Steel Design (Activate Learning with these NEW titles from Engineering!)
6th Edition
ISBN: 9781337094740
Author: Segui, William T.
Publisher: Cengage Learning
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Question
Chapter 6, Problem 6.6.5P
To determine
(a)
If the member is a beam-column using LRFD method.
To determine
(b)
If the member is a beam-column using ASD method.
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Consider the simply supported truss as defined in the figure
and parameter table. Find the force in members CD, HD,
and HG. Follow the convention the tension is positive and
compression is negative.
A
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B
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1.5
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50
60
60
L5
L6
P₁
P₂
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The force in member HD =
The force in member HG =
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Determine the force in members FE, FB, and BC of
the truss and state if the members are in tension or
compression. After sectioning the truss, solve for each
force directly using a single equilibrium equation to obtain
each force. Assume that all joints are pin connected.
P-800 lb and P-1300 lb. (Figure 1)
Figure
15 h
100
-100
(1 of 1
-10 -
Part A
Determine the force in member FE of the truss
Express your answer in kilopounds to three significant figures. Enter negative value in the case of
compression and positive value in the case of tension.
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Submit
Part B
Fra
Submit
Request Answer
Determine the force in member FB of the truss.
Express your answer in kilopounds to three significant figures. Enter negative value in the case of
compression and positive value in the case of tension.
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Part C
Request Answer
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For the truss shown in Figure 2.3a, determine the force in member
GH if m = 4 m, n = 7 m, a = 87°, andP = 4.5 kN. Indicate whether the
member is in tension or compression. (Note: Use negative sign (-) if
the member is in compression.)
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m H
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G m
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C
D
E
P kN
Chapter 6 Solutions
Steel Design (Activate Learning with these NEW titles from Engineering!)
Ch. 6 - Prob. 6.2.1PCh. 6 - Prob. 6.2.2PCh. 6 - Prob. 6.6.1PCh. 6 - Prob. 6.6.2PCh. 6 - Prob. 6.6.3PCh. 6 - The member shown in Figure P6.6-4 is part of a...Ch. 6 - Prob. 6.6.5PCh. 6 - Prob. 6.6.6PCh. 6 - Prob. 6.6.7PCh. 6 - Prob. 6.6.8P
Ch. 6 - Prob. 6.6.9PCh. 6 - Prob. 6.6.10PCh. 6 - Prob. 6.6.11PCh. 6 - Prob. 6.6.12PCh. 6 - Prob. 6.6.13PCh. 6 - Prob. 6.7.1PCh. 6 - Prob. 6.7.2PCh. 6 - Prob. 6.8.1PCh. 6 - Prob. 6.8.2PCh. 6 - Prob. 6.8.3PCh. 6 - Prob. 6.8.4PCh. 6 - Prob. 6.8.5PCh. 6 - Prob. 6.8.6PCh. 6 - Prob. 6.8.7PCh. 6 - Prob. 6.8.8PCh. 6 - Prob. 6.8.9PCh. 6 - Prob. 6.8.10PCh. 6 - Prob. 6.9.1PCh. 6 - Prob. 6.9.2P
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Similar questions
- Problem 2: Determine the force in ALL the members of the truss. State if the members are in tension or compression. Show all your work to receive full credit. (Hint: It is not needed to find the reaction forces at C and E if you use the Method of Joints). Note: P1= 1000 lb and P: = 500 lb B C30 45 999 4 ft E 550 D. -4 ft- - 4 ft- 999 299arrow_forwardF ., É, are applied to the truss system. В a) Find member forces in each member and state if the members are in tension or 4 m compression. b) If the maximum force that any member can support is Tmax in tension and Cmax in compression, determine the maximum value of P that can be supported. A E 3 т 3 m 3 т 3 m F1 F2 F3 F4 F5 Tmax Cmax P 2P 40° 7 kN 8 kN 2P Note: Do not show zero forces in your calculations.arrow_forwardDetermine the smallest safe cross-sectional areas of members CD, Cl and CH for the truss shown. The allowable stress are 100 MPa in tension and 80 MPa in compression. Indicate tension or compression. (Draw the required FBD and answer in mm2). Fa a –– a→– a- B D |E A a F G H а 3 2 т 45 kNarrow_forward
- -5 @ 3m-15m- C F H J K ML boo I A 4@4m=16m B D G E 60 kips A For the truss shown, what is the force in member FG? B what is the force in member BE? + --Darrow_forwardASAParrow_forwardA.) the plastic section modulusand the plastic moment Mp.Bending is about the x-axis,and the steel is A572 Grade50. Fy = 345 MPaarrow_forward
- Q₁: Analyze the truss shown below B с <50k 3m IMI A E 100ku EA is Constant for all members + Am X Amarrow_forwardFor the truss shown in Figure 2.3b, determine the force in member DG if x = 5 m, y = 3 m and P = 6 kN. Indicate whether the member is in tension or compression. (Note: Use negative sign (-) if the member is in compression.) 7 panels at x m = 7x m В J C D K E y F A N H G P kN P kNarrow_forwardFor the truss shown below, F= 12 kN and L=3 m. a) Determine the force in member BE. A and E are constant. Assume Ngg is tension. b) Determine the deformed shape of the truss. L Fill out the table below: N (kN) (assuming Nis in tension, fill in with actual ON ON Member L (m) FBE values) AE BD FBE FBE CE FBE FBE ВЕ FBE FBE CD FBE FBE AB BC FBE FBE DE FBE FBE Summation FBEarrow_forward
- DETERMINE FORCE (N) OF MEMBER EG in the truss shown. F1 = 214 N %D F2 = 876 N %3D F3 = 435 N a = 38 degree X = 15 m. **Note: for compression, include a negative sign (- ) and for tension, type your answer as is. Input your answer in two (2) decimal places only without the unit. В H A C E G F1 F2 F3arrow_forwardG5 // The bar AB is considered to be absolutely rigid and is horizontal before the load of 10000N is applied. The connection at C is a pin, and AB is supported by the bronze rod EA and the steel rod FB. The length of EA is 1.5m and FB is 2.5m. Neglect any possibility of lateral buckling and the weights of all bars „Calculate the stresses in each rod. For bronze E=100 GPa, A=60 mm? for steel E=200 GPa, A= 25 mm? F Steel L=2.5m B. 3m 2m- Bronze L=1.5m 10000Narrow_forwardFor the truss shown in Figure 2.3a, determine the force in member BH if m= 5 m, n = 4 m, a = 76°, and P = 1.45 kN. Indicate whether the member is in tension or compression. (Note: Use negative sign (-) if the member is in compression.) A J m Hm Gm F m B PKN C n D α Earrow_forward
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