Concept explainers
a)
Interpretation:
Starting from benzene as the only source of
Concept introduction:
In aromatic electrophilic substitution reactions halogens are ortho and para directing groups while the keto group is a meta directing group. Hence to prepare p-chloroacetophenone, benzene has to be halogenated and the halobenzene obtained should be subjected to Friedal-Crafts acylation.
To state:
Starting from benzene as the only source of aromatic compounds and assuming that the ortho and para isomers can be separated, if necessary, how p-chloroacetophenone can be synthesized.
b)
Interpretation:
Starting from benzene as the only source of aromatic compounds and assuming that the ortho and para isomers can be separated, if necessary, how m-bromonitrobenzene can be synthesized is to be stated.
Concept introduction:
In aromatic electrophilic substitution reactions halogens are ortho and para directing groups while the nitro group is a meta directing group. Hence to prepare m-bromonitrobenzene, benzene has to be first nitrated and the nitrobenzene obtained should be halogenated.
To state:
Starting from benzene as the only source of aromatic compounds and assuming that the ortho and para isomers can be separated, if necessary, how m–bromonitrobenzene can be synthesized.
c)
Interpretation:
Starting from benzene as the only source of aromatic compounds and assuming that the ortho and para isomers can be separated, if necessary, how o-bromobenzenesulfonic acid can be synthesized is to be stated.
Concept introduction:
In aromatic electrophilic substitution reactions halogens are ortho and para directing groups while the sulfonic acid group is a meta directing group. Hence to prepare o-bromobenzenesulfonic acid, benzene has to be halogenated and the halobenzene obtained should be subjected to sulfonation.
To state:
Starting from benzene as the only source of aromatic compounds and assuming that the ortho and para isomers can be separated, if necessary, how o-bromobenzenesulfonic acid can be synthesized.
d)
Interpretation:
Starting from benzene as the only source of aromatic compounds and assuming that the ortho and para isomers can be separated, if necessary, how m-chlorobenzenesulfonic acid can be synthesized is to be stated.
Concept introduction:
In aromatic electrophilic substitution reactions halogens are ortho and para directing groups while the sulfonic acid group is a meta directing group. Hence to prepare m-chlorobenzenesulfonic acid, benzene has to be sulfonated and the benzenesulfonicacid obtained should be halogenated.
To state:
Starting from benzene as the only source of aromatic compounds and assuming that the ortho and para isomers can be separated, if necessary, how m-chlorobenzenesulfonic acid can be synthesized.
Trending nowThis is a popular solution!
Chapter 16 Solutions
Organic Chemistry
- (a) How will you convert:(i) Benzene to acetophenone (ii) Propanone to 2-Methylpropan-2-ol(b) Give reasons :(i) Electrophilic substitution in benzoic acid takes place at meta position.(ii) Carboxylic acids are higher boiling liquids than aldehydes, ketones and alcohols of comparable molecular masses.(iii) Propanal is more reactive than propanone in nucleophilic addition reactions.arrow_forwardHow could you convert butanoic acid into the following compounds? Write each step showing the reagents needed. (a) 1-Butanol (b) 1-Bromobutane (c) 1-Butenearrow_forward(a) Draw the structure of the following :(i) p-Methylbenzaldehyde (ii) 4-Methylpent-3-en-2-one(b) Give chemical tests to distinguish between the following pairs of compounds :(i) Benzoic acid and Ethyl benzoate, (ii) Benzaldehyde and Acetophenone.(iii) Phenol and Benzoic acid.arrow_forward
- 4) Aromatic compounds are among the most abundant and versatile in nature. From a synthetic point of view, these compounds, despite their stabilities, are quite useful and can undergo reactions under special conditions and by specific mechanisms, such as the Electrophilic Aromatic Substitution (SAE) and the Nucleophilic Aromatic Substitution (SNAr). Based on this, please answer the following items: (b) How would you prepare the following compounds starting from benzene? Explain the second in a different wayarrow_forwardNucleophilic aromatic substitution provides one of the common methods for making phenols. Show how you would synthesize the following phenols, using benzene or toluene as your aromatic starting material, and explain why mixtures of products would be obtained in some cases.(a) p-nitrophenol (b) 2,4,6-tribromophenol (c) p-chlorophenolarrow_forwardGive reasons for the following: (i) p-nitrophenol is more acidic than p-methylphenol. (ii) Bond length of C—O bond in phenol is shorter than that in methanol. (iii) (CH3)3C—Br on reaction with sodium methoxide (Na+ _OCH3) gives alkene as the main product and not an ether.arrow_forward
- Biphenyl has the following structure.(a) Is biphenyl a (fused) polynuclear aromatic hydrocarbon?(b) How many pi electrons are there in the two aromatic rings of biphenyl? How does this number compare with that for naphthalene?(c) The heat of hydrogenation for biphenyl is about 418 kJ>mol (100 kcal>mol). Calculate theresonance energy of biphenyl.(d) Compare the resonance energy of biphenyl with that of naphthalene and with that of two benzene rings. Explain thedifference in the resonance energies of naphthalene and biphenyl.arrow_forwardFollowing is the structural formula of the tranquilizer meparfynol (Oblivon). Propose a synthesis for this compound starting with acetylene and a ketone. (Notice the -yn- and -ol in the chemical name of this compound, indicating that it contains alkyne and hydroxyl functional groups.)arrow_forwardDescribe how would you distinguish the following pairs, (a) Benzene and cyclohexane (b) Phenol and toluene (c) Phenol and benzoic acidarrow_forward
- Draw structural formulas for these ketones. (a) Ethyl isopropyl ketone (b) 2-Chlorocyclohexanone (c) 2,4-Dimethyl-3-pentanone (d) Diisopropyl ketone (e) Acetone (f) 2,5-Dimethylcyclohexanonearrow_forwardHow could you convert butanoic acid into the following compounds? Write each step showing the reagents needed. (a) 1-Butanol (b) 1-Bromobutane (c) Pentanoic acid (d) 1-Butene (e) Octanearrow_forwardA postgraduate student wanted to synthesized two carbonyl compounds known as compounds M and N using oxidation of alcohol. However, these carbonyl compounds should have more than 6 carbon atoms. Draw two (2) possible structural formulae for compounds M and N. How would you distinguish between compounds M and N?arrow_forward
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning