Chemistry: Structure and Properties
1st Edition
ISBN: 9780321834683
Author: Nivaldo J. Tro
Publisher: PEARSON
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Chapter A1, Problem 16E
Interpretation Introduction
Interpretation:
Unit conversion is required in engineering and science fields. They require a relationship between the expressed units.
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Students have asked these similar questions
34. Convert 4.58 x 10³ cm³ to each
unit.
a. L
b. mL
c. gal
d. qt
The m in the equation for density is
in italic type, meaning that it stands
for mass rather than for meters. In
general, the symbols for units such
as meters (m), seconds (s), or
kelvins (K) appear in regular type,
while those for variables such as
mass (m), volume (V), and time (t)
appear in italics.
The mass of a certain atom is 2.086 x 10-22 g. This is the same mass as
2.086 x 10-16 mg.
2.086 x 10-25
kg.
2.086 x 10-28
μ8.
2.086 x 10-31 ng.
The mass of a certain atom is 2.086 x 10°22 g. This is the same mass as
2.086 x 10-16 mg.
2.086 x 10-25
kg.
2.086 x 10-28
Hg.
O 2.086 x 10-31
ng.
Chapter A1 Solutions
Chemistry: Structure and Properties
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- 1.53 Carry out the following unit conversions. (a) 3.47106g to g , (b) 2.73104L to mL, (c) 725 ns to s, (d) 1.3 m to km.arrow_forwarda 7.11 hg to g, b 5.27 x 107 m to pm, c 3.63 x 106 g to dag.arrow_forward3. Provide the answer with the appropriate number of significant figures. a. 6.03 x 650 b. 2.7 x 1031.645 c. 3.000 + 7.61 + 124.2 d. (3.55 x 109) x (9.5 x 10-7) e. 7.845 - 1.20 f. 7.845- 1.2 g. (6.72 x 106 ) - (4.32 x 10“ )arrow_forward
- 15. Complete this table so that all the measurements in each row have the same value. Use the metric staircase. How mg 6.6 x 10³ 26×107 g 2.8 x 104 cg 28.3 16. What equation is used to determine the density of an object? mass Dz Vakume kg 17. Would the density of a person be the same on the surface of the Earth and o he surface of the moon? Explain.arrow_forward5 nyoor X A the p X Spoti x A Chap x E * Par X Netfli X Goo 53. Calculate Make the following conversions. Express your answers in scientific notation. a. 14.8 g = ? ug b. 3.72 g = ? kg C. 66.3 L ? cm³ d. 7.5 x 104 J = ? kJ e. 3.9 × 10° mg = ? dg f. 2.1 X 10 dL = ? µL %3D %3Darrow_forwardConvert 15.0 L to each unit.a. mL b. cm3c. gal d. qtarrow_forward
- I. Significant Figures and Conversion A. Scientific Notation 1. 58 cm → km 2. 67 W → MW 3. 196 mL L 4. 17 dm – cm 5. 299 W → TWarrow_forward7. Convert the following:a. 623.5 F to K b. 0.0083 miles to cm c. 3027.2 ml to ounces d. 0.885 kg to poundsarrow_forward1) The density of a material can be used to calculate the volume of an object if its mass is known. Likewise, the mass can be calculated if the density and volume are known. A pre-1964 quarter, made predominantly of silver (density= 10.5 g/mL), was determined to have a mass of 6.25 g. What is the volume of a quarter? A. 65.6 B. 0.595 mL C. 1.68 mL D. 6.25 mL 2) Add: 2.11 + 104.056 + 0.1205 A. 106 B. 106.29 C. 106.286 D. 106.2865arrow_forward
- The owner of a rock shop claims that a nugget is pure gold. When the nugget is placed into a 100.0-mL graduated cylinder containing 50.0 mL of water and the water rises to 55.4 mL, what should the mass of the nugget be? (densitygold = 19.3 g/cm3) A. 5.40 g B. 20.3 g C. 104 g D. 1.07 x 103 g thank you!arrow_forward2. Convert 475.0 dyne/cm? to Pa.arrow_forwardAssume you measured an irregular shaped object in a beaker to be 149.167 g, and you know that the empty beaker weighs 96.222 g. You then carefully drop this object in a graduated cylinder containing 20.0 mL of water, and the water level rises to 42.3 mL. Calculate the final density of the irregular shaped object to the correct number of significant figures. a. 1.25 b. 2.37 c. 7.46 d. 4.31 e. 3.53arrow_forward
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