BASIC BIOMECHANICS
BASIC BIOMECHANICS
8th Edition
ISBN: 9781259913877
Author: Hall
Publisher: RENT MCG
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Chapter 6, Problem 5AP

If the fibers of a pennate muscle are oriented at a 45° angle to a central tendon, how much tension is produced in the tendon when the muscle fibers contract with 150 N of force? (Answer: 106 N)

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ney: Load (L) = 5 kgs = Effort E = Fulcrum Weight of forearm = 1.8 kgs L = Load Biceps brachii muscle Distance of load from elbow joint = 35 cm %3D Effort (E) = contraction of biceps brachii Distance of center of mass of forearm from elbow = 17 cm Distance of tendon from elbow = 4 cm A) Draw the free-body diagram to represent the forces and moments Load (L) = weight of object plus forearm B) Write the torque equation for static equilibrium Fulcrum (F) = elbow joint
Arrange the following in statements in the order that they occur during muscle contraction: 1-10 ACh leaves the synaptic knob and enters the synaptic cleft          The action potential is carried deep into the muscle cell by T tubules       The muscle cell relaxes and lengthens        Myosin binds to and pulls on actin, resulting in muscle shortening             Calcium attaches to troponin           As calcium re-enters the sarcoplasmic reticulum, its concentration at the myofilaments decreases     Calcium is released from the sarcoplasmic reticulum        Tropomyosin rolls out of the way, exposing actin                 ACh diffuses across the synaptic cleft and attaches to protein receptors on the sarcolemma, resulting in muscle "excitation"          Na+ enters the muscle cell and K+ exits, resulting in an action potential
describe the events that lead to muscle contraction starting at the level of the neuromuscular junction.  Make sure to use the terms: myosin, actin, calcium, troponin, tropomyosin, T tubules, SR, myosin head, ATP.
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