KINETIC CONSTANT No Na2HPO4 25mM Na2HPO4 50mM Na2HPO4 Vmax nmol p-NP. Min- 20.3252 14.30615 17.30104 Km mM -0.819106 -0.46495 -0.352941 1. What does this suggest about the structure of the active side of the enzyme?
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- The enzyme lysozyme hydrolyzes glycosidic bonds in peptidoglycan, an oligosaccharide found in bacterial cell walls. The active site of lysozyme contains two amino acid residues essential for catalysis: E35 and D52. Which of the following statements about lysozyme is true? More than one may apply The graph shows the pH-activity profile of lysozyme. 100 50 4. 6. 8. 10 pH Residue E35 exhibits general base catalysis O The pKa of E35 is approximately 4.3 O The pKa of D52 is approximately 4.5 O The optimal activity of lysozyme is approximately 5.2 Residue E35 exhibits covalent catalysis The pka of E35 is approximately 6.1 The pka of D52 is approximately 3.7 Activity (% of maximal)Chymotrypsin has the highest affinity for which of the following substrates: Table. The values of KM and kcat for some Enzymes and Substrates Enzyme Chymotrypsin Ки (М) 4.4 x 10-1 8.8 x 10-2 6.6 x 104 Kcat (S-1) 5.1 x 10-2 1.7 x 10-1 1.9 x 102 Substrate N-acetylglycine ethyl ester N-acetylvaline ethyl ester N-acetyltyrosine ethyl ester Catalase H2O2 2.5 x 10-2 1.0 x 107 Urease Urea 2.5 x 10-2 4.0 x 105 OA. N-acetylglycine ethyl ester OB. N-acetylvaline ethyl ester OC. N-acetyltyrosine ethyl ester D. UreaA certain plant storage protein, after being isolated, was digested using both 8N H2SO4 and conc. Ba(OH)2. The resulting hydrolysates were then analyzed for amino acid composition using paper chromatography with EtOH-NH3-H2O (80:10:10) as the solvent system and ninhydrin as the visualizing agent. Name the amino acids found in the acid hydrolysate labelled 1-5.
- Chitinase is a protein that breaks down chitin, a primary component of the cell wall in fungi, scales in fish and exoskeletons of arthropods. The activity of chitinase extracted from a plant was shown to be optimum at pH 5. You were tasked to prepare 300 mL of 150 mM buffer solution for further analysis of the extracted chitinase. REAGENTS Ka 2.5M Acetic acid Solid NaOAc•3H2O [136.08g/mol] 1.76 x 10-5 2.5M NH3 Solid NH4Cl [53.49g/mol] 5.6 x 10-10 2.5M Lactic acid Solid sodium lactate [112.06g/mol] 4.0 x 10-5 5 M HCl 5M NaOH Pls show sol'ns 1. Given the following reagents, give the moles of each component (acid & base).2. What are the mass/volume of the components needed to prepare the buffer? 3. What will the pH of the buffer be if 1mL of 5 M NaOH was added?His388 Glu357 His388 Glu357 Ring opening Proton HO HO abstraction HO но- G6P He NH- NH His388 His388 His388 Glu357 Glu357 Glu357 HO но HO но- но OH cis-enediol F6P Ring closure intermediate OH Describe the mechanism shown above for phosphoglucose isomerase. Describe the chemistry of each step • How the enzyme appears or might facilitate the chemistry How the enzyme increases the reaction rate.In the hexokinase reaction (in glycolysis) Keq caclualtion, what is the OBVIOUS problem with getting a Keq of 678? what should keq be normally? how can you EXPLAIN a Keq of 678?
- The active site of lysozyme contains two amino acid residues essential for catalysis: Glu35 and Asp52. The pKa values of the carboxyl side chains of these residues are 5.9 and 4.5, respectively. What is the ionization state(protonated or deprotonated) of each residue at pH 5.2, the pH optimum of lysozyme? How can the ionization states of these residues explain the pH-activity profile of lysozyme shown below?The protein catalase catalyzes the reaction 2H,O,(aq) — 2H,O(l) + O,(g) and has a Michaelis-Menten constant of KM = 25 mM and a turnover number of 4.0 × 107 s¯¹. The total enzyme concentration is 0.010 µM and the initial substrate concentration is 4.83 µM. Catalase has a single active site. Calculate the value of Rmax (often written as Vmax) for this enzyme. Rmax Calculate the initial rate, R (often written as V), of this reaction. R = ×10 mM.s-1 mM-s-1The enzymatic activity of lysozyme is optimal at pH 5.2 and decreases above and below this pH value. Lysozyme contains two amino acid residues in the active site essential for catalysis: Glu35 and Asp52. The pK value for the carboxyl side chains of these two residues are 5.9 and 4.5 respectively. What is the ionization state of each residue at the pH optimum of lysozyme? How can the ionization states of these 2 amino acid residues explain the pH-activity profile of lysozyme?
- A synthetic substrate, the para-nitrophenylacetate (PNPA), is used to monitor enzyme activity of protein P. The product of the hydrolysis reaction absorbs at 410 nm with a molar extinction coefficient of 4 000 M-¹.cm-¹. 1- Write the reaction catalyzed by the protease P using the pNPA substrate. 2- The enzyme extract is too concentrated and a 1/300 dilution is needed for enzyme tests. Considering that you would need at least 600 µL of diluted enzyme extract for activity tests, indicate which volume of buffer and enzyme extract you must use for the dilution.at what substrate concentration is v= 5.0 mM s^-1 for the enzyme catalyzed hydrolysis of trehalose?The active site of an enzyme that uses a general acid-base catalytic mechanism contains a Glu and an Asp residue (both of which are essential for catalysis) with pKa values of 5.9 and 4.5, respectively. If the enzyme is found in the lysosome (pH = 5.2), which residue will act as the general acid and which will act as the general base during the initial steps of the reaction?