Physical Universe
16th Edition
ISBN: 9780077862619
Author: KRAUSKOPF, Konrad B. (konrad Bates), Beiser, Arthur
Publisher: Mcgraw-hill Education,
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Chapter 8, Problem 28E
To determine
The kinetic energy of
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An Erbium-166 nucleus contains 68 protons. The atomic mass of a
neutral Erbium-166 atom is 165.930u, where u = 931.5 MeV/c². In
this question you may use that the mass of a proton is 938.27 MeV/c²,
the mass of a neutron is 939.57 MeV/e² and the mass of an electron
is 0.511 MeV/c².
i. Calculate the nuclear binding energy per nucleon, giving your
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ii. Electrons with an energy of 0.5 GeV are scattered off the nucleus.
Estimate the scattering angle of the first minimum in the resulting
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iii. Briefly comment on whether or not you expect this nucleus to be
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How much energy in kJ is released to form one mole of 75As from protons, electrons, and neutrons if the nucleus has a mass of 74.921594 amu? The masses of the proton, electron and neutron are 1.00728 amu, 0.000549 amu and 1.00867 amu, respectively.
-3.15e10 kJ/mol
-6.31e10 kJ/mol
-6.31e13 kJ/mol
3.15e13 kJ/mol
Use the below values for this problem. Please note that the mass for H is for the entire atom (proton & electron).
Neutron: m = 1.67493x10-27 kg = 1.008665 u = 939.57 MeV/c²
.
¹H: mH = 1.67353x10-27 kg = 1.007825 u = 938.78 MeV/c²
1
1 u = 1.6605x10-27 kg = 931.5 MeV/c²
.
Consider the following decay: 239 Pu 235 U+ a. 239 Pu has a mass of 239.0521634 u, 235 U has a mass of 235.0439299 u, and a has a mass of 4.002603 u.
94
92
94
92
Determine the disintegration energy (Q-value) in MeV.
Q =
Determine the binding energy (in MeV) for 239 Pu.
94
EB =
Chapter 8 Solutions
Physical Universe
Ch. 8 - Prob. 1MCCh. 8 - Prob. 2MCCh. 8 - Prob. 3MCCh. 8 - Prob. 4MCCh. 8 - Prob. 5MCCh. 8 - Prob. 6MCCh. 8 - Prob. 7MCCh. 8 - Prob. 8MCCh. 8 - Prob. 9MCCh. 8 - Prob. 10MC
Ch. 8 - Prob. 11MCCh. 8 - Prob. 12MCCh. 8 - Prob. 13MCCh. 8 - Prob. 14MCCh. 8 - Prob. 15MCCh. 8 - Prob. 16MCCh. 8 - Prob. 17MCCh. 8 - Prob. 18MCCh. 8 - Prob. 19MCCh. 8 - Prob. 20MCCh. 8 - Prob. 21MCCh. 8 - Prob. 22MCCh. 8 - Prob. 23MCCh. 8 - Prob. 24MCCh. 8 - Prob. 25MCCh. 8 - Prob. 26MCCh. 8 - Prob. 27MCCh. 8 - Prob. 28MCCh. 8 - Prob. 29MCCh. 8 - Prob. 30MCCh. 8 - Prob. 31MCCh. 8 - Prob. 32MCCh. 8 - Prob. 33MCCh. 8 - Prob. 34MCCh. 8 - Prob. 35MCCh. 8 - Prob. 36MCCh. 8 - Prob. 37MCCh. 8 - Prob. 38MCCh. 8 - Prob. 39MCCh. 8 - Prob. 40MCCh. 8 - Prob. 1ECh. 8 - Prob. 2ECh. 8 - Prob. 3ECh. 8 - Prob. 4ECh. 8 - Prob. 5ECh. 8 - Prob. 6ECh. 8 - Prob. 7ECh. 8 - Prob. 8ECh. 8 - Prob. 9ECh. 8 - Prob. 10ECh. 8 - Prob. 11ECh. 8 - Prob. 12ECh. 8 - Prob. 13ECh. 8 - Prob. 14ECh. 8 - The polonium isotope 84210Po undergoes alpha decay...Ch. 8 - Prob. 16ECh. 8 - Prob. 17ECh. 8 - Prob. 18ECh. 8 - Prob. 19ECh. 8 - Prob. 20ECh. 8 - Prob. 21ECh. 8 - If the half-life of a radionuclide is 1 month, is...Ch. 8 - Prob. 23ECh. 8 - One-eighth of a sample of T90227h remains...Ch. 8 - Prob. 25ECh. 8 - Prob. 26ECh. 8 - Prob. 27ECh. 8 - Prob. 28ECh. 8 - Prob. 29ECh. 8 - Prob. 30ECh. 8 - Prob. 31ECh. 8 - Prob. 32ECh. 8 - Prob. 33ECh. 8 - Prob. 34ECh. 8 - Prob. 35ECh. 8 - Prob. 36ECh. 8 - Prob. 37ECh. 8 - Prob. 38ECh. 8 - Prob. 39ECh. 8 - Prob. 40ECh. 8 - Prob. 41ECh. 8 - Prob. 42ECh. 8 - Prob. 43ECh. 8 - Prob. 44ECh. 8 - Prob. 45ECh. 8 - Prob. 46ECh. 8 - Prob. 47ECh. 8 - Prob. 48ECh. 8 - Prob. 49ECh. 8 - Prob. 50ECh. 8 - Prob. 51ECh. 8 - Prob. 52ECh. 8 - Prob. 53ECh. 8 - Prob. 54ECh. 8 - Prob. 55ECh. 8 - Prob. 56ECh. 8 - Prob. 57ECh. 8 - Prob. 58E
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- How many kJ of energy are released to form one mole of 133Cs from protons and neutrons if the atom has a mass of 132.905429 amu? Please remember to include the mass of electrons in the calculation. Given the mass of a proton is 1.007825 amuarrow_forwardAn alpha particle (charge +3.20 x 10^-19C, mass 6.64 x10^-27kg) is initially 5.2cm away from a fixed golden nucleus (charge +1.36 x10^-17C, mass 3.29x10^-25kg), and moving toward the nucleus with a speed of 8.1x10^5m/s. How close to the nucleus does te alpha particle get? Note: the nucleus diameter is approximately 10^-14m and the alpha particles's is 10^-15marrow_forwardUse the below values for this problem. Please note that the mass for H is for the entire atom (proton & electron). Neutron: m,= 1.67493x1027 kg= 1.008665 u = 939.57 MeVIC H: my = 1.67353x10 27 kg = 1.007825 u = 938.78 MeVic 1u= 1.6605x10-27 kg = 931.5 MeVic? Consider the following decay: 211 At 207 Bi + a. 211 At has a mass of 210.9874963 u, 207 Bi has a mass of 206.981593 u, and a has a mass of 4.002603 u. 85 83 85 83 Determine the disintegration energy (Q-value) in MeV. Determine the binding energy (in MeV) for 211 At. 85 EB =arrow_forward
- A Boron -12 atom ( 12.01435u) beta -decays into a carbon atom ( 12.00000 u). What is the maximum kinetic energy of the emitted electron? ( Hint: the kinetic energy of the electron will be the maximum if the antineutrino kas zero energy).arrow_forwardc) The equation below describes the disintegration of a polonium nucleus into a lead nucleus and an alpha-particle. During the reaction energy Q is released. 210Po → He +²02Pb+Q 84 82 Calculate the loss of energy during the reaction. The masses in the atomic mass unit u are as follows: 210 206 Po= 209.98287 u, Pb = 205.97446 u and He = 4.002604 u. 84 82 You may assume that 1u is equivalent to 931 MeV. d) The lead nucleus recoils in the opposite direction to the emitted alpha particle conserving momentum. Hence calculate: i) The ratio of the recoil nucleus and alpha particle velocities ii) The kinetic energy distribution of these products.arrow_forwardO Two deuterium atoms (H) react to produce tritium (H) and hydrogen (H) according to the following reaction: + + |H 2.014 102 u 2.014 102 u 3.016 050 u 1.007 825 u What is the energy (in MeV) released by this deuterium-deuterium reaction?arrow_forward
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- The element 218Po (Polonium-218, Z = 84, atomic mass 218.008966 u) can decay through the emission of a β-particle to 218At (Astatine-218, Z = 85, atomic mass 218.00880 u). If all of the energy released is carried away by the β-particle's kinetic energy, calculate the kinetic energy of the β-particle.answer in units of MeV, correct to two decimal places.arrow_forwardd) The equation below describes the disintegration of a bismuth nucleus into a thallium nucleus and an alpha-particle. During the reaction energy Q is released. 212 208 Bi He + 83 81 TI + energy released Q. The masses in the atomic mass unit u are as follows: 212 83 208 Bi = 211.99127 u, 81 TI = 207.98201 u and He = 4.002050 u. You may assume that 1u is equivalent to 931 MeV. Calculate: i) The loss of mass during the reaction. ii) kinetic energy of the products. e) When an alpha particle is emitted, the thallium nucleus recoils in the opposite direction. Use the principle of the conservation of momentum to estimate how the kinetic energy will be shared between the thallium nucleus and the a- particle.arrow_forwardA sample of Co (atomic mass= 59.933820u) undergoes ß decay emitting electrons with maximum kinetic energy 0.31 MeV. If the ground state mass of the Ni atom is 59.930788u, then calculate the excitation energy of the state to which the decay occurs.arrow_forward
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