The systems in Exercises 25 and 26 exhibit a “lower triangular” pattern that makes them easy to solve by forward substitution. (We will encounter forward substitution again in Chapter 3.) Solve these systems. x = 2 2 x + y = − 3 − 3 x − 4 y + z = − 10
The systems in Exercises 25 and 26 exhibit a “lower triangular” pattern that makes them easy to solve by forward substitution. (We will encounter forward substitution again in Chapter 3.) Solve these systems. x = 2 2 x + y = − 3 − 3 x − 4 y + z = − 10
Solution Summary: The author explains how to solve the given system by back substitution.
The systems in Exercises 25 and 26 exhibit a “lower triangular” pattern that makes them easy to solve by forward substitution. (We will encounter forward substitution again in Chapter 3.) Solve these systems.
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