(a)
Interpretation:
The total number of valence electrons in of
Concept Introduction:
The number of electrons present in outermost shell of an atom which are available for bonding are known as valence electrons. For a molecule, total number of valence electrons will be sum of valence electrons of each atom present in the molecule.
Answer to Problem 3.61P
8.
Explanation of Solution
Total number valence electrons in
The number of valence electrons in n are 5 and that in hydrogen is 1 thus.
Hence, total number valence electrons in
(b)
Interpretation:
Number of valence electrons in
Concept Introduction:
The number of electrons present in outermost shell of an atom which are available for bonding are known as valence electrons. For a molecule, total number of valence electrons will be sum of valence electrons of each atom present in the molecule.
Answer to Problem 3.61P
18.
Explanation of Solution
Total number valence electrons in
The number of valence electrons in C are 4 and that in hydrogen is 1 thus.
Hence, total number valence electrons in
(c)
Interpretation:
Number of valence electrons in
Concept Introduction:
The number of electrons present in outermost shell of an atom which are available for bonding are known as valence electrons. For a molecule, total number of valence electrons will be sum of valence electrons of each atom present in the molecule.
Answer to Problem 3.61P
24.
Explanation of Solution
Total number valence electrons in
The number of valence electrons in C are 4, in H is 1and in O are 6 thus.
Hence, total number valence electrons in
(d)
Interpretation:
Number of valence electrons in
Concept Introduction:
The number of electrons present in outermost shell of an atom which are available for bonding are known as valence electrons. For a molecule, total number of valence electrons will be sum of valence electrons of each atom present in the molecule.
Answer to Problem 3.61P
20.
Explanation of Solution
Total number valence electrons in
The number of valence electrons in C are 4, in H is 1and in O are 6 thus.
Hence, total number valence electrons in
(e)
Interpretation:
Number of valence electrons in
Concept Introduction:
The number of electrons present in outermost shell of an atom which are available for bonding are known as valence electrons. For a molecule, total number of valence electrons will be sum of valence electrons of each atom present in the molecule.
Answer to Problem 3.61P
32.
Explanation of Solution
Total number valence electrons in
The number of valence electrons in C are 4 and in Cl is 7 thus.
Hence, total number valence electrons in
(f)
Interpretation:
Number of valence electrons in
Concept Introduction:
The number of electrons present in outermost shell of an atom which are available for bonding are known as valence electrons. For a molecule, total number of valence electrons will be sum of valence electrons of each atom present in the molecule.
Answer to Problem 3.61P
18.
Explanation of Solution
Total number valence electrons in
The number of valence electrons in H is 1, in nitrogen is 5 and in O are 6 thus.
Hence, total number valence electrons in
(g)
Interpretation:
Number of valence electrons in
Concept Introduction:
The number of electrons present in outermost shell of an atom which are available for bonding are known as valence electrons. For a molecule, total number of valence electrons will be sum of valence electrons of each atom present in the molecule.
Answer to Problem 3.61P
32.
Explanation of Solution
Total number valence electrons in
The number of valence electrons in C is 4, in Cl is 7 and in F is also 7 thus.
Hence, total number valence electrons in
(h)
Interpretation:
Number of valence electrons in
Concept Introduction:
The number of electrons present in outermost shell of an atom which are available for bonding are known as valence electrons. For a molecule, total number of valence electrons will be sum of valence electrons of each atom present in the molecule.
Answer to Problem 3.61P
12.
Explanation of Solution
Total number valence electrons in
The number of valence electrons in O are 6, thus.
Hence, total number valence electrons in
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Chapter 3 Solutions
Introduction to General, Organic and Biochemistry
- 3-41 Describe the structure of sodium chloride in the solid state.arrow_forward3-109 Until several years ago, the two chlorofluorocarbons (CFCs) most widely used as heat transfer media in refrigeration systems were Freon-li (trichloro fluoromethane, CC13F) and Freon-12 (dichiorodi fluoromethane, CCl2F2). Draw a three-dimensional representation of each molecule and indicate the Direction of it.s polarity.arrow_forwardA 1.88/The curved arrow notation introduced in Section 1.6B is a powerful method used by organic chemists to show the movement of electrons not only in resonance structures, but also in chemical reactions. Because each curved arrow shows the movement of two electrons, following the curved arrows illustrates what bonds are broken and formed in a reaction. Consider the following three-step process. (a) Add curved arrows in Step [1] to show the movement of electrons. (b) Use the curved arrows drawn in Step [2] to identify the structure of X. X is converted in Step [3] to phenol and HCI. H [1] + H-i: + :ÖH HO [2] + H-i: [3] phenolarrow_forward
- 1.88/ The curved arrow notation introduced in Section 1.6B is a powerful method used by organic chemists to show the movement of electrons not only in resonance structures, but also in chemical reactions. Because each curved arrow shows the movement of two electrons, following the curved arrows illustrates what bonds are broken and formed in a reaction. Consider the following three-step process. (a) Add curved arrows in Step [1] to show the movement of electrons. (b) Use the curved arrows drawn in Step [2] to identify the structure of X. X is converted in Step [3] to phenol and HCI. H HÖ [1] + H-CI: + + :Cl: :OH HO [2] C: + H-i: [3] phenolarrow_forwardSelect the correct starting material for the reaction shown below: 1) MgBr 2) H3O+ work up OHarrow_forward(B) "moty" =yey HOarrow_forward
- Name each of the following compounds:(a) BrF3(b) NaBrO3(c) PBr5(d) NaClO4(e) KClOarrow_forward(a) Draw a line drawing for the Lewis diagram given below. Hint start converting the Lewis to a VSEPR diagram. H H H +4 H H (b) What is the line drawing for a chemical species with the condensed molecular formula -H CH3CHC(CH3)CH(CH3)2. Hint start by converting the condensed formula to a Lewis diagram....then you solve this just like Question 1(a)!. (c) Of course, concepts can be examined in reverse! Draw a VSEPR diagram THAT IS ALSO A BEST LEWIS DIAGRAM, for the chemical that has the following line drawing: H₂N IOarrow_forward3.39 (a) Which of the following molecules can hydrogen bond to another molecule like itself? (b) Which of the following molecules eán hydrogen bond to water? ОН CI СНО NH A Вarrow_forward
- (CH3)2CHCH,CHO 1. NH3 2. NaCN, HCI 3. HCI, H₂O, heatarrow_forwardComplete the Lewis structure for each of the following molecules using the information proVided in lable 1-4. You may assume that all formal charges are zero. All H atoms are shown; add only bonding pairs and lone pairs of electrons. (a) (b) нн H (c) N- H-C-Ć-C-N-0 н н H. N.arrow_forward(a) What is a hydrocarbon? (b) Pentane is the alkane witha chain of five carbon atoms. Write a structural formula forthis compound and determine its molecular and empiricalformulas.arrow_forward
- Introduction to General, Organic and BiochemistryChemistryISBN:9781285869759Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar TorresPublisher:Cengage Learning