Operations Research : Applications and Algorithms
Operations Research : Applications and Algorithms
4th Edition
ISBN: 9780534380588
Author: Wayne L. Winston
Publisher: Brooks Cole
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Chapter 6, Problem 34RP
Program Plan Intro

Optimal solution:

  • Consider the linear programming problem given below:
  • max z= 20x1+10x2
  • Subject to constraints:
    • x1+x2=150
    • x140
    • x220
    • x1,x20
  • Here,
  • xi= Fraction of investment I purchased by star oil.
  • The Lindo output of the LP is given in the following figure:
  • LP optimum found at step 5
  • Objective function value: 57.44902.
VariableValueReduced Cost
x11.0000000.000000
x20.2008600.000000
x31.0000000.000000
x41.0000000.000000
x50.2880840.000000
RowSlack or SurplusDual prices
10.0000000.190418
20.0000000.984644
30.0000007.951474
40.7991400.000000
50.00000010.124693
60.00000012.063268
70.7119160.000000
  • Number of iterations: 5
  • Ranges in which the basis is unchanged:
Obj coefficient ranges
VariableCurrent coefficientAllowable increaseAllowable Decrease
x113.000000Infinity7.951474
x216.00000045.1045279.117647
x316.000000Infinity10.124693
x414.000000Infinity12.063268
x539.00000051.66666830.245285
Right-hand side ranges
RowCurrent RHSAllowable increaseAllowable Decrease
140.00000038.2647069.617647
220.00000011.2758638.849056
31.0000001.1393731.000000
41.000000Infinity0.799140
51.0000001.9957451.000000
61.0000002.3191491.000000
71.000000Infinity0.711916

Explanation of Solution

b.

  • The given LP is called the primal. If the primal is a max problem, then the dual will be min problem. Define the variables for the max problem to be z,x1,x2,...........,xn and the variables for the min problem to be w,y1,y2,........,yn.
  • max z= c1x1+c2x2+.......+cnxn
  • subject to constraints
    • a11x1+a12x2+.......+a1nxnb1
    • a21x1+a22x2+.......+a2nxnb2
    • am1x1+am2x2+.......+amnxnbm
  • The dual of the normal max problem is defined below:
  • min w=b1y1+b2y2+.......+b2yn
  • subject to constraints
    • a11y1+a12y2+.......+a1nync1
    • a21y1+a22y2+.......+a2nync2
    • am1y1+am2y2+.......+amnyncm
  • Given a max problem, the primal is read across the table and the dual is found by reading down.
min w (x10)(x20)

max z

(xn0) 
  x1x2 xn 
(y10)y1a11a12a1nb1
(y20)y2a21a22a2nb2
 
(ym0)ymam1am2amnbm
  c1c2 cn 
  • The given problem is a non normal Max problem

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Chapter 6 Solutions

Operations Research : Applications and Algorithms

Ch. 6.3 - Prob. 4PCh. 6.3 - Prob. 5PCh. 6.3 - Prob. 6PCh. 6.3 - Prob. 7PCh. 6.3 - Prob. 8PCh. 6.3 - Prob. 9PCh. 6.4 - Prob. 1PCh. 6.4 - Prob. 2PCh. 6.4 - Prob. 3PCh. 6.4 - Prob. 4PCh. 6.4 - Prob. 5PCh. 6.4 - Prob. 6PCh. 6.4 - Prob. 7PCh. 6.4 - Prob. 8PCh. 6.4 - Prob. 9PCh. 6.4 - Prob. 10PCh. 6.4 - Prob. 11PCh. 6.4 - Prob. 12PCh. 6.4 - Prob. 13PCh. 6.5 - Prob. 1PCh. 6.5 - Find the duals of the following LPs: Ch. 6.5 - Prob. 3PCh. 6.5 - Prob. 4PCh. 6.5 - Prob. 5PCh. 6.5 - Prob. 6PCh. 6.6 - Prob. 1PCh. 6.6 - Prob. 2PCh. 6.7 - Prob. 1PCh. 6.7 - Prob. 2PCh. 6.7 - Prob. 3PCh. 6.7 - Prob. 4PCh. 6.7 - Prob. 5PCh. 6.7 - Prob. 6PCh. 6.7 - Prob. 7PCh. 6.7 - Prob. 8PCh. 6.7 - Prob. 9PCh. 6.8 - Prob. 1PCh. 6.8 - Prob. 2PCh. 6.8 - Prob. 3PCh. 6.8 - Prob. 4PCh. 6.8 - Prob. 5PCh. 6.8 - Prob. 6PCh. 6.8 - Prob. 8PCh. 6.8 - Prob. 9PCh. 6.8 - Prob. 10PCh. 6.8 - Prob. 11PCh. 6.9 - Prob. 1PCh. 6.9 - Prob. 2PCh. 6.9 - Prob. 3PCh. 6.10 - Prob. 1PCh. 6.10 - Prob. 2PCh. 6.10 - Prob. 3PCh. 6.11 - Prob. 1PCh. 6.11 - Prob. 3PCh. 6.11 - Prob. 4PCh. 6.12 - Prob. 5PCh. 6.12 - Prob. 6PCh. 6.12 - Prob. 7PCh. 6 - Prob. 1RPCh. 6 - Prob. 2RPCh. 6 - Prob. 3RPCh. 6 - Prob. 4RPCh. 6 - Prob. 5RPCh. 6 - Prob. 6RPCh. 6 - Prob. 7RPCh. 6 - Prob. 8RPCh. 6 - Prob. 9RPCh. 6 - Prob. 10RPCh. 6 - Prob. 11RPCh. 6 - Prob. 13RPCh. 6 - Prob. 14RPCh. 6 - Prob. 15RPCh. 6 - Prob. 17RPCh. 6 - Prob. 18RPCh. 6 - Prob. 19RPCh. 6 - Prob. 20RPCh. 6 - Prob. 21RPCh. 6 - Prob. 22RPCh. 6 - Prob. 25RPCh. 6 - Prob. 29RPCh. 6 - Prob. 33RPCh. 6 - Prob. 34RPCh. 6 - Prob. 35RPCh. 6 - Prob. 36RPCh. 6 - Prob. 37RP
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Operations Research : Applications and Algorithms
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ISBN:9780534380588
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