a.
To find: How large is
a.
Answer to Problem 6PSA
Explanation of Solution
Given:
A rectangle PRST having diagonals PS and TR intersecting at O, with each angle at the corner is of measure 90 degrees. Also
Concept Used:
Calculation:
A rectangle PRST having diagonals PS and TR intersecting at O, with each angle at the corner is of measure 90 degrees.
Also
Since, angles formed at the corner are complementary angle.
Conclusion:
b.
To find: How large is
b.
Answer to Problem 6PSA
Explanation of Solution
Given:
A rectangle PRST having diagonals PS and TR intersecting at O, with each angle at the corner is of measure 90 degrees. Also
Concept Used:
Angles formed at the corner are complementary angle.
Calculation:
A rectangle PRST having diagonals PS and TR intersecting at O, with each angle at the corner is of measure 90 degrees.
Also
Since, angles formed at the corner are complementary angle.
Conclusion:
c.
To find: How large is
c.
Answer to Problem 6PSA
Explanation of Solution
Given:
A rectangle PRST having diagonals PS and TR intersecting at O, with each angle at the corner is of measure 90 degrees. Also
Concept Used:
Sum of linear pair of angles is 180 degrees.
Calculation:
A rectangle PRST having diagonals PS and TR intersecting at O, with each angle at the corner is of measure 90 degrees.
Also
Sum of linear pair of angles is 180 degrees.
Conclusion:
d.
To find: The nature of
d.
Answer to Problem 6PSA
Explanation of Solution
Given:
A rectangle PRST having diagonals PS and TR intersecting at O, with each angle at the corner is of measure 90 degrees.
Concept Used:
Sum of angles of
Calculation:
A rectangle PRST having diagonals PS and TR intersecting at O, with each angle at the corner is of measure 90 degrees.
As we have
Since, vertically opposite angles are equal in measure.
Thus,
Conclusion:
Chapter 1 Solutions
Geometry For Enjoyment And Challenge
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