COLLEGE PHYSICS
COLLEGE PHYSICS
2nd Edition
ISBN: 9781464196393
Author: Freedman
Publisher: MAC HIGHER
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Chapter 5, Problem 51QAP
To determine

The magnitude and direction of the initial acceleration of the given system and the tension in the string once the objects are released.

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8-63. Determine the smallest force P that will cause impending motion. The crate and wheel have a mass of 50 kg and 25 kg, respectively. The coefficient of static friction between the crate and the ground is , = 0.2, and between the wheel and the ground, = 0.5. *8-64. Determine the smallest force P that will cause impending motion. The crate and wheel have a mass of 50 kg and 25 kg. respectively. The coefficient of static friction between the crate and the ground is , = 0.5, and between the wheel and the ground μ = 0.3. O O O 127 10 L C A 300 mm
EXAMPLE 5-11 ESTIMATE Gravity on Everest. Estimate the effective value of g on the top of Mt. Everest, 8850 m (29,035 ft) above sea level (Fig. 5-20). That is, what is the acceleration due to gravity of objects allowed to fall freely at this altitude? Ignore the mass of the mountain itself. APPROACH The force of gravity (and the acceleration due to gravity g) depends on the distance from the center of the Earth, so there will be an effective value g on top of Mt. Everest which will be smaller than g at sea level. We assume the Earth is a uniform sphere (a reasonable "estimate"). SOLUTION We use Eq. 5-5, with r replaced by r = 6380 km + 8.9 km 6389 km 6.389 x 106 m: (6.67 x 10-11 N-m2/kg²)(5.98 x 1024 kg) (6.389 x 10° m) which is a reduction of about 3 parts in a thousand (0.3%). ME 8 = G- = 9.77 m/s, %3D %3D How many Significant Figures are in the answer? Check
The uniform crate has a mass of 150 kg. If the coefficient of static friction between the crate and the floor is us = 0.2, determine the smallest mass of the man so he can move the crate. The coefficient of static friction between his shoes and the floor is us = 0.45. Assume the man exerts only a horizontal force on the crate 2.4 m 1.6 m -1.2 m-

Chapter 5 Solutions

COLLEGE PHYSICS

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Newton's Third Law of Motion: Action and Reaction; Author: Professor Dave explains;https://www.youtube.com/watch?v=y61_VPKH2B4;License: Standard YouTube License, CC-BY