The reason for not using heat in Kinyoun modification. Introduction: The acid-fast stain is used to differentiate between acid-fast bacteria and non-acid fast bacteria. The stain here is used in carbol fuchsin, which is soluble in the lipoidal material found in the mycobacterial cell wall. The decolorizing agent used here is acid alcohol.

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Chapter 8, Problem 5Q

Summary Introduction

To determine:

The reason for not using heat in Kinyoun modification.

Introduction:

The acid-fast stain is used to differentiate between acid-fast bacteria and non-acid fast bacteria. The stain here is used in carbol fuchsin, which is soluble in the lipoidal material found in the mycobacterial cell wall. The decolorizing agent used here is acid alcohol.

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Answer 2

Question

Chapter 8, Problem 5Q

Summary Introduction

To determine:

The reason for not using heat in Kinyoun modification.

Introduction:

The acid-fast stain is used to differentiate between acid-fast bacteria and non-acid fast bacteria. The stain here is used in carbol fuchsin, which is soluble in the lipoidal material found in the mycobacterial cell wall. The decolorizing agent used here is acid alcohol.

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Answer 3

Question

Chapter 8, Problem 5Q

Summary Introduction

To determine:

The reason for not using heat in Kinyoun modification.

Introduction:

The acid-fast stain is used to differentiate between acid-fast bacteria and non-acid fast bacteria. The stain here is used in carbol fuchsin, which is soluble in the lipoidal material found in the mycobacterial cell wall. The decolorizing agent used here is acid alcohol.

Expert Solution & Answer

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Check out a sample textbook solution

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Answer 4

Question

Chapter 8, Problem 5Q

Summary Introduction

To determine:

The reason for not using heat in Kinyoun modification.

Introduction:

The acid-fast stain is used to differentiate between acid-fast bacteria and non-acid fast bacteria. The stain here is used in carbol fuchsin, which is soluble in the lipoidal material found in the mycobacterial cell wall. The decolorizing agent used here is acid alcohol.

Expert Solution & Answer

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Check out a sample textbook solution

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Answer 5

Chapter 8, Problem 5Q

Summary Introduction

To determine:

The reason for not using heat in Kinyoun modification.

Introduction:

The acid-fast stain is used to differentiate between acid-fast bacteria and non-acid fast bacteria. The stain here is used in carbol fuchsin, which is soluble in the lipoidal material found in the mycobacterial cell wall. The decolorizing agent used here is acid alcohol.

Answer 6

Chapter 8, Problem 5Q

Summary Introduction

To determine:

The reason for not using heat in Kinyoun modification.

Introduction:

The acid-fast stain is used to differentiate between acid-fast bacteria and non-acid fast bacteria. The stain here is used in carbol fuchsin, which is soluble in the lipoidal material found in the mycobacterial cell wall. The decolorizing agent used here is acid alcohol.

Answer 7

Chapter 8, Problem 5Q

Summary Introduction

To determine:

The reason for not using heat in Kinyoun modification.

Introduction:

The acid-fast stain is used to differentiate between acid-fast bacteria and non-acid fast bacteria. The stain here is used in carbol fuchsin, which is soluble in the lipoidal material found in the mycobacterial cell wall. The decolorizing agent used here is acid alcohol.

Answer 8

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Answer 11

Ch. 8 - What are the large blue-stained areas on the...Ch. 8 - What is the decolorizing agent in the Gram stain?...Ch. 8 - Prob. 3Q Ch. 8 - What is phenol (carbolic acid), and what is its...Ch. 8 - Prob. 5Q Ch. 8 - How might the acid-fast characteristic of...Ch. 8 - In 1882, after experimenting with staining...Ch. 8 - Clinical specimens suspected of containing...Ch. 8 - The acid-fast stain is used to detect...

Solution Summary: The author explains the reason for not using heat in Kinyoun modification, which is a modifies method of weak acid-fast stain that uses 5 percent sulfuric acid.

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