Concept explainers
The number of protons, neutrons, and electrons in the atom
Answer to Problem 18SP
Solution:
Explanation of Solution
Given data:
The atom is represented as
Formula used:
An atom represented as
Here,
The calculations for the atom
Here,
Explanation:
Compare the atom
The number of protonsis equal to the atomic number. Hence, the number of protons in
Observe the notation for the atom
Recall the formula to calculate the number of neutrons in the atom
Substitute
The number of neutrons is
Conclusion:
Thenumber of protons, neutrons, and electrons in the atom
Want to see more full solutions like this?
Chapter 45 Solutions
Schaum's Outline of College Physics, Twelfth Edition (Schaum's Outlines)
- What prevents gravity from pulling you through the ground to the center of the Earth? Choose the best answer. (a) The density of matter is too great. (b) The positive nuclei of your body’s atoms repel the positive nuclei of the atoms of the ground. (c) The density of the ground is greater than the density of your body. (d) Atoms are bound together by chemical bonds. (e) Electrons on the ground’s surface and the surface of your feet repel one another.arrow_forwardUse the below values for this problem. Please note that the mass for H is for the entire atom (proton & electron). Neutron: m = 1.67493x10-27 kg = 1.008665 u = 939.57 MeV/c² . ¹H: mH = 1.67353x10-27 kg = 1.007825 u = 938.78 MeV/c² 1 1 u = 1.6605x10-27 kg = 931.5 MeV/c² . Consider the following decay: 239 Pu 235 U+ a. 239 Pu has a mass of 239.0521634 u, 235 U has a mass of 235.0439299 u, and a has a mass of 4.002603 u. 94 92 94 92 Determine the disintegration energy (Q-value) in MeV. Q = Determine the binding energy (in MeV) for 239 Pu. 94 EB =arrow_forwardThe electron in the hydrogen atom (in its ground state) orbits the nucleus at a distance of 0.5292 Å. (a) Calculate the gravitational force and (b) the electrostatic force of attraction between the two. (c) Comment on the magnitude and the importance of these two forces. [G, gravitational constant = 6.672 x 10-11 N m2 kg-2; 4+Єo = 1.113 x 10-10 C2 m-1 J-1]arrow_forward
- C3. A Rubidium nucleus undergoes the electron capture as given by 33Rb + e¯ → AXN+Y. Assume the electron came from the K-shell of Rubidium and K-edge is 15.2 keV. Given that the mass of neutral atom 33Rb is 82.9151106u, and the mass of neutral atom 4XN is 82.9141360u. (a) Determine the values of A, Z and N. (b) Given the name of particle Y. (c) Calculate the disintegration energy of the decay (in MeV). (d) Explain why K-edge should be considered in electron capture. Express the values to 3 significant figures, if necessary.arrow_forwardTwo electrons in the nucleus of a 238U atom are separated by a distance of 8 fm. What is the potential energy of the arrangement? A) 179.77 keVB) 2.25×10 43 eVC) 4.61×10 −33 keVD) 3.596 eVarrow_forwardOne of the following is considered as a mirror nucleus to O (A=18, z=8): Ne (A=19, z=10) b. Mg (A=21, z=12) c. Ne (A=23, z=10) С. d. O (A=19, z=8) Ne (A=18, z=10) е.arrow_forward
- 1. A thin (1 mg/cm2) target of 48 Ca is bombarded with a 10 nA beam of a paarticles. A detector, with a solid angle of 0.0020 steradians., records 15 protons per second. If the angular distribution is isotropic, determine the total cross section (in mb) for the 48 Ca(a, p) reaction. Take the atomic mass of 48 Ca to be 48 u. hoourarrow_forwardUse the below values for this problem. Please note that the mass for H is for the entire atom (proton & electron). Neutron: m,= 1.67493x1027 kg= 1.008665 u = 939.57 MeVIC H: my = 1.67353x10 27 kg = 1.007825 u = 938.78 MeVic 1u= 1.6605x10-27 kg = 931.5 MeVic? Consider the following decay: 211 At 207 Bi + a. 211 At has a mass of 210.9874963 u, 207 Bi has a mass of 206.981593 u, and a has a mass of 4.002603 u. 85 83 85 83 Determine the disintegration energy (Q-value) in MeV. Determine the binding energy (in MeV) for 211 At. 85 EB =arrow_forwardAssume the electron in a hydrogen atom is 53.0 pm from the nucleus of the atom, which consists of a single proton. (a) calculate the electrical force between the electron and the nucleus. (b) Calculate the gravitational force between the electron and the nucleus. (c) What is the ratio of the gravitational force to the electrical force?arrow_forward
- Find the radius of a nucleus of 238 92 U and 16 8 O. a. 238 92 U fm b. 16 8 O fm See attached image for reference.arrow_forwardHow many kJ of energy are released to form one mole of 133Cs from protons and neutrons if the atom has a mass of 132.905429 amu? Please remember to include the mass of electrons in the calculation. Given the mass of a proton is 1.007825 amuarrow_forwardWhat is the density in kg/m3 of the material in the nucleus of the hydrogen atom? The nucleus can be considered to be a sphere of radius 1.2 x 10-15 m, and its mass is 1.67 x 10-27 kg.arrow_forward
- College PhysicsPhysicsISBN:9781938168000Author:Paul Peter Urone, Roger HinrichsPublisher:OpenStax CollegeModern PhysicsPhysicsISBN:9781111794378Author:Raymond A. Serway, Clement J. Moses, Curt A. MoyerPublisher:Cengage Learning
- College PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage Learning