle is twice as long as the short side. An axis of ro- tation is shown perpendicular to the plane of the rectangle at its center. A third force (not shown in the drawing) is applied to cor- ner A, directed along the short side of the rectangle (either toward B or away from B), such that the piece of wood is at equilib- rium. Find the magnitude and direction of the force applied to corner A. A D Axis Problem 16arrow_forward
- The force F has a magnitude of 480 lb and acts along the line AM where M is the midpoint of the vertical side OB of the parallelepiped. Express F as its magnitude times the appropriate unit vector and then determine its x-, y-, and z-scalar components. B M 13" F = 480 lb i+ k) 9" Answers: Vector F = (480 lb)(i Scalar components 13" 3 A i+ iarrow_forwardA thin flexible gold chain of uniform linear density has a mass of 12.3 g. It hangs between two 30.0 cm long vertical sticks (vertical axes) which are a distance of 30.0 cm apart horizontally (x-axis), as shown in the figure below which is drawn to scale. 30 28 26 24 22 20 18 16 14 12 10 8 6 4 2 0 0 2 4 6 8 Evaluate the magnitude of the force on the left hand pole. .02011 N The graph shows that the lower part of the chain is horizontal at the left stick. Submit Answer Incorrect. Tries 3/12 Previous Tries 10 14 12 14 16 18 20 22 24 26 28 30arrow_forward3–6. Determine the force in member C and its angle 0 for equilibrium. The forces are concurrent at point O. Take F = 8 kN. Problems 3-5/6 9 kN 1088 00 000. 100 B C Xarrow_forward
- Determine the magnitude and coordinate direction angles of the resultant force acting at point A on the post. FAC =150 N JA FAв — 200 N C 3 m 3 m 2 m B 4 marrow_forwardY P = 800 N 30° 30° 30° X' 2. A block is resting on an incline of slope 5:12 as shown in Fig. It is subjected to a force F = 500 N on a slope of 3:4. Determine the components of F parallel and perpendicular to the incline. %3D F = 500 N 12 1arrow_forwardThe slope of the 5.0 KN force F is specified as shown in the figure. Express F as a vector in terms of the unit vectors i and j. Assume a = 13, b = 6. Answer: F = ( F b i+ j) KNarrow_forward
- Dental braces and kits are used to align and straighten the orientation of the teeth. In a specific case, the tooth that is needed to be aligned is pulled with a force of 9.21 N, 45° CW from the wire (from the +x-axis) and 6.27 N, 45° CCW from the wire (from the +x-axis). What is the magnitude of the resulting force of the two forces aligning the tooth?arrow_forwardThe force F has a magnitude of 480 Ib and acts along the diagonal of the parallelepiped as shown. Express Fin terms of its magnitude times the appropriate unit vector and determine its x-, y-, and z-components. A 6' F = 480 b 8' 3' B Answers: i+ i j+ i F= ( i Ib)( i Fx Ib i Fy Ib F2 Ib iarrow_forwardSAQ 1 1.2 m D C 80 kN m An 80-kn.m couple shown in the plate is caused by a pair of parallel forces of magnitude F (not shown). 1.6 m Determine: a) the smallest possible value of F, and b) the value of F if the forces act at points A and C and are parallel to the dashed line shown at A. A В 60°arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Glencoe Physics: Principles and Problems, Student...PhysicsISBN:9780078807213Author:Paul W. ZitzewitzPublisher:Glencoe/McGraw-HillPrinciples of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
Glencoe Physics: Principles and Problems, Student...
Physics
ISBN:9780078807213
Author:Paul W. Zitzewitz
Publisher:Glencoe/McGraw-Hill
Principles of Physics: A Calculus-Based Text
Physics
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Newton's First Law of Motion: Mass and Inertia; Author: Professor Dave explains;https://www.youtube.com/watch?v=1XSyyjcEHo0;License: Standard YouTube License, CC-BY