Concept explainers
(a)
Frequency of oscillation.
(a)
Answer to Problem 114P
Frequency of oscillation is
Explanation of Solution
Write an expression for the speed.
Here,
Write an expression for frequency.
Here,
Write an expression for the circumference.
Here,
Rewrite equation (II) by using equation (I) and (III).
Conclusion:
Substitute
Thus, the frequency of oscillation is
(b)
The kinetic energy of the proton.
(b)
Answer to Problem 114P
The kinetic energy of the proton is
Explanation of Solution
Write an expression for the kinetic energy.
Here,
Rewrite equation (V) using equation (I).
Conclusion:
Substitute
Thus, the kinetic energy of the proton is
(c)
The equivalent voltage necessary to accelerate protons.
(c)
Answer to Problem 114P
The equivalent voltage necessary to accelerate protons is
Explanation of Solution
Write an expression for the equivalent voltage necessary to accelerate protons.
Here,
Rewrite equation (VII) using equation (VI).
Conclusion:
Substitute
Thus, the equivalent voltage necessary to accelerate protons is
(d)
The minimum number of revolutions each proton has to make in the cyclotron.
(d)
Answer to Problem 114P
The minimum number of revolutions each proton has to make in the cyclotron is
Explanation of Solution
Write an expression for the minimum number of revolutions each proton has to make in the cyclotron.
Here,
Conclusion:
Substitute
Thus, the minimum number of revolutions each proton has to make in the cyclotron is
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Chapter 19 Solutions
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