Concept explainers
Balance the following equations.
- a NaOH + H2CO3 → Na2CO3 + H2O
- b SiCl4 + H2O → SiO2 + HCl
- c Ca3(PO4)2 + C → Ca3P2 + CO
- d H2S + O2 → SO2 + H2O
- e N2O5 → NO2 → O2
(a)
Interpretation:
The given chemical equation has to be balanced.
Concept Introduction:
When a chemical reaction occurs, the total number of atoms in the reactant has to be same as that in the product formed. Chemical reaction can be entered in form of chemical equation with all necessary conditions. The chemical equation has to be balanced by adding coefficients only before the elements or compounds to make the atoms on both sides of arrow equal. This is known as balanced chemical equation.
Answer to Problem 2.126QP
The balanced equation is given as,
Explanation of Solution
The raw chemical equation given in the problem statement is,
Start balancing sodium as this occurs only once in the product side. This can be done by adding coefficient “2” to sodium hydroxide in the reactant side. The equation is obtained as,
Now balance hydrogen atom on both side. This can be done by adding coefficient “2” to water in the product side. This balanced the oxygen atom also. Hence, the balanced chemical equation obtained can be given as,
The balanced equation was given as,
(b)
Interpretation:
The given chemical equation has to be balanced.
Concept Introduction:
When a chemical reaction occurs, the total number of atoms in the reactant has to be same as that in the product formed. Chemical reaction can be entered in form of chemical equation with all necessary conditions. The chemical equation has to be balanced by adding coefficients only before the elements or compounds to make the atoms on both sides of arrow equal. This is known as balanced chemical equation.
Answer to Problem 2.126QP
The balanced equation is given as,
Explanation of Solution
The raw chemical equation given in the problem statement is,
Start by balancing chlorine as it occurs only once in the product side. This can be done by adding coefficient “4” to hydrogen chloride in the product side. By doing this we obtain, the chemical equation as shown below,
Now balance the hydrogen atom by adding the coefficient to “2” to water in the reactant side. This balances the whole equation. The balanced equation can be given as,
The balanced equation was given as,
(c)
Interpretation:
The given chemical equation has to be balanced.
Concept Introduction:
When a chemical reaction occurs, the total number of atoms in the reactant has to be same as that in the product formed. Chemical reaction can be entered in form of chemical equation with all necessary conditions. The chemical equation has to be balanced by adding coefficients only before the elements or compounds to make the atoms on both sides of arrow equal. This is known as balanced chemical equation.
Answer to Problem 2.126QP
The balanced equation is given as,
Explanation of Solution
The raw chemical equation given in the problem statement is,
Start by balancing oxygen as it occurs only once in the product side. This can be done by adding coefficient “8” to
Now start balancing carbon atom. This can be done by adding coefficient “8” to
The balanced equation was given as,
(d)
Interpretation:
The given chemical equation has to be balanced.
Concept Introduction:
When a chemical reaction occurs, the total number of atoms in the reactant has to be same as that in the product formed. Chemical reaction can be entered in form of chemical equation with all necessary conditions. The chemical equation has to be balanced by adding coefficients only before the elements or compounds to make the atoms on both sides of arrow equal. This is known as balanced chemical equation.
Answer to Problem 2.126QP
The balanced equation is given as,
Explanation of Solution
The raw chemical equation given in the problem statement is,
Start by balancing oxygen atom by adding coefficient “3” to oxygen molecule in the reactant side and coefficient “2” to the substance present in the product side. By doing this we obtain, the chemical equation as shown below,
Now balance the sulfur atom by adding the coefficient to “2” to hydrogen sulfide in the reactant side. This balances the whole equation. The balanced equation can be given as,
The balanced equation was given as,
(e)
Interpretation:
The given chemical equation has to be balanced.
Concept Introduction:
When a chemical reaction occurs, the total number of atoms in the reactant has to be same as that in the product formed. Chemical reaction can be entered in form of chemical equation with all necessary conditions. The chemical equation has to be balanced by adding coefficients only before the elements or compounds to make the atoms on both sides of arrow equal. This is known as balanced chemical equation.
Answer to Problem 2.126QP
The balanced equation is given as,
Explanation of Solution
The raw chemical equation given in the problem statement is,
Start by balancing nitrogen as it occurs only once in the product side. This can be done by adding coefficient “2” to nitrogen dioxide in the product side. By doing this we obtain, the chemical equation as shown below,
Now balance the oxygen atom. Totally there are five oxygen atoms in the reactant side, while in the product side there are six oxygen atoms. Multiply by ½ in front of Oxygen molecule in the product side gives the equation as,
Multiply the whole equation by 2. This gives the balanced equation as,
The balanced equation was given as,
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Chapter 2 Solutions
General Chemistry - Standalone book (MindTap Course List)
- Classify each chemical reaction: reaction Na₂S (aq) + FeCl₂ (aq) → 2NaCl(aq) + FeS (s) - 2CH, (CH₂) CH₂(g) + 130₂(g) → 8CO₂(g) + 10H₂O(g) 2 CH₂CH₂CH₂(g) + 50₂(g) → 3CO₂(g) + 4H₂O(g) KBr(aq) + AgNO3(aq) → KNO3(aq) + AgBr(s) type of reaction (check all that apply) combination Osingle replacement double replacement decomposition combination single replacement double replacement decomposition combination single replacement double replacement decomposition combination single replacement double replacement decomposition X precipitation combustion acid-base precipitation combustion acid-base precipitation combustion acid-base precipitation combustion acid-base Śarrow_forwardWrite out the balanced equation for the following reaction. Don’t forget that there may be coefficients on each side of the equation. a) NaOH + H2SO4 → H2O + Na2SO4 b) NH3 + CuO → Cu + N2 + H2Oarrow_forwardWhich of the reactants will produce H2S(g) O Na2S NazSO4 O Na,SO2 O NazSO3arrow_forward
- Using your Data Sheet for guidance, determine the products of each reaction shown below. Make sure to have correct formulas (watch ion charges) and balance each equation. portfelle Ca + 02 → HCl + Al > Pb(NO3)2 + HI → NaOH + CO2 > HC2H3O2 + Ca(OH)2 →arrow_forwardRefer to the given equation KI + K₂Cr₂O₇ + HCl → CrCl₃ + KCl + I₂ + H₂Oarrow_forwardAriana plans to react a sample of magnesium carbonate (MgCO3) with hydrochloric acid (HCl) to generate magnesium chloride (MgCl2), carbon dioxide gas (CO2), and liquid water (H2O). Write the balanced chemical equation for this reaction.arrow_forward
- Ethanol can be used as a fuel source in an alcohol lamp. The formula for ethanol is C2H5OH. Write the balanced equation for the combustion of ethanol.arrow_forwardPhosphoric acid, H3PO4, has K1 - 7.5 x 10 3 Ka2 = 6.3x 10 8 K3= 4.7x 10 13 HPO42 + H20 = HPO4* + OH K = ? O 2.1x 103 O 1.3x10 13 O 1.6 x 107 O 6.3x 108 O 4.7x 10 13arrow_forwardProvide balanced equations for the following: ___C7H14 + ___O2 → ___CO2 + ___H2O ___KO2 + ___CO2 → ___K2CO3 + ___O2arrow_forward
- Cu + 4HNO3 ——->Cu(NO3)2 + 2NO2 + 2H2Oarrow_forwardBalance the following equation. (Fill in the blanks with the correct numbers. If necessary, do place a "1", rather than leaving it blank.) NH3+ H₂O 0₂ → N₂+arrow_forwardo + CHO NaOH CH3OH Bno H₂, Pd/c CH3OH PDC DMF 4 (CH3) Cu H30 COOCH3 Solz 242612 Ets Ny LAPH₂, H₂Oarrow_forward
- Chemistry & Chemical ReactivityChemistryISBN:9781337399074Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage LearningChemistry & Chemical ReactivityChemistryISBN:9781133949640Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage Learning