Concept explainers
a.
The velocity of the rocket, when it runs out of the fuel.
Given:
Acceleration of rocket starting from rest is 3.2 m/sec2
Rocket runs out of fuel at an altitude of 1200 m.
Formula used:
Calculation:
For the given situation, u = 0, h = 1200 m, a = 3.2m/sec2
b.
Time taken by the rocket to reach the given height.
Given:
Acceleration of rocket starting from rest is 3.2 m/sec2
Rocket runs out of fuel at an altitude of 1200 m.
Formula used:
Here h is height, u is initial velocity, a is acceleration and t is time Calculation:
From
c.
The maximum altitude does the rocket reach.
Maximum altitude = 1591.84m
Given:
Acceleration of rocket starting from rest is 3.2 m/sec2
Rocket runs out of fuel at an altitude of 1200 m.
Formula used:
The equation of motion is,
Calculation:
After 1200 m height it will go upwards until its velocity becomes zero
Let it goes up to h1m height after 1200m.
The maximum altitude that the rocket reach
d.
Time taken by the rocket to reach the maximum height.
Given:
Acceleration of rocket starting from rest is 3.2 m/sec2
Rocket runs out of fuel at an altitude of 1200 m.
Formula used:
The equation of motion is,
Calculation:
Let t1is the time to reach from 1200m to the height when velocity becomes zero.So,
Total time is,
e.
The velocity at the instant of striking the Earth.
Given:
Acceleration of rocket starting from rest is 3.2 m/sec2
Rocket runs out of fuel at an altitude of 1200 m.
Formula used:
From previous parts,
Substituting the values,
f.
Total time for which the rocket is in the air.
Total time = 54.35sec
Given:
Acceleration of rocket starting from rest is 3.2 m/sec2
Rocket runs out of fuel at an altitude of 1200 m.
Formula used:
The equation of motion is,
Calculation:
Let the time taken to reach the ground from maximum altitude is
Total time is,
Chapter 2 Solutions
Physics: Principles with Applications
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