Chapter 5, Problem 35CRP

Explanation of Solution

The given program states that define a function name “MysteryPrint()” that takes “N” as an argument and then checks the “if” or “else” condition. This program has recursive function which calls the function directly by itself and then repeat the operation until the function get terminated or failed.

To ensure check the given program in the Python language,

# Function definition

def MysteryPrint(N):

  # Check Condition N is greater than 0

  if(N > 0):

    # Condition is true, display N

    print(N)

    # Call MysteryPrint with argument N-2

    MysteryPrint(N - 2)

  # Otherwise

  else:

    # Display N

    print(N)

    # Check condition N is greater than -1

    if(N > -1):

      # Call MysteryPrint with argument N+1

      MysteryPrint(N + 1)

# Call MysteryPrint with argument 2

MysteryPrint(2)

Explanation:

• Initially, the “MysteryPrint()” function takes value “2” as an argument, since it is given that call the function with the value “2”.
• In the next step, it checks the “if” condition which says if the value of “N” is greater than “0”, then execute the block of statement under the “if” condition and since, the value “2” is greater than “0”, so it executes the instruction under “if” condition and print the value “2”...