To find:
For the two reactions represented by their energy profiles shown in Figure P14.1,
a) Which reaction has a larger forward rate constant?
b) Which reaction has a smaller reverse rate constant?
c) Which reaction has a larger equilibrium constant Kc?
Answer to Problem 14.1VP
Solution:
a)
b)
c)
Explanation of Solution
The twographs represent the energy profile diagram for the two reactions.
Reactant molecules must acquire a certain energy known as activation energy to form products. This is the different in the energies of the transition state and the reactants. For the reverse reaction, it is the difference in the energies of the transition state and the products.Maximum energy in the profile represents the transition state.
The larger the activation energy, the slower the
The equilibrium constant depends on the reaction energy. If the products have less energy than the reaction, the forward reaction is favored over the reverse reaction.The value of Keq is then larger than when reactants have less energy than the products.
a) The activation energy for the forward reaction is less in case of the second reaction,
b) The activation energy for the reverse reaction is larger for the reaction
c) For reaction
Conclusion:
The energy profile of a reaction provides information about relative rates of forward and reverse rate constants as well as the relative value of the equilibrium constant.
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