College Physics
11th Edition
ISBN: 9781305952300
Author: Raymond A. Serway, Chris Vuille
Publisher: Cengage Learning
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Textbook Question
Chapter 16, Problem 25P
Calculate the speed of (a) an electron and (b) a proton with a kinetic energy of 1.00 electron volt (eV). (c) Calculate the average translational kinetic energy in cV of a 3.00 × 102 K ideal gas particle. (Recall from Topic 10 that
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Calculate the speed of (a) an electron and (b) a proton with
a kinetic energy of 1.00 electron volt (eV). (c) Calculate the
average translational kinetic energy in eV of a 3.00 x 102-K
ideal gas particle. (Recall from Topic 10 that mu = kT.)
This transmission electron microscope (TEM) image of coronavirus can be taken using a beam of
electrons accelerated from rest through a potential difference of 25 kV. What is the final speed of
the electrons?
Provide the answer: .
x 108 m/s
An electron is fired at a speed vo = 5.6 x 10° m/s and at
an angle 6, = -45° between two parallel conducting plates
that are D = 2.0 mm apart, as in Figure P16.72. If the volt-
age difference between the plates is AV = 100. V, determine
(a) how close, d, the electron will get to the bottom plate and
(b) where the electron will strike the top plate.
+ + + + + + + +
Path of
the electron
AV
Figure P16.72
Chapter 16 Solutions
College Physics
Ch. 16.1 - If an electron is released from rest in a uniform...Ch. 16.1 - If a negatively charged particle is placed at rest...Ch. 16.1 - Figure 16.3 is a graph of an electric potential as...Ch. 16.1 - If a negatively charged particle is placed at...Ch. 16.2 - Consider a collection of charges in a given region...Ch. 16.2 - A spherical balloon contains a positively charged...Ch. 16.3 - An electron initially at rest accelerates through...Ch. 16.6 - A capacitor is designed so that one plate is large...Ch. 16.7 - A parallel-plate capacitor is disconnected from a...Ch. 16.8 - A fully charged parallel-plate capacitor remains...
Ch. 16.8 - Consider a parallel-plate capacitor with a...Ch. 16 - A proton is released from rest in a uniform...Ch. 16 - An electron is released from rest in a uniform...Ch. 16 - Figure CQ16.3 shows equipotential contours in the...Ch. 16 - Rank the potential energies of the four systems of...Ch. 16 - A parallel-plate capacitor with capacitance C0...Ch. 16 - An air-filled parallel-plate capacitor with...Ch. 16 - Choose the words that make each statement correct,...Ch. 16 - Why is it important to avoid sharp edges or points...Ch. 16 - Explain why, under static conditions, all points...Ch. 16 - If you are given three different capacitors C1,...Ch. 16 - (a) Why is it dangerous to touch the terminals of...Ch. 16 - The plates of a capacitor are connected to a...Ch. 16 - Rank the electric potentials at the four points...Ch. 16 - If you were asked to design a capacitor in which...Ch. 16 - Is it always possible to reduce a combination of...Ch. 16 - Explain why a dielectric increases the maximum...Ch. 16 - A uniform electric field of magnitude 375 N/C...Ch. 16 - A proton is released from rest in a uniform...Ch. 16 - A potential difference of 90.0 mV exists between...Ch. 16 - Cathode ray tubes (CRTs) used in old-style...Ch. 16 - A constant electric field accelerates a proton...Ch. 16 - A point charge q = +40.0 C moves from A to B...Ch. 16 - Oppositely charged parallel plates are separated...Ch. 16 - (a) Find the potential difference VB required to...Ch. 16 - An ionized oxygen molecule (O+2) at point A has...Ch. 16 - On planet Tehar, the free-fall acceleration is the...Ch. 16 - An electron is at the origin, (a) Calculate the...Ch. 16 - The two charges in Figure P16.12 are separated by...Ch. 16 - (a) Find the electric potential, taking zero at...Ch. 16 - Three charges are situated at corners of a...Ch. 16 - Two point charges Q1 = +5.00 nC and Q2 = 3.00 nC...Ch. 16 - Three identical point charges each of charge q are...Ch. 16 - The three charges in Figure P16.17 are at the...Ch. 16 - A positive point charge q = +2.50 nC is located at...Ch. 16 - A proton is located at the origin, and a second...Ch. 16 - A proton and an alpha particle (charge = 2e, mass...Ch. 16 - A tiny sphere of mass 8.00 g and charge 2.80 nC is...Ch. 16 - The metal sphere of a small Van de Graaff...Ch. 16 - In Rutherfords famous scattering experiments that...Ch. 16 - Four point charges each haring charge Q are...Ch. 16 - Calculate the speed of (a) an electron and (b) a...Ch. 16 - An electric field does 1.50 103 eV of work on a...Ch. 16 - An alpha particle, which has charge 3.20 1019 C,...Ch. 16 - In the classical model of a hydrogen atom, an...Ch. 16 - Consider the Earth and a cloud layer 8.0 102 m...Ch. 16 - (a) When a 9.00-V battery is connected to the...Ch. 16 - An air-filled parallel-plate capacitor has plates...Ch. 16 - Air breaks down and conducts charge as a spark if...Ch. 16 - An air-filled capacitor consists of two parallel...Ch. 16 - A 1-megabit computer memory chip contains many...Ch. 16 - a parallel-plate capacitor with area 0.200 m2 and...Ch. 16 - A small object with a mass of 350. g carries a...Ch. 16 - Given a 2.50-F capacitor, a 6.25-F capacitor, and...Ch. 16 - Two capacitors, C1 = 5.00 F and C2 = 12.0 F, are...Ch. 16 - Find (a) the equivalent capacitance of the...Ch. 16 - Two capacitors give an equivalent capacitance of...Ch. 16 - For the system of capacitors shown in Figure...Ch. 16 - Consider the combination of capacitors in Figure...Ch. 16 - Find the charge on each of the capacitors in...Ch. 16 - Three capacitors are connected to a battery as...Ch. 16 - A 25.0-F capacitor and a 40.0-F capacitor are...Ch. 16 - (a) Find the equivalent capacitance between points...Ch. 16 - A 1.00-F capacitor is charged by being connected...Ch. 16 - Four capacitors are connected as shown in Figure...Ch. 16 - A 12.0 V battery is connected to a 4.50 F...Ch. 16 - Two capacitors, C1 = 18.0 F and C2 = 36.0 F, are...Ch. 16 - A parallel-plate capacitor has capacitance 3.00 F....Ch. 16 - Each plate of a 5.00 F capacitor stores 60.0 C of...Ch. 16 - The voltage across an air-filled parallel-plate...Ch. 16 - (a) How much charge can be placed on a capacitor...Ch. 16 - Determine (a) the capacitance and (b) the maximum...Ch. 16 - A parallel-plate capacitor has plates of area A =...Ch. 16 - A model of a red blood cell portrays the cell as a...Ch. 16 - When a potential difference of 150. V is applied...Ch. 16 - Three parallel-plate capacitors are constructed,...Ch. 16 - For the system of four capacitors shown in Figure...Ch. 16 - A parallel-plate capacitor with a plate separation...Ch. 16 - Two capacitors give an equivalent capacitance of...Ch. 16 - A parallel-plate capacitor is constructed using a...Ch. 16 - Two charges of 1.0 C and 2.0 C are 0.50 m apart at...Ch. 16 - Find the equivalent capacitance of the group of...Ch. 16 - A spherical capacitor consists of a spherical...Ch. 16 - The immediate cause of many deaths is ventricular...Ch. 16 - When a certain air-filled parallel-plate capacitor...Ch. 16 - Capacitors C1 = 6.0 F and C2 = 2.0 F are charged...Ch. 16 - Two positive charges each of charge q are fixed on...Ch. 16 - Metal sphere A of radius 12.0 cm carries 6.00 C of...Ch. 16 - An electron is fired at a speed v0 = 5.6 106 m/s...
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- How many electrons should be removed from an initially uncharged spherical conductor of radius 0.300 m to produce a potential of 7.50 kV at the surface?arrow_forward(a) Find the potential difference VB required to stop an electron (called a slopping potential) moving with an initial speed of 2.85 107 m/s. (b) Would a proton traveling at the same speed require a greater or lesser magnitude potential difference? Explain. (c) Find a symbolic expression for the ratio of the proton stopping potential and the electron stopping potential, Vp/Ve. The answer should be in terms of the proton mass mp and electron mass me.arrow_forwardSuppose an electron (q= -e= -1.6 x 10-19 C,m=9.1x 10-31 kg) is accelerated from rest through a potential difference of Vab = +5000 V. Solve for the final speed of the electron. Express numerical answer in two significant figures. The potential energy U is related to the electron charge (-e) and potential Vab is related by the equation: U = Assuming all potential energy U is converted to kinetic energy K, K +U = 0 K = -U Since K- and using the formula for potential energy above, we arrive at an equation for speed: v = ( 51/2 Plugging in values, the value of the electron's speed is: V= x 107 m/sarrow_forward
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