Study Guide for Stewart's Single Variable Calculus: Early Transcendentals, 8th
Study Guide for Stewart's Single Variable Calculus: Early Transcendentals, 8th
8th Edition
ISBN: 9781305279148
Author: Stewart, James, St. Andre, Richard
Publisher: Cengage Learning
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Chapter 5.5, Problem 1PT
To determine

To choose: The appropriate option for the value of f(g(x))g(x)dx when f(x)=F(x)+C.

Expert Solution & Answer
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Answer to Problem 1PT

The appropriate option for the value of f(g(x))g(x)dx when f(x)=F(x)+C is d)F(g(x))+C_.

Explanation of Solution

Formula used:

Substitution rule:

If u=g(x) is differentiable function whose range is an interval I and f is continuous on I, then f(g(x))g(x)dx=f(u)du. Here, u=g(x) and du=g(x)dx.

Calculation:

From the substitution rule,

f(g(x))g(x)dx=f(u)du(1).

In equation (1), if u=x and du=1, then f(g(x))g(x)dx=f(x).

It is known that, f(x)=F(x)+C.

Compute the value of f(g(x))g(x)dx by substituting u=g(x) and du=g(x) in equation (1).

f(g(x))g(x)dx=f(g(x))g(x)f(g(x))g(x)dx=F(g(x))+C[f(x)=F(x)+C]

Therefore, the appropriate option for the value of f(g(x))g(x)dx when f(x)=F(x)+C is d)F(g(x))+C_.

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